我有一个纯JavaScript承诺(内置实现或poly-fill):

var promise = new promise(函数(解析,拒绝){/*…* /});

从规范来看,Promise可以是:

" settle "和" resolved " “解决”和“拒绝” “等待”

我有一个用例,我希望同步审问承诺并确定:

承诺达成了吗? 如果是,承诺解决了吗?

我知道我可以使用#then()来安排在Promise改变状态后异步执行的工作。我不是在问你该怎么做。

这个问题是关于Promise状态的同步询问。我怎样才能做到这一点呢?


当前回答

警告:process.binding(“跑龙套”)。节点16上的getPromiseDetails未定义!

基准:

候选人:

/**
 * https://stackoverflow.com/a/47009572/5318303
 */
const isPromisePending1 = (() => { // noinspection JSUnresolvedFunction
    const util = process.binding('util')  // noinspection JSUnresolvedFunction
    return promise => !util.getPromiseDetails(promise)[0]
})()

/**
 * https://stackoverflow.com/a/35852666/5318303
 */
const isPromisePending2 = (promise) => util.inspect(promise) === 'Promise { <pending> }'

/**
 * https://stackoverflow.com/a/35820220/5318303
 */
const isPromisePending3 = (promise) => {
    const t = {}
    return Promise.race([promise, t])
            .then(v => v === t, () => false)
}

测试的承诺:

const a = Promise.resolve()
const b = Promise.reject()
const c = new Promise(() => {})
const x = (async () => 1)()

运行基准:

const n = 1000000

console.time('isPromisePending1')
for (let i = 0; i < n; i++) {
    isPromisePending1(a)
    isPromisePending1(b)
    isPromisePending1(c)
    isPromisePending1(x)
}
console.timeEnd('isPromisePending1')

console.time('isPromisePending2')
for (let i = 0; i < n; i++) {
    isPromisePending2(a)
    isPromisePending2(b)
    isPromisePending2(c)
    isPromisePending2(x)
}
console.timeEnd('isPromisePending2')

console.time('isPromisePending3')
for (let i = 0; i < n; i++) {
    await isPromisePending3(a)
    await isPromisePending3(b)
    await isPromisePending3(c)
    await isPromisePending3(x)
}
console.timeEnd('isPromisePending3')

结果:

isPromisePending1: 440.694ms
isPromisePending2: 3.354s
isPromisePending3: 4.761s

显然isPromisePending1()太快了(8~10倍)!但它在节点16上不可用!(见上述警告)。

其他回答

2019:

据我所知,做到这一点的简单方法是thenable,超薄包装承诺或任何异步作业。

const sleep = (t) => new Promise(res => setTimeout(res,t));
const sleeping = sleep(30);

function track(promise){
    let state = 'pending';
    promise = promise.finally( _=> state ='fulfilled');
    return {
        get state(){return state},
        then: promise.then.bind(promise), /*thentable*/
        finally:promise.finally.bind(promise),
        catch:promise.catch.bind(promise),
    }
}


promise = track(sleeping);
console.log(promise.state) // pending

promise.then(function(){
    console.log(promise.state); // fulfilled
})

您可以扩展Promise类来创建一个新的可查询的Promise 类。

您可以通过继承本机可用的Promise类来创建自己的子类,比如QueryablePromise,它的实例上有一个可用的status属性,您可以使用该属性同步查询Promise对象的状态。它的实现可以在下面看到,或者参考这个来获得更好的解释。

class QueryablePromise extends Promise { constructor (executor) { super((resolve, reject) => executor( data => { resolve(data) this._status = 'Resolved' }, err => { reject(err) this._status = 'Rejected' }, )) this._status = 'Pending' } get status () { return this._status } } // Create a promise that resolves after 5 sec var myQueryablePromise = new QueryablePromise((resolve, reject) => { setTimeout(() => resolve(), 5000) }) // Log the status of the above promise every 500ms setInterval(() => { console.log(myQueryablePromise.status) }, 500)

This is older question but I was trying to do something similar. I need to keep n workers going. They are structured in a promise. I need to scan and see if they are resolved, rejected or still pending. If resolved, I need the value, if rejected do something to correct the issue or pending. If resolved or rejected I need to start another task to keep n going. I can't figure a way to do it with Promise.all or Promise.race as I keep working promises in an array and can find no way to delete them. So I create a worker that does the trick

我需要一个承诺生成器函数,返回一个承诺,根据需要解决或拒绝。它由一个函数调用,该函数设置框架以了解承诺在做什么。

在下面的代码中,生成器只是返回一个基于setTimeout的承诺。

在这里

//argObj should be of form
// {succeed: <true or false, nTimer: <desired time out>}
function promiseGenerator(argsObj) {
  let succeed = argsObj.succeed;          
  let nTimer = argsObj.nTimer;
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      if (succeed) {
        resolve('ok');
      }
      else {
        reject(`fail`);
      }
    }, nTimer);
  })

