我有一个纯JavaScript承诺(内置实现或poly-fill):

var promise = new promise(函数(解析,拒绝){/*…* /});

从规范来看,Promise可以是:

" settle "和" resolved " “解决”和“拒绝” “等待”

我有一个用例,我希望同步审问承诺并确定:

承诺达成了吗? 如果是,承诺解决了吗?

我知道我可以使用#then()来安排在Promise改变状态后异步执行的工作。我不是在问你该怎么做。

这个问题是关于Promise状态的同步询问。我怎样才能做到这一点呢?


当前回答

这里是一个更充实的QueryablePromise的es6版本,允许在第一次解析后进行链接和捕获,并立即解析或拒绝以保持api与本机Promise一致。

const PROMISE = Symbol('PROMISE') const tap = fn => x => (fn(x), x) const trace = label => tap(x => console.log(label, x)) class QueryablePromise { resolved = false rejected = false fulfilled = false catchFns = [] constructor(fn) { this[PROMISE] = new Promise(fn) .then(tap(() => { this.fulfilled = true this.resolved = true })) .catch(x => { this.fulfilled = true this.rejected = true return Promise.reject(x) }) } then(fn) { this[PROMISE].then(fn) return this } catch(fn) { this[PROMISE].catch(fn) return this } static resolve(x) { return new QueryablePromise((res) => res(x)) } static reject(x) { return new QueryablePromise((_, rej) => rej(x)) } } const resolvedPromise = new QueryablePromise((res) => { setTimeout(res, 200, 'resolvedPromise') }) const rejectedPromise = new QueryablePromise((_, rej) => { setTimeout(rej, 200, 'rejectedPromise') }) // ensure our promises have not been fulfilled console.log('test 1 before: is resolved', resolvedPromise.resolved) console.log('test 2 before: is rejected', rejectedPromise.rejected) setTimeout(() => { // check to see the resolved status of our promise console.log('test 1 after: is resolved', resolvedPromise.resolved) console.log('test 2 after: is rejected', rejectedPromise.rejected) }, 300) // make sure we can immediately resolve a QueryablePromise const immediatelyResolvedPromise = QueryablePromise.resolve('immediatelyResolvedPromise') // ensure we can chain then .then(trace('test 3 resolved')) .then(trace('test 3 resolved 2')) .catch(trace('test 3 rejected')) // make sure we can immediately reject a QueryablePromise const immediatelyRejectedPromise = QueryablePromise.reject('immediatelyRejectedPromise') .then(trace('test 4 resolved')) .catch(trace('test 4 rejected')) <script src="https://codepen.io/synthet1c/pen/KyQQmL.js"></script>

其他回答

对于原生JavaScript承诺,不存在这样的同步检查API。用本土的承诺是不可能做到的。规范没有指定这样的方法。

用户域库可以做到这一点,如果你的目标是一个特定的引擎(比如v8),并且可以访问平台代码(也就是说,你可以在核心中编写代码),那么你可以使用特定的工具(比如私有符号)来实现这一点。这是非常具体的,但不是在用户领域。

不,没有同步API,但这是我的async承诺(在@Matthijs的帮助下):

函数promiseState(p) { Const t = {}; 回报的承诺。种族([p t]) .then(v => (v == t)?"pending": " completed ", () => "rejected"); } var a = Promise.resolve(); var b = Promise.reject(); var c = new Promise(() => {}); promiseState (a)。Then (state => console.log(state));/ /实现 promiseState (b)。Then (state => console.log(state));/ /拒绝 promiseState (c)。Then (state => console.log(state));/ /等待

老问题有很多答案,但似乎没有一个建议我认为是最简单的解决方案:在承诺解决/拒绝上设置bool指示器。

类Promise2 { 构造函数(args) { let promise = new promise(…args); promise.then(() => promise。_resolved_ = true); promise.catch(() => promise。_rejected_ = true); 返回的诺言; } } let p = new promise (r => setTimeout(r, 3000)); setInterval(() => { Console.log('正在同步检查p是否已解析?”,p._resolved_); }, 1000);

This is older question but I was trying to do something similar. I need to keep n workers going. They are structured in a promise. I need to scan and see if they are resolved, rejected or still pending. If resolved, I need the value, if rejected do something to correct the issue or pending. If resolved or rejected I need to start another task to keep n going. I can't figure a way to do it with Promise.all or Promise.race as I keep working promises in an array and can find no way to delete them. So I create a worker that does the trick

