有什么方法,我可以检查如果一个元素是可见的纯JS(没有jQuery) ?

因此,给定一个DOM元素,我如何检查它是否可见?我试着:

window.getComputedStyle(my_element)['display']);

但这似乎并不奏效。我想知道我应该检查哪些属性。我想到了:

display !== 'none'
visibility !== 'hidden'

还有我可能漏掉的吗?


当前回答

这就是我所做的:

HTML和CSS:默认情况下使元素隐藏

<html>
<body>

<button onclick="myFunction()">Click Me</button>

<p id="demo" style ="visibility: hidden;">Hello World</p> 

</body>
</html> 

JavaScript:增加了一个代码来检查可见性是否被隐藏:

<script>
function myFunction() {
   if ( document.getElementById("demo").style.visibility === "hidden"){
   document.getElementById("demo").style.visibility = "visible";
   }
   else document.getElementById("demo").style.visibility = "hidden";
}
</script>

其他回答

var visible = document.getElementById("yourelementID's");
 if (visible){
          // make events
 } else
 {
   //other events
 }

所以我找到了最可行的方法:

function visible(elm) {
  if(!elm.offsetHeight && !elm.offsetWidth) { return false; }
  if(getComputedStyle(elm).visibility === 'hidden') { return false; }
  return true;
}

这是基于以下事实:

显示:所有元素(即使是嵌套的元素)都没有宽度和高度。 可见性即使对于嵌套的元素也是隐藏的。

因此不需要测试offsetParent或在DOM树中循环来测试哪个父对象具有可见性:hidden。这应该可以在ie9中工作。

你可能会说,如果透明度:0和折叠的元素(有宽度但没有高度-反之亦然)也不是真正可见的。但话说回来,它们并不是隐藏的。

如果你对用户可见感兴趣:

function isVisible(elem) {
    if (!(elem instanceof Element)) throw Error('DomUtil: elem is not an element.');
    const style = getComputedStyle(elem);
    if (style.display === 'none') return false;
    if (style.visibility !== 'visible') return false;
    if (style.opacity < 0.1) return false;
    if (elem.offsetWidth + elem.offsetHeight + elem.getBoundingClientRect().height +
        elem.getBoundingClientRect().width === 0) {
        return false;
    }
    const elemCenter   = {
        x: elem.getBoundingClientRect().left + elem.offsetWidth / 2,
        y: elem.getBoundingClientRect().top + elem.offsetHeight / 2
    };
    if (elemCenter.x < 0) return false;
    if (elemCenter.x > (document.documentElement.clientWidth || window.innerWidth)) return false;
    if (elemCenter.y < 0) return false;
    if (elemCenter.y > (document.documentElement.clientHeight || window.innerHeight)) return false;
    let pointContainer = document.elementFromPoint(elemCenter.x, elemCenter.y);
    do {
        if (pointContainer === elem) return true;
    } while (pointContainer = pointContainer.parentNode);
    return false;
}

测试对象(使用摩卡术语):

describe.only('visibility', function () {
    let div, visible, notVisible, inViewport, leftOfViewport, rightOfViewport, aboveViewport,
        belowViewport, notDisplayed, zeroOpacity, zIndex1, zIndex2;
    before(() => {
        div = document.createElement('div');
        document.querySelector('body').appendChild(div);
        div.appendChild(visible = document.createElement('div'));
        visible.style       = 'border: 1px solid black; margin: 5px; display: inline-block;';
        visible.textContent = 'visible';
        div.appendChild(inViewport = visible.cloneNode(false));
        inViewport.textContent = 'inViewport';
        div.appendChild(notDisplayed = visible.cloneNode(false));
        notDisplayed.style.display = 'none';
        notDisplayed.textContent   = 'notDisplayed';
        div.appendChild(notVisible = visible.cloneNode(false));
        notVisible.style.visibility = 'hidden';
        notVisible.textContent      = 'notVisible';
        div.appendChild(leftOfViewport = visible.cloneNode(false));
        leftOfViewport.style.position = 'absolute';
        leftOfViewport.style.right = '100000px';
        leftOfViewport.textContent = 'leftOfViewport';
        div.appendChild(rightOfViewport = leftOfViewport.cloneNode(false));
        rightOfViewport.style.right       = '0';
        rightOfViewport.style.left       = '100000px';
        rightOfViewport.textContent = 'rightOfViewport';
        div.appendChild(aboveViewport = leftOfViewport.cloneNode(false));
        aboveViewport.style.right       = '0';
        aboveViewport.style.bottom       = '100000px';
        aboveViewport.textContent = 'aboveViewport';
        div.appendChild(belowViewport = leftOfViewport.cloneNode(false));
        belowViewport.style.right       = '0';
        belowViewport.style.top       = '100000px';
        belowViewport.textContent = 'belowViewport';
        div.appendChild(zeroOpacity = visible.cloneNode(false));
        zeroOpacity.textContent   = 'zeroOpacity';
        zeroOpacity.style.opacity = '0';
        div.appendChild(zIndex1 = visible.cloneNode(false));
        zIndex1.textContent = 'zIndex1';
        zIndex1.style.position = 'absolute';
        zIndex1.style.left = zIndex1.style.top = zIndex1.style.width = zIndex1.style.height = '100px';
        zIndex1.style.zIndex = '1';
        div.appendChild(zIndex2 = zIndex1.cloneNode(false));
        zIndex2.textContent = 'zIndex2';
        zIndex2.style.left = zIndex2.style.top = '90px';
        zIndex2.style.width = zIndex2.style.height = '120px';
        zIndex2.style.backgroundColor = 'red';
        zIndex2.style.zIndex = '2';
    });
    after(() => {
        div.parentNode.removeChild(div);
    });
    it('isVisible = true', () => {
        expect(isVisible(div)).to.be.true;
        expect(isVisible(visible)).to.be.true;
        expect(isVisible(inViewport)).to.be.true;
        expect(isVisible(zIndex2)).to.be.true;
    });
    it('isVisible = false', () => {
        expect(isVisible(notDisplayed)).to.be.false;
        expect(isVisible(notVisible)).to.be.false;
        expect(isVisible(document.createElement('div'))).to.be.false;
        expect(isVisible(zIndex1)).to.be.false;
        expect(isVisible(zeroOpacity)).to.be.false;
        expect(isVisible(leftOfViewport)).to.be.false;
        expect(isVisible(rightOfViewport)).to.be.false;
        expect(isVisible(aboveViewport)).to.be.false;
        expect(isVisible(belowViewport)).to.be.false;
    });
});

有许多情况下,这将不一定工作,但在我的情况下,我正在使用这个,它为我所需要的工作。所以,如果你正在寻找一个基本的解决方案(不包括所有的可能性),如果这个简单的解决方案适合你的特殊需求,它“可能”对你有帮助。

var element= document.getElementById('elementId');

if (element.style.display == "block"){

<!-- element is visible -->

} else {

<!-- element is hidden-->

}

Chrome 105(以及Edge和Opera)和Firefox 106引入了element . checkvisibility(),如果元素是可见的,则返回true,否则返回false。

该函数检查了使元素不可见的各种因素,包括display:none、可见性、内容可见性和不透明度:

let element = document.getElementById("myIcon");
let isVisible = element.checkVisibility({
    checkOpacity: true,      // Check CSS opacity property too
    checkVisibilityCSS: true // Check CSS visibility property too
});

旁注:checkVisibility()以前被称为isVisible()。看这个GitHub问题。 参见这里的checkVisibility()规范草案。