下面是另一个尝试:

function stringToColor(str){
  var hash = 0;
  for(var i=0; i < str.length; i++) {
    hash = str.charCodeAt(i) + ((hash << 3) - hash);
  }
  var color = Math.abs(hash).toString(16).substring(0, 6);

  return "#" + '000000'.substring(0, 6 - color.length) + color;
}

Javascript解决方案受到Aslam的解决方案的启发，但返回十六进制颜色代码的颜色

/**
 * 
 * @param {String} - stringInput - 'xyz'
 * @returns {String} - color in hex color code - '#ae6204'
 */
function getBackgroundColor(stringInput) {
    const h = [...stringInput].reduce((acc, char) => {
        return char.charCodeAt(0) + ((acc << 5) - acc);
    }, 0);
    const s = 95, l = 35 / 100;
    const a = s * Math.min(l, 1 - l) / 100;
    const f = n => {
        const k = (n + h / 30) % 12;
        const color = l - a * Math.max(Math.min(k - 3, 9 - k, 1), -1);
        return Math.round(255 * color).toString(16).padStart(2, '0');   // convert to Hex and prefix "0" if needed
    };
    return `#${f(0)}${f(8)}${f(4)}`;
}

你真正需要的是一个好的哈希函数。在节点上，我只用

const crypto = require('crypto');
function strToColor(str) {
    return '#' + crypto.createHash('md5').update(str).digest('hex').substr(0, 6);
}

我发现随机生成的颜色往往没有足够的对比度来满足我的口味。我发现解决这个问题最简单的方法是预先填充一个非常不同的颜色列表。对于每个新字符串，分配列表中的下一个颜色:

// Takes any string and converts it into a #RRGGBB color.
var StringToColor = (function(){
    var instance = null;

    return {
    next: function stringToColor(str) {
        if(instance === null) {
            instance = {};
            instance.stringToColorHash = {};
            instance.nextVeryDifferntColorIdx = 0;
            instance.veryDifferentColors = ["#000000","#00FF00","#0000FF","#FF0000","#01FFFE","#FFA6FE","#FFDB66","#006401","#010067","#95003A","#007DB5","#FF00F6","#FFEEE8","#774D00","#90FB92","#0076FF","#D5FF00","#FF937E","#6A826C","#FF029D","#FE8900","#7A4782","#7E2DD2","#85A900","#FF0056","#A42400","#00AE7E","#683D3B","#BDC6FF","#263400","#BDD393","#00B917","#9E008E","#001544","#C28C9F","#FF74A3","#01D0FF","#004754","#E56FFE","#788231","#0E4CA1","#91D0CB","#BE9970","#968AE8","#BB8800","#43002C","#DEFF74","#00FFC6","#FFE502","#620E00","#008F9C","#98FF52","#7544B1","#B500FF","#00FF78","#FF6E41","#005F39","#6B6882","#5FAD4E","#A75740","#A5FFD2","#FFB167","#009BFF","#E85EBE"];
        }

        if(!instance.stringToColorHash[str])
            instance.stringToColorHash[str] = instance.veryDifferentColors[instance.nextVeryDifferntColorIdx++];

            return instance.stringToColorHash[str];
        }
    }
})();

// Get a new color for each string
StringToColor.next("get first color");
StringToColor.next("get second color");

// Will return the same color as the first time
StringToColor.next("get first color");

虽然它的颜色限制只有64种，但我发现大多数人在那之后都无法真正分辨出区别。我认为你可以添加更多的颜色。

虽然这段代码使用了硬编码的颜色，但至少可以保证您在开发过程中确切地知道在生产中您将看到的颜色之间的对比有多大。

颜色列表是从这个SO答案中提取的，还有其他更多颜色的列表。

以下是对CD Sanchez的答案的改编，它始终返回一个6位数的颜色代码:

var stringToColour = function(str) {
  var hash = 0;
  for (var i = 0; i < str.length; i++) {
    hash = str.charCodeAt(i) + ((hash << 5) - hash);
  }
  var colour = '#';
  for (var i = 0; i < 3; i++) {
    var value = (hash >> (i * 8)) & 0xFF;
    colour += ('00' + value.toString(16)).substr(-2);
  }
  return colour;
}

用法:

stringToColour("greenish");
// -> #9bc63b

例子:

http://jsfiddle.net/sUK45/

(另一种/更简单的解决方案可能涉及返回'rgb(…)'风格的颜色代码。)

还有一个随机颜色的解决方案:

function colorize(str) {
    for (var i = 0, hash = 0; i < str.length; hash = str.charCodeAt(i++) + ((hash << 5) - hash));
    color = Math.floor(Math.abs((Math.sin(hash) * 10000) % 1 * 16777216)).toString(16);
    return '#' + Array(6 - color.length + 1).join('0') + color;
}

对我来说，这是一种混合的工作。 我使用了JFreeman散列函数(也是这个线程中的一个答案)和Asykäri伪随机函数，以及我自己的一些填充和数学。

我怀疑该函数产生均匀分布的颜色，尽管它看起来很好，并做了它应该做的事情。