我需要一个承诺生成器函数,返回一个承诺,根据需要解决或拒绝。它由一个函数调用,该函数设置框架以了解承诺在做什么。

在下面的代码中,生成器只是返回一个基于setTimeout的承诺。

在这里

//argObj should be of form
// {succeed: <true or false, nTimer: <desired time out>}
function promiseGenerator(argsObj) {
  let succeed = argsObj.succeed;          
  let nTimer = argsObj.nTimer;
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      if (succeed) {
        resolve('ok');
      }
      else {
        reject(`fail`);
      }
    }, nTimer);
  })

}

function doWork(generatorargs) {
  let sp = { state: `pending`, value: ``, promise: "" };
  let p1 = promiseGenerator(generatorargs)
    .then((value) => {
      sp.state = "resolved";
      sp.value = value;
    })
    .catch((err) => {
      sp.state = "rejected";
      sp.value = err;
    })
  sp.promise = p1;
  return sp;
}

doWork返回一个包含promise及其状态和返回值的对象。

下面的代码运行一个循环,测试状态并创建新的工作线程以保持在3个正在运行的工作线程。

let promiseArray = [];

promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
promiseArray.push(doWork({ succeed: true, nTimer: 500 }));
promiseArray.push(doWork({ succeed: false, nTimer: 3000 }));

function loopTimerPromise(delay) {
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      resolve('ok');
    }, delay)
  })
}

async function looper() {
  let nPromises = 3;      //just for breaking loop
  let nloop = 0;          //just for breaking loop
  let i;
  //let continueLoop = true;
  while (true) {
    await loopTimerPromise(900);  //execute loop every 900ms
    nloop++;
    //console.log(`promiseArray.length = ${promiseArray.length}`);
    for (i = promiseArray.length; i--; i > -1) {
      console.log(`index ${i} state: ${promiseArray[i].state}`);
      switch (promiseArray[i].state) {
        case "pending":
          break;
        case "resolved":
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
          break;
        case "rejected":
          //take recovery action
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: false, nTimer: 500 }));
          break;
        default:
          console.log(`error bad state in i=${i} state:${promiseArray[i].state} `)
          break;
      }
    }
    console.log(``);
    if (nloop > 10 || nPromises > 10) {
      //should do a Promise.all on remaining promises to clean them up but not for test
      break;
    }
  }
}

looper();

在node.js中测试

顺便说一句,不是在这个问题上,而是在其他类似的问题上,我讨厌有人说“你不明白”或“事情不是这样的”,我通常认为提问者知道他们想要什么。建议一个更好的方法是很好的。耐心地解释承诺如何起作用也会很好。

警告:process.binding(“跑龙套”)。节点16上的getPromiseDetails未定义!

基准:

候选人:

/**
 * https://stackoverflow.com/a/47009572/5318303
 */
const isPromisePending1 = (() => { // noinspection JSUnresolvedFunction
    const util = process.binding('util')  // noinspection JSUnresolvedFunction
    return promise => !util.getPromiseDetails(promise)[0]
})()

/**
 * https://stackoverflow.com/a/35852666/5318303
 */
const isPromisePending2 = (promise) => util.inspect(promise) === 'Promise { <pending> }'

/**
 * https://stackoverflow.com/a/35820220/5318303
 */
const isPromisePending3 = (promise) => {
    const t = {}
    return Promise.race([promise, t])
            .then(v => v === t, () => false)
}

测试的承诺:

const a = Promise.resolve()
const b = Promise.reject()
const c = new Promise(() => {})
const x = (async () => 1)()

运行基准:

const n = 1000000

console.time('isPromisePending1')
for (let i = 0; i < n; i++) {
    isPromisePending1(a)
    isPromisePending1(b)
    isPromisePending1(c)
    isPromisePending1(x)
}
console.timeEnd('isPromisePending1')

console.time('isPromisePending2')
for (let i = 0; i < n; i++) {
    isPromisePending2(a)
    isPromisePending2(b)
    isPromisePending2(c)
    isPromisePending2(x)
}
console.timeEnd('isPromisePending2')

console.time('isPromisePending3')
for (let i = 0; i < n; i++) {
    await isPromisePending3(a)
    await isPromisePending3(b)
    await isPromisePending3(c)
    await isPromisePending3(x)
}
console.timeEnd('isPromisePending3')

结果:

isPromisePending1: 440.694ms
isPromisePending2: 3.354s
isPromisePending3: 4.761s

显然isPromisePending1()太快了(8~10倍)!但它在节点16上不可用!(见上述警告)。