使用hashCode，就像Cristian Sanchez用hsl和现代javascript回答的那样，你可以创建一个具有良好对比度的颜色选择器，如下所示:

函数hashCode(str) { 设hash = 0; For (var I = 0;I < str.length;我+ +){ hash = str.charCodeAt(i) + ((hash << 5) - hash); ｝ 返回哈希; ｝ 函数pickColor(str) { 返回' hsl(${hashCode(str) % 360}， 100%， 80%) '; ｝ one.style.backgroundColor = pickColor(one.innerText) two.style.backgroundColor = pickColor(two.innerText) div { 填充:10 px; ｝ < div id = " 1 " > < / div >一 < div id = "两个“>两个div > < /

因为它是hsl，你可以缩放亮度来得到你想要的对比度。

function hashCode(str) { let hash = 0; for (var i = 0; i < str.length; i++) { hash = str.charCodeAt(i) + ((hash << 5) - hash); } return hash; } function pickColor(str) { // Note the last value here is now 50% instead of 80% return `hsl(${hashCode(str) % 360}, 100%, 50%)`; } one.style.backgroundColor = pickColor(one.innerText) two.style.backgroundColor = pickColor(two.innerText) div { color: white; padding: 10px; } <div id="one">One</div> <div id="two">Two</div>

我想要类似丰富的HTML元素的颜色，我惊讶地发现CSS现在支持hsl()颜色，所以一个完整的解决方案如下:

另参见如何自动生成N“不同”的颜色?更多类似的选择。

编辑:根据@zei的版本更新(美式拼写)

var stringToColor = (string, saturation = 100, lightness = 75) => { let hash = 0; for (let i = 0; i < string.length; i++) { hash = string.charCodeAt(i) + ((hash << 5) - hash); hash = hash & hash; } return `hsl(${(hash % 360)}, ${saturation}%, ${lightness}%)`; } // For the sample on stackoverflow function colorByHashCode(value) { return "<span style='color:" + stringToColor(value) + "'>" + value + "</span>"; } document.body.innerHTML = [ "javascript", "is", "nice", ].map(colorByHashCode).join("<br/>"); span { font-size: 50px; font-weight: 800; }

在HSL中，它的色调，饱和度，亮度。所以色调在0-359之间会得到所有的颜色，饱和度是你想要的颜色的丰富程度，100%对我来说是合适的。而亮度决定了深度，50%是正常的，25%是深色，75%是粉彩。我有30%，因为它最适合我的配色方案。

下面是我提出的一个解决方案，根据输入字符串生成美观的粉彩颜色。它使用字符串的前两个字符作为随机种子，然后基于该种子生成R/G/B。

它可以很容易地扩展，以便种子是字符串中所有字符的异或，而不仅仅是前两个字符。

灵感来自David Crow的回答:算法随机生成一个美观的调色板

//magic to convert strings to a nice pastel colour based on first two chars
//
// every string with the same first two chars will generate the same pastel colour
function pastel_colour(input_str) {

    //TODO: adjust base colour values below based on theme
    var baseRed = 128;
    var baseGreen = 128;
    var baseBlue = 128;

    //lazy seeded random hack to get values from 0 - 256
    //for seed just take bitwise XOR of first two chars
    var seed = input_str.charCodeAt(0) ^ input_str.charCodeAt(1);
    var rand_1 = Math.abs((Math.sin(seed++) * 10000)) % 256;
    var rand_2 = Math.abs((Math.sin(seed++) * 10000)) % 256;
    var rand_3 = Math.abs((Math.sin(seed++) * 10000)) % 256;

    //build colour
    var red = Math.round((rand_1 + baseRed) / 2);
    var green = Math.round((rand_2 + baseGreen) / 2);
    var blue = Math.round((rand_3 + baseBlue) / 2);

    return { red: red, green: green, blue: blue };
}

GIST在这里:https://gist.github.com/ro-sharp/49fd46a071a267d9e5dd

Javascript解决方案受到Aslam的解决方案的启发，但返回十六进制颜色代码的颜色

/**
 * 
 * @param {String} - stringInput - 'xyz'
 * @returns {String} - color in hex color code - '#ae6204'
 */
function getBackgroundColor(stringInput) {
    const h = [...stringInput].reduce((acc, char) => {
        return char.charCodeAt(0) + ((acc << 5) - acc);
    }, 0);
    const s = 95, l = 35 / 100;
    const a = s * Math.min(l, 1 - l) / 100;
    const f = n => {
        const k = (n + h / 30) % 12;
        const color = l - a * Math.max(Math.min(k - 3, 9 - k, 1), -1);
        return Math.round(255 * color).toString(16).padStart(2, '0');   // convert to Hex and prefix "0" if needed
    };
    return `#${f(0)}${f(8)}${f(4)}`;
}

这是我2021年的版本，带有还原功能和HSL颜色。

function getBackgroundColor(stringInput) {
    let stringUniqueHash = [...stringInput].reduce((acc, char) => {
        return char.charCodeAt(0) + ((acc << 5) - acc);
    }, 0);
    return `hsl(${stringUniqueHash % 360}, 95%, 35%)`;
}

我发现随机生成的颜色往往没有足够的对比度来满足我的口味。我发现解决这个问题最简单的方法是预先填充一个非常不同的颜色列表。对于每个新字符串，分配列表中的下一个颜色:

// Takes any string and converts it into a #RRGGBB color.
var StringToColor = (function(){
    var instance = null;

    return {
    next: function stringToColor(str) {
        if(instance === null) {
            instance = {};
            instance.stringToColorHash = {};
            instance.nextVeryDifferntColorIdx = 0;
            instance.veryDifferentColors = ["#000000","#00FF00","#0000FF","#FF0000","#01FFFE","#FFA6FE","#FFDB66","#006401","#010067","#95003A","#007DB5","#FF00F6","#FFEEE8","#774D00","#90FB92","#0076FF","#D5FF00","#FF937E","#6A826C","#FF029D","#FE8900","#7A4782","#7E2DD2","#85A900","#FF0056","#A42400","#00AE7E","#683D3B","#BDC6FF","#263400","#BDD393","#00B917","#9E008E","#001544","#C28C9F","#FF74A3","#01D0FF","#004754","#E56FFE","#788231","#0E4CA1","#91D0CB","#BE9970","#968AE8","#BB8800","#43002C","#DEFF74","#00FFC6","#FFE502","#620E00","#008F9C","#98FF52","#7544B1","#B500FF","#00FF78","#FF6E41","#005F39","#6B6882","#5FAD4E","#A75740","#A5FFD2","#FFB167","#009BFF","#E85EBE"];
        }

        if(!instance.stringToColorHash[str])
            instance.stringToColorHash[str] = instance.veryDifferentColors[instance.nextVeryDifferntColorIdx++];

            return instance.stringToColorHash[str];
        }
    }
})();

// Get a new color for each string
StringToColor.next("get first color");
StringToColor.next("get second color");

// Will return the same color as the first time
StringToColor.next("get first color");

虽然它的颜色限制只有64种，但我发现大多数人在那之后都无法真正分辨出区别。我认为你可以添加更多的颜色。

虽然这段代码使用了硬编码的颜色，但至少可以保证您在开发过程中确切地知道在生产中您将看到的颜色之间的对比有多大。

颜色列表是从这个SO答案中提取的，还有其他更多颜色的列表。