This is older question but I was trying to do something similar. I need to keep n workers going. They are structured in a promise. I need to scan and see if they are resolved, rejected or still pending. If resolved, I need the value, if rejected do something to correct the issue or pending. If resolved or rejected I need to start another task to keep n going. I can't figure a way to do it with Promise.all or Promise.race as I keep working promises in an array and can find no way to delete them. So I create a worker that does the trick
我需要一个承诺生成器函数,返回一个承诺,根据需要解决或拒绝。它由一个函数调用,该函数设置框架以了解承诺在做什么。
在下面的代码中,生成器只是返回一个基于setTimeout的承诺。
在这里
//argObj should be of form
// {succeed: <true or false, nTimer: <desired time out>}
function promiseGenerator(argsObj) {
let succeed = argsObj.succeed;
let nTimer = argsObj.nTimer;
return new Promise((resolve, reject) => {
setTimeout(() => {
if (succeed) {
resolve('ok');
}
else {
reject(`fail`);
}
}, nTimer);
})
}
function doWork(generatorargs) {
let sp = { state: `pending`, value: ``, promise: "" };
let p1 = promiseGenerator(generatorargs)
.then((value) => {
sp.state = "resolved";
sp.value = value;
})
.catch((err) => {
sp.state = "rejected";
sp.value = err;
})
sp.promise = p1;
return sp;
}
doWork返回一个包含promise及其状态和返回值的对象。
下面的代码运行一个循环,测试状态并创建新的工作线程以保持在3个正在运行的工作线程。
let promiseArray = [];
promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
promiseArray.push(doWork({ succeed: true, nTimer: 500 }));
promiseArray.push(doWork({ succeed: false, nTimer: 3000 }));
function loopTimerPromise(delay) {
return new Promise((resolve, reject) => {
setTimeout(() => {
resolve('ok');
}, delay)
})
}
async function looper() {
let nPromises = 3; //just for breaking loop
let nloop = 0; //just for breaking loop
let i;
//let continueLoop = true;
while (true) {
await loopTimerPromise(900); //execute loop every 900ms
nloop++;
//console.log(`promiseArray.length = ${promiseArray.length}`);
for (i = promiseArray.length; i--; i > -1) {
console.log(`index ${i} state: ${promiseArray[i].state}`);
switch (promiseArray[i].state) {
case "pending":
break;
case "resolved":
nPromises++;
promiseArray.splice(i, 1);
promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
break;
case "rejected":
//take recovery action
nPromises++;
promiseArray.splice(i, 1);
promiseArray.push(doWork({ succeed: false, nTimer: 500 }));
break;
default:
console.log(`error bad state in i=${i} state:${promiseArray[i].state} `)
break;
}
}
console.log(``);
if (nloop > 10 || nPromises > 10) {
//should do a Promise.all on remaining promises to clean them up but not for test
break;
}
}
}
looper();
在node.js中测试
顺便说一句,不是在这个问题上,而是在其他类似的问题上,我讨厌有人说“你不明白”或“事情不是这样的”,我通常认为提问者知道他们想要什么。建议一个更好的方法是很好的。耐心地解释承诺如何起作用也会很好。