我看不出这里虚拟关键词的重要性。B是一个静态类型变量，它的类型由编译器在编译时确定。函数调用不会引用虚表。当b被构造时，它的父类的构造函数被调用，这就是为什么_n的值被设置为1。

在大多数OO语言中，从构造函数调用多态函数是导致灾难的原因。遇到这种情况时，不同的语言会有不同的表现。

基本问题是，在所有语言中，基类型必须在派生类型之前构造。现在，问题是从构造函数调用多态方法意味着什么。你希望它表现得怎样?有两种方法:在基本层调用方法(c++风格)或在层次结构底部的未构造对象上调用多态方法(Java方式)。

In C++ the Base class will build its version of the virtual method table prior to entering its own construction. At this point a call to the virtual method will end up calling the Base version of the method or producing a pure virtual method called in case it has no implementation at that level of the hierarchy. After the Base has been fully constructed, the compiler will start building the Derived class, and it will override the method pointers to point to the implementations in the next level of the hierarchy.

class Base {
public:
   Base() { f(); }
   virtual void f() { std::cout << "Base" << std::endl; } 
};
class Derived : public Base
{
public:
   Derived() : Base() {}
   virtual void f() { std::cout << "Derived" << std::endl; }
};
int main() {
   Derived d;
}
// outputs: "Base" as the vtable still points to Base::f() when Base::Base() is run

In Java, the compiler will build the virtual table equivalent at the very first step of construction, prior to entering the Base constructor or Derived constructor. The implications are different (and to my likings more dangerous). If the base class constructor calls a method that is overriden in the derived class the call will actually be handled at the derived level calling a method on an unconstructed object, yielding unexpected results. All attributes of the derived class that are initialized inside the constructor block are yet uninitialized, including 'final' attributes. Elements that have a default value defined at the class level will have that value.

public class Base {
   public Base() { polymorphic(); }
   public void polymorphic() { 
      System.out.println( "Base" );
   }
}
public class Derived extends Base
{
   final int x;
   public Derived( int value ) {
      x = value;
      polymorphic();
   }
   public void polymorphic() {
      System.out.println( "Derived: " + x ); 
   }
   public static void main( String args[] ) {
      Derived d = new Derived( 5 );
   }
}
// outputs: Derived 0
//          Derived 5
// ... so much for final attributes never changing :P

如您所见，调用多态(c++术语为虚拟)方法是一个常见的错误来源。在c++中，至少你可以保证它永远不会对一个尚未构造的对象调用方法……

你知道Windows资源管理器的崩溃错误吗?“纯虚函数调用…” 同样的问题…

class AbstractClass 
{
public:
    AbstractClass( ){
        //if you call pureVitualFunction I will crash...
    }
    virtual void pureVitualFunction() = 0;
};

由于pureVitualFunction()函数没有实现，并且在构造函数中调用该函数，因此程序将崩溃。

c++标准(ISO/IEC 14882-2014)说:

Member functions, including virtual functions (10.3), can be called during construction or destruction (12.6.2). When a virtual function is called directly or indirectly from a constructor or from a destructor, including during the construction or destruction of the class’s non-static data members, and the object to which the call applies is the object (call it x) under construction or destruction, the function called is the final overrider in the constructor’s or destructor’s class and not one overriding it in a more-derived class. If the virtual function call uses an explicit class member access (5.2.5) and the object expression refers to the complete object of x or one of that object’s base class subobjects but not x or one of its base class subobjects, the behavior is undefined.

因此，不要从构造函数或析构函数中调用试图调用正在构造或销毁的对象的虚函数，因为构造函数的顺序从基类开始到派生类，而析构函数的顺序从派生类开始到基类。

因此，试图从正在构建的基类调用派生类函数是危险的。类似地，对象以与构造相反的顺序被销毁，因此试图从析构函数调用派生类中的函数可能会访问已经释放的资源。

c++ FAQ Lite很好地涵盖了这一点:

本质上，在调用基类构造函数期间，对象还不是派生类型，因此调用的是基类型的虚函数实现，而不是派生类型的实现。

作为补充，调用尚未完成构造的对象的虚函数也将面临同样的问题。

例如，在对象的构造函数中启动一个新线程，并将该对象传递给新线程，如果新线程在对象完成构造之前调用该对象的虚函数将导致意想不到的结果。

例如:

#include <thread>
#include <string>
#include <iostream>
#include <chrono>

class Base
{
public:
  Base()
  {
    std::thread worker([this] {
      // This will print "Base" rather than "Sub".
      this->Print();
    });
    worker.detach();
    // Try comment out this code to see different output.
    std::this_thread::sleep_for(std::chrono::seconds(1));
  }
  virtual void Print()
  {
    std::cout << "Base" << std::endl;
  }
};

class Sub : public Base
{
public:
  void Print() override
  {
    std::cout << "Sub" << std::endl;
  }
};

int main()
{
  Sub sub;
  sub.Print();
  getchar();
  return 0;
}

这将输出:

Base
Sub