到目前为止,当我需要在小部件中使用条件语句时,我已经做了以下工作(使用中心和容器作为简化的虚拟示例):

new Center(
  child: condition == true ? new Container() : new Container()
)

虽然当我尝试使用if/else语句时,它会导致一个死亡代码警告:

new Center(
  child: 
    if(condition == true){
      new Container();
    }else{
      new Container();
    }
)

有趣的是,我尝试了一个switch case语句,它给了我同样的警告,因此我不能运行代码。我做错了什么,或者它是这样的,不能使用if/else或开关语句而不颤振认为有死代码?


当前回答

仅当部件振动时

if(bool = true) Container(

child: ....

),

OR

if(bool = true) Container(

child: ....

) else new Container(child: lalala),

其他回答

Flutter Widget可以在不破坏代码树的情况下有条件地用父元素包装子树

import 'package:flutter/widgets.dart';

/// Conditionally wrap a subtree with a parent widget without breaking the code tree.
///
/// [condition]: the condition depending on which the subtree [child] is wrapped with the parent.
/// [child]: The subtree that should always be build.
/// [conditionalBuilder]: builds the parent with the subtree [child].
///
/// ___________
/// Usage:
/// ```dart
/// return ConditionalParentWidget(
///   condition: shouldIncludeParent,
///   child: Widget1(
///     child: Widget2(
///       child: Widget3(),
///     ),
///   ),
///   conditionalBuilder: (Widget child) => SomeParentWidget(child: child),
///);
/// ```
///
/// ___________
/// Instead of:
/// ```dart
/// Widget child = Widget1(
///   child: Widget2(
///     child: Widget3(),
///   ),
/// );
///
/// return shouldIncludeParent ? SomeParentWidget(child: child) : child;
/// ```
///
class ConditionalParentWidget extends StatelessWidget {
  const ConditionalParentWidget({
    Key key,
    @required this.condition,
    @required this.child,
    @required this.conditionalBuilder,
  }) : super(key: key);

  final Widget child;
  final bool condition;
  final Widget Function(Widget child) conditionalBuilder;

  @override
  Widget build(BuildContext context) {
    return condition ? this.conditionalBuilder(this.child) : this.child;
  }
}

我发现使用条件逻辑构建Flutter UI的一个简单方法是将逻辑保持在UI之外。下面是一个返回两种不同颜色的函数:

Color getColor(int selector) {
  if (selector % 2 == 0) {
    return Colors.blue;
  } else {
    return Colors.blueGrey;
  }
}

下面的函数用于设置CircleAvatar的背景。

new ListView.builder(
  itemCount: users.length,
  itemBuilder: (BuildContext context, int index) {
    return new Column(
      children: <Widget>[
        new ListTile(
          leading: new CircleAvatar(
            backgroundColor: getColor(index),
            child: new Text(users[index].name[0])
          ),
          title: new Text(users[index].login),
          subtitle: new Text(users[index].name),
        ),
        new Divider(height: 2.0),
      ],
    );
  },
);

非常整洁,因为你可以在几个小部件中重用你的颜色选择器函数。

另一种选择:对于“switch’s”这样的语句,有很多条件,我喜欢使用map:

return Card(
        elevation: 0,
        margin: EdgeInsets.all(1),
        child: conditions(widget.coupon)[widget.coupon.status] ??
            (throw ArgumentError('invalid status')));


conditions(Coupon coupon) => {
      Status.added_new: CheckableCouponTile(coupon.code),
      Status.redeemed: SimpleCouponTile(coupon.code),
      Status.invalid: SimpleCouponTile(coupon.code),
      Status.valid_not_redeemed: SimpleCouponTile(coupon.code),
    };

在不使用条件语句的情况下,更容易向条件列表中添加/删除元素。

另一个例子:

var condts = {
  0: Container(),
  1: Center(),
  2: Row(),
  3: Column(),
  4: Stack(),
};

class WidgetByCondition extends StatelessWidget {
  final int index;
  WidgetByCondition(this.index);
  @override
  Widget build(BuildContext context) {
    return condts[index];
  }
}

****您还可以使用此方法****来使用条件

 int _moneyCounter = 0;
  void _rainMoney(){
    setState(() {
      _moneyCounter +=  100;
    });
  }

new Expanded(
          child: new Center(
            child: new Text('\$$_moneyCounter', 

            style:new TextStyle(
              color: _moneyCounter > 1000 ? Colors.blue : Colors.amberAccent,
              fontSize: 47,
              fontWeight: FontWeight.w800
            )

            ),
          ) 
        ),

如果希望避免使用If语句,可以使用Flutter Visibility小部件

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