This is older question but I was trying to do something similar. I need to keep n workers going. They are structured in a promise. I need to scan and see if they are resolved, rejected or still pending. If resolved, I need the value, if rejected do something to correct the issue or pending. If resolved or rejected I need to start another task to keep n going. I can't figure a way to do it with Promise.all or Promise.race as I keep working promises in an array and can find no way to delete them. So I create a worker that does the trick

我需要一个承诺生成器函数，返回一个承诺，根据需要解决或拒绝。它由一个函数调用，该函数设置框架以了解承诺在做什么。

在下面的代码中，生成器只是返回一个基于setTimeout的承诺。

在这里

//argObj should be of form
// {succeed: <true or false, nTimer: <desired time out>}
function promiseGenerator(argsObj) {
  let succeed = argsObj.succeed;          
  let nTimer = argsObj.nTimer;
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      if (succeed) {
        resolve('ok');
      }
      else {
        reject(`fail`);
      }
    }, nTimer);
  })

}

function doWork(generatorargs) {
  let sp = { state: `pending`, value: ``, promise: "" };
  let p1 = promiseGenerator(generatorargs)
    .then((value) => {
      sp.state = "resolved";
      sp.value = value;
    })
    .catch((err) => {
      sp.state = "rejected";
      sp.value = err;
    })
  sp.promise = p1;
  return sp;
}

doWork返回一个包含promise及其状态和返回值的对象。

下面的代码运行一个循环，测试状态并创建新的工作线程以保持在3个正在运行的工作线程。

let promiseArray = [];

promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
promiseArray.push(doWork({ succeed: true, nTimer: 500 }));
promiseArray.push(doWork({ succeed: false, nTimer: 3000 }));

function loopTimerPromise(delay) {
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      resolve('ok');
    }, delay)
  })
}

async function looper() {
  let nPromises = 3;      //just for breaking loop
  let nloop = 0;          //just for breaking loop
  let i;
  //let continueLoop = true;
  while (true) {
    await loopTimerPromise(900);  //execute loop every 900ms
    nloop++;
    //console.log(`promiseArray.length = ${promiseArray.length}`);
    for (i = promiseArray.length; i--; i > -1) {
      console.log(`index ${i} state: ${promiseArray[i].state}`);
      switch (promiseArray[i].state) {
        case "pending":
          break;
        case "resolved":
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
          break;
        case "rejected":
          //take recovery action
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: false, nTimer: 500 }));
          break;
        default:
          console.log(`error bad state in i=${i} state:${promiseArray[i].state} `)
          break;
      }
    }
    console.log(``);
    if (nloop > 10 || nPromises > 10) {
      //should do a Promise.all on remaining promises to clean them up but not for test
      break;
    }
  }
}

looper();

在node.js中测试

顺便说一句，不是在这个问题上，而是在其他类似的问题上，我讨厌有人说“你不明白”或“事情不是这样的”，我通常认为提问者知道他们想要什么。建议一个更好的方法是很好的。耐心地解释承诺如何起作用也会很好。

更新:2019

Bluebird.js提供了这个:http://bluebirdjs.com/docs/api/isfulfilled.html

var Promise = require("bluebird");
let p = Promise.resolve();
console.log(p.isFulfilled());

如果您更喜欢创建自己的包装器，这里有一个关于它的不错的博客。

因为JavaScript是单线程的，所以很难找到一个足够常见的用例来证明将其放在规范中是正确的。知道承诺是否被解决的最佳位置是在.then()中。测试Promise是否被履行将创建一个轮询循环，这很可能是错误的方向。

如果你想同步推理异步代码，Async /await是一个很好的结构。

await this();
await that();
return 'success!';

另一个有用的调用是Promise.all()

var promise1 = Promise.resolve(3);
var promise2 = 42;
var promise3 = new Promise(function(resolve, reject) {
  setTimeout(resolve, 100, 'foo');
});

Promise.all([promise1, promise2, promise3]).then(function(values) {
  console.log(values);
});
// expected output: Array [3, 42, "foo"]

当我第一次得到这个答案时，这就是我正在寻找的用例。

你可以在Node.js中使用一个(丑陋的)黑客，直到一个本地方法被提供:

util = require('util');

var promise1 = new Promise (function (resolve) {
}

var promise2 = new Promise (function (resolve) {

    resolve ('foo');
}

state1 = util.inspect (promise1);
state2 = util.inspect (promise2);

if (state1 === 'Promise { <pending> }') {

    console.log('pending'); // pending
}

if (state2 === "Promise { 'foo' }") {

    console.log ('foo') // foo
}

不，没有同步API，但这是我的async承诺(在@Matthijs的帮助下):

函数promiseState(p) { Const t = {}; 回报的承诺。种族([p t]) .then(v => (v == t)?"pending": " completed "， () => "rejected"); ｝ var a = Promise.resolve(); var b = Promise.reject(); var c = new Promise(() => {}); promiseState (a)。Then (state => console.log(state));/ /实现 promiseState (b)。Then (state => console.log(state));/ /拒绝 promiseState (c)。Then (state => console.log(state));/ /等待

Promise-status-async可以做到。它是异步的，但它不使用然后等待承诺被解决。

const {promiseStatus} = require('promise-status-async');
// ...
if (await promiseStatus(promise) === 'pending') {
    const idle = new Promise(function(resolve) {
        // can do some IDLE job meanwhile
    });
    return idle;
}

从Node.js版本8开始，您现在可以使用智能检查包来同步检查本机承诺(没有任何危险的黑客)。