TypeScript中基于承诺的递归解决方案，使用Array.flat()处理嵌套返回。

import { resolve } from 'path'
import { Dirent } from 'fs'
import * as fs from 'fs'

function getFiles(root: string): Promise<string[]> {
 return fs.promises
   .readdir(root, { withFileTypes: true })
   .then(dirents => {
      const mapToPath = (r: string) => (dirent: Dirent): string => resolve(r, dirent.name)
      const directoryPaths = dirents.filter(a => a.isDirectory()).map(mapToPath(root))
      const filePaths = dirents.filter(a => a.isFile()).map(mapToPath(root))

     return Promise.all<string>([
       ...directoryPaths.map(a => getFiles(a, include)).flat(),
       ...filePaths.map(a => Promise.resolve(a))
     ]).then(a => a.flat())
  })
}

简单，基于异步承诺

const fs = require('fs/promises');
const getDirRecursive = async (dir) => {
    try {
        const items = await fs.readdir(dir);
        let files = [];
        for (const item of items) {
            if ((await fs.lstat(`${dir}/${item}`)).isDirectory()) files = [...files, ...(await getDirRecursive(`${dir}/${item}`))];
            else files.push({file: item, path: `${dir}/${item}`, parents: dir.split("/")});
        }
        return files;
    } catch (e) {
        return e
    }
};

用法:await getDirRecursive("./public");

独立承诺实现

在这个例子中，我使用的是when.js承诺库。

var fs = require('fs')
, path = require('path')
, when = require('when')
, nodefn = require('when/node/function');

function walk (directory, includeDir) {
    var results = [];
    return when.map(nodefn.call(fs.readdir, directory), function(file) {
        file = path.join(directory, file);
        return nodefn.call(fs.stat, file).then(function(stat) {
            if (stat.isFile()) { return results.push(file); }
            if (includeDir) { results.push(file + path.sep); }
            return walk(file, includeDir).then(function(filesInDir) {
                results = results.concat(filesInDir);
            });
        });
    }).then(function() {
        return results;
    });
};

walk(__dirname).then(function(files) {
    console.log(files);
}).otherwise(function(error) {
    console.error(error.stack || error);
});

我包含了一个可选参数includeDir，如果设置为true，它将在文件列表中包含目录。

这是另一个实现。上述解决方案都没有任何限制，因此如果您的目录结构很大，它们都会崩溃并最终耗尽资源。

var async = require('async');
var fs = require('fs');
var resolve = require('path').resolve;

var scan = function(path, concurrency, callback) {
    var list = [];

    var walker = async.queue(function(path, callback) {
        fs.stat(path, function(err, stats) {
            if (err) {
                return callback(err);
            } else {
                if (stats.isDirectory()) {
                    fs.readdir(path, function(err, files) {
                        if (err) {
                            callback(err);
                        } else {
                            for (var i = 0; i < files.length; i++) {
                                walker.push(resolve(path, files[i]));
                            }
                            callback();
                        }
                    });
                } else {
                    list.push(path);
                    callback();
                }
            }
        });
    }, concurrency);

    walker.push(path);

    walker.drain = function() {
        callback(list);
    }
};

使用50的并发工作得非常好，并且几乎和小型目录结构的简单实现一样快。

TypeScript中基于承诺的递归解决方案，使用Array.flat()处理嵌套返回。

import { resolve } from 'path'
import { Dirent } from 'fs'
import * as fs from 'fs'

function getFiles(root: string): Promise<string[]> {
 return fs.promises
   .readdir(root, { withFileTypes: true })
   .then(dirents => {
      const mapToPath = (r: string) => (dirent: Dirent): string => resolve(r, dirent.name)
      const directoryPaths = dirents.filter(a => a.isDirectory()).map(mapToPath(root))
      const filePaths = dirents.filter(a => a.isFile()).map(mapToPath(root))

     return Promise.all<string>([
       ...directoryPaths.map(a => getFiles(a, include)).flat(),
       ...filePaths.map(a => Promise.resolve(a))
     ]).then(a => a.flat())
  })
}

用递归

var fs = require('fs')
var path = process.cwd()
var files = []

var getFiles = function(path, files){
    fs.readdirSync(path).forEach(function(file){
        var subpath = path + '/' + file;
        if(fs.lstatSync(subpath).isDirectory()){
            getFiles(subpath, files);
        } else {
            files.push(path + '/' + file);
        }
    });     
}

调用

getFiles(path, files)
console.log(files) // will log all files in directory