我不太熟悉来客模式。看看我做得对不对。假设你有一个动物等级

class Animal {  };
class Dog: public Animal {  };
class Cat: public Animal {  };

(假设它是一个具有良好接口的复杂层次结构。)

现在我们想要向层次结构添加一个新操作，即我们想要每个动物发出它的声音。既然层次结构这么简单，你可以直接用多态性来实现:

class Animal
{ public: virtual void makeSound() = 0; };

class Dog : public Animal
{ public: void makeSound(); };

void Dog::makeSound()
{ std::cout << "woof!\n"; }

class Cat : public Animal
{ public: void makeSound(); };

void Cat::makeSound()
{ std::cout << "meow!\n"; }

但是按照这种方式进行，每次想要添加操作时，都必须修改到层次结构中每个类的接口。现在，假设您对原始界面感到满意，并且希望对其进行尽可能少的修改。

访问者模式允许您在合适的类中移动每个新操作，并且您只需要扩展层次结构的接口一次。我们开始吧。首先，我们定义了一个抽象操作(GoF中的“Visitor”类)，它对层次结构中的每个类都有一个方法:

class Operation
{
public:
    virtual void hereIsADog(Dog *d) = 0;
    virtual void hereIsACat(Cat *c) = 0;
};

然后，我们修改层次结构以接受新的操作:

class Animal
{ public: virtual void letsDo(Operation *v) = 0; };

class Dog : public Animal
{ public: void letsDo(Operation *v); };

void Dog::letsDo(Operation *v)
{ v->hereIsADog(this); }

class Cat : public Animal
{ public: void letsDo(Operation *v); };

void Cat::letsDo(Operation *v)
{ v->hereIsACat(this); }

最后，我们实现了实际的操作，没有修改Cat和Dog:

class Sound : public Operation
{
public:
    void hereIsADog(Dog *d);
    void hereIsACat(