我有两个JavaScript数组:

var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];

我希望输出为:

var array3 = ["Vijendra","Singh","Shakya"];

输出数组应删除重复的单词。

如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?


当前回答

模块化,通用

这可以通过组成两个基本功能来实现。

const getUniqueMerge = (...arrs) => getUniqueArr(mergeArrs(...arrs))
const getUniqueArr = (array) => Array.from(new Set(array))  
const mergeArrs = (...arrs) => [].concat(...arrs)

它可以处理无限的数组或值

console.log(getUniqueMerge(["Vijendra","Singh"],["Singh", "Shakya"])
// ["Vijendra", "Singh", "Shakya"]

console.log(getUniqueMerge(["Sheldon", "Cooper"], ["and", "Cooper", "Amy", "and"], "Farrah", "Amy", "Fowler"))
// ["Sheldon", "Cooper", "and", "Amy", "Farrah", "Fowler"]

其他回答

取两个数组a和b

var a = ['a','b','c'];

var b = ['d','e','f'];
var c = a.concat(b); 


//c is now an an array with: ['a','b','c','d','e','f']

我简化了这个答案的最佳部分,并将其转化为一个很好的函数:

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

使用Lodash

我发现@GijsjanB的答案很有用,但我的数组包含具有许多属性的对象,因此我不得不使用其中一个属性来消除它们的重复。

这是我使用lodash的解决方案

userList1 = [{ id: 1 }, { id: 2 }, { id: 3 }]
userList2 = [{ id: 3 }, { id: 4 }, { id: 5 }]
// id 3 is repeated in both arrays

users = _.unionWith(userList1, userList2, function(a, b){ return a.id == b.id });

// users = [{ id: 1 }, { id: 2 }, { id: 3 }, { id: 4 }, { id: 5 }]

作为第三个参数传递的函数有两个参数(两个元素),如果它们相等,则必须返回true。

Array.prototype.union = function (other_array) {
/* you can include a test to check whether other_array really is an array */
  other_array.forEach(function(v) { if(this.indexOf(v) === -1) {this.push(v);}}, this);    
}

我的一便士半:

Array.prototype.concat_n_dedupe = function(other_array) {
  return this
    .concat(other_array) // add second
    .reduce(function(uniques, item) { // dedupe all
      if (uniques.indexOf(item) == -1) {
        uniques.push(item);
      }
      return uniques;
    }, []);
};

var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];

var result = array1.concat_n_dedupe(array2);

console.log(result);