}

function doWork(generatorargs) {
  let sp = { state: `pending`, value: ``, promise: "" };
  let p1 = promiseGenerator(generatorargs)
    .then((value) => {
      sp.state = "resolved";
      sp.value = value;
    })
    .catch((err) => {
      sp.state = "rejected";
      sp.value = err;
    })
  sp.promise = p1;
  return sp;
}

doWork返回一个包含promise及其状态和返回值的对象。

下面的代码运行一个循环,测试状态并创建新的工作线程以保持在3个正在运行的工作线程。

let promiseArray = [];

promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
promiseArray.push(doWork({ succeed: true, nTimer: 500 }));
promiseArray.push(doWork({ succeed: false, nTimer: 3000 }));

function loopTimerPromise(delay) {
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      resolve('ok');
    }, delay)
  })
}

async function looper() {
  let nPromises = 3;      //just for breaking loop
  let nloop = 0;          //just for breaking loop
  let i;
  //let continueLoop = true;
  while (true) {
    await loopTimerPromise(900);  //execute loop every 900ms
    nloop++;
    //console.log(`promiseArray.length = ${promiseArray.length}`);
    for (i = promiseArray.length; i--; i > -1) {
      console.log(`index ${i} state: ${promiseArray[i].state}`);
      switch (promiseArray[i].state) {
        case "pending":
          break;
        case "resolved":
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
          break;
        case "rejected":
          //take recovery action
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: false, nTimer: 500 }));
          break;
        default:
          console.log(`error bad state in i=${i} state:${promiseArray[i].state} `)
          break;
      }
    }
    console.log(``);
    if (nloop > 10 || nPromises > 10) {
      //should do a Promise.all on remaining promises to clean them up but not for test
      break;
    }
  }
}

looper();

在node.js中测试

顺便说一句,不是在这个问题上,而是在其他类似的问题上,我讨厌有人说“你不明白”或“事情不是这样的”,我通常认为提问者知道他们想要什么。建议一个更好的方法是很好的。耐心地解释承诺如何起作用也会很好。

你可以和Promise.resolve赛跑 它不是同步的,但现在就发生了

function promiseState(p, isPending, isResolved, isRejected) {
  Promise.race([p, Promise.resolve('a value that p should not return')]).then(function(value) {
    if (value == 'a value that p should not return') {
      (typeof(isPending) === 'function') && isPending();
    }else {
      (typeof(isResolved) === 'function') && isResolved(value);
    }
  }, function(reason) {
    (typeof(isRejected) === 'function') && isRejected(reason);
  });
}

一个用于测试的小脚本,并理解异步的含义

var startTime = Date.now() - 100000;//padding trick "100001".slice(1) => 00001
function log(msg) {
  console.log((""+(Date.now() - startTime)).slice(1) + ' ' + msg);
  return msg;//for chaining promises
};

function prefix(pref) { return function (value) { log(pref + value); return value; };}

function delay(ms) {
  return function (value) {
    var startTime = Date.now();
    while(Date.now() - startTime < ms) {}
    return value;//for chaining promises
  };
}
setTimeout(log, 0,'timeOut 0 ms');
setTimeout(log, 100,'timeOut 100 ms');
setTimeout(log, 200,'timeOut 200 ms');

var p1 = Promise.resolve('One');
var p2 = new Promise(function(resolve, reject) { setTimeout(resolve, 100, "Two"); });
var p3 = Promise.reject("Three");

p3.catch(delay(200)).then(delay(100)).then(prefix('delayed L3 : '));

promiseState(p1, prefix('p1 Is Pending '), prefix('p1 Is Resolved '), prefix('p1 Is Rejected '));
promiseState(p2, prefix('p2 Is Pending '), prefix('p2 Is Resolved '), prefix('p2 Is Rejected '));
promiseState(p3, prefix('p3 Is Pending '), prefix('p3 Is Resolved '), prefix('p3 Is Rejected '));

p1.then(prefix('Level 1 : ')).then(prefix('Level 2 : ')).then(prefix('Level 3 : '));
p2.then(prefix('Level 1 : ')).then(prefix('Level 2 : ')).then(prefix('Level 3 : '));
p3.catch(prefix('Level 1 : ')).then(prefix('Level 2 : ')).then(prefix('Level 3 : '));
log('end of promises');
delay(100)();
log('end of script');

延迟(0)的结果(注释在延迟中的while)

00001 end of promises
00001 end of script
00001 Level 1 : One
00001 Level 1 : Three
00001 p1 Is Resolved One
00001 p2 Is Pending undefined
00001 p3 Is Rejected Three
00001 Level 2 : One
00001 Level 2 : Three
00001 delayed L3 : Three
00002 Level 3 : One
00002 Level 3 : Three
00006 timeOut 0 ms
00100 timeOut 100 ms
00100 Level 1 : Two
00100 Level 2 : Two
00101 Level 3 : Two
00189 timeOut 200 ms

与firefox(chrome保持顺序)测试的结果

00000 end of promises
00100 end of script
00300 Level 1 : One
00300 Level 1 : Three
00400 p1 Is Resolved One
00400 p2 Is Pending undefined
00400 p3 Is Rejected Three
00400 Level 2 : One
00400 Level 2 : Three
00400 delayed L3 : Three
00400 Level 3 : One
00400 Level 3 : Three
00406 timeOut 0 ms
00406 timeOut 100 ms
00406 timeOut 200 ms
00406 Level 1 : Two
00407 Level 2 : Two
00407 Level 3 : Two

promise estate make .race and .then:第二级

更新:2019

Bluebird.js提供了这个:http://bluebirdjs.com/docs/api/isfulfilled.html

var Promise = require("bluebird");
let p = Promise.resolve();
console.log(p.isFulfilled());

如果您更喜欢创建自己的包装器,这里有一个关于它的不错的博客。

因为JavaScript是单线程的,所以很难找到一个足够常见的用例来证明将其放在规范中是正确的。知道承诺是否被解决的最佳位置是在.then()中。测试Promise是否被履行将创建一个轮询循环,这很可能是错误的方向。

如果你想同步推理异步代码,Async /await是一个很好的结构。

await this();
await that();
return 'success!';

另一个有用的调用是Promise.all()

var promise1 = Promise.resolve(3);
var promise2 = 42;
var promise3 = new Promise(function(resolve, reject) {
  setTimeout(resolve, 100, 'foo');
});

Promise.all([promise1, promise2, promise3]).then(function(values) {
  console.log(values);
});
// expected output: Array [3, 42, "foo"]

当我第一次得到这个答案时,这就是我正在寻找的用例。