我需要从一个相当大的SQL Server表(即300,000+行)中删除重复的行。

当然,由于RowID标识字段的存在,这些行不会完全重复。

MyTable

RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null

我该怎么做呢?


当前回答

下面的查询用于删除重复的行。本例中的表以ID作为标识列,具有重复数据的列是Column1、Column2和Column3。

DELETE FROM TableName
WHERE  ID NOT IN (SELECT MAX(ID)
                  FROM   TableName
                  GROUP  BY Column1,
                            Column2,
                            Column3
                  /*Even if ID is not null-able SQL Server treats MAX(ID) as potentially
                    nullable. Because of semantics of NOT IN (NULL) including the clause
                    below can simplify the plan*/
                  HAVING MAX(ID) IS NOT NULL) 

下面的脚本显示GROUP BY、HAVING、ORDER BY在一个查询中的用法,并返回带有重复列及其计数的结果。

SELECT YourColumnName,
       COUNT(*) TotalCount
FROM   YourTableName
GROUP  BY YourColumnName
HAVING COUNT(*) > 1
ORDER  BY COUNT(*) DESC 

其他回答

快速和脏删除精确重复的行(小表):

select  distinct * into t2 from t1;
delete from t1;
insert into t1 select *  from t2;
drop table t2;

另一种表达方式:——

DELETE A
FROM   TABLE A,
       TABLE B
WHERE  A.COL1 = B.COL1
       AND A.COL2 = B.COL2
       AND A.UNIQUEFIELD > B.UNIQUEFIELD 

我更喜欢CTE从sql server表中删除重复的行

强烈推荐阅读本文::http://codaffection.com/sql-server-article/delete-duplicate-rows-in-sql-server/

保持原创性

WITH CTE AS
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY col1,col2,col3 ORDER BY col1,col2,col3) AS RN
FROM MyTable
)

DELETE FROM CTE WHERE RN<>1

不保留原创

WITH CTE AS
(SELECT *,R=RANK() OVER (ORDER BY col1,col2,col3)
FROM MyTable)
 
DELETE CTE
WHERE R IN (SELECT R FROM CTE GROUP BY R HAVING COUNT(*)>1)

这是删除重复记录最简单的方法

 DELETE FROM tblemp WHERE id IN 
 (
  SELECT MIN(id) FROM tblemp
   GROUP BY  title HAVING COUNT(id)>1
 )

如果重复行的所有列都是相同的,那么下面的查询可以用来删除重复的记录。

SELECT DISTINCT * INTO #TemNewTable FROM #OriginalTable
TRUNCATE TABLE #OriginalTable
INSERT INTO #OriginalTable SELECT * FROM #TemNewTable
DROP TABLE #TemNewTable