我在Bash中有一个字符串：
string="My string"
如何测试它是否包含另一个字符串？
if [ $string ?? 'foo' ]; then
echo "It's there!"
fi
哪里是我不认识的接线员。我使用echo和grep吗？
if echo "$string" | grep 'foo'; then
echo "It's there!"
fi
这看起来有点笨拙。
当前回答
grep-q对于这个目的很有用。
同样使用awk：
string="unix-bash 2389"
character="@"
printf '%s' "$string" | awk -vc="$character" '{ if (gsub(c, "")) { print "Found" } else { print "Not Found" } }'
输出：
未找到
string="unix-bash 2389"
character="-"
printf '%s' "$string" | awk -vc="$character" '{ if (gsub(c, "")) { print "Found" } else { print "Not Found" } }'
输出：
建立
原始来源：http://unstableme.blogspot.com/2008/06/bash-search-letter-in-string-awk.html
其他回答
case $string in (*foo*)
# Do stuff
esac
这与https://stackoverflow.com/a/229585/11267590.但风格简单，也符合POSIX。
我不确定是否使用if语句，但您可以使用case语句获得类似的效果：
case "$string" in
*foo*)
# Do stuff
;;
esac
我喜欢sed。
substr="foo"
nonsub="$(echo "$string" | sed "s/$substr//")"
hassub=0 ; [ "$string" != "$nonsub" ] && hassub=1
编辑，逻辑：
使用sed从字符串中删除子字符串的实例如果新字符串与旧字符串不同，则存在子字符串
此堆栈溢出答案是唯一一个陷阱空格和破折号字符的答案：
# For null cmd arguments checking
to_check=' -t'
space_n_dash_chars=' -'
[[ $to_check == *"$space_n_dash_chars"* ]] && echo found
这里回答的问题的扩展如何判断POSIX sh中的字符串是否包含另一个字符串？：
此解决方案适用于特殊字符：
# contains(string, substring)
#
# Returns 0 if the specified string contains the specified substring,
# otherwise returns 1.
contains() {
string="$1"
substring="$2"
if echo "$string" | $(type -p ggrep grep | head -1) -F -- "$substring" >/dev/null; then
return 0 # $substring is in $string
else
return 1 # $substring is not in $string
fi
}
contains "abcd" "e" || echo "abcd does not contain e"
contains "abcd" "ab" && echo "abcd contains ab"
contains "abcd" "bc" && echo "abcd contains bc"
contains "abcd" "cd" && echo "abcd contains cd"
contains "abcd" "abcd" && echo "abcd contains abcd"
contains "" "" && echo "empty string contains empty string"
contains "a" "" && echo "a contains empty string"
contains "" "a" || echo "empty string does not contain a"
contains "abcd efgh" "cd ef" && echo "abcd efgh contains cd ef"
contains "abcd efgh" " " && echo "abcd efgh contains a space"
contains "abcd [efg] hij" "[efg]" && echo "abcd [efg] hij contains [efg]"
contains "abcd [efg] hij" "[effg]" || echo "abcd [efg] hij does not contain [effg]"
contains "abcd *efg* hij" "*efg*" && echo "abcd *efg* hij contains *efg*"
contains "abcd *efg* hij" "d *efg* h" && echo "abcd *efg* hij contains d *efg* h"
contains "abcd *efg* hij" "*effg*" || echo "abcd *efg* hij does not contain *effg*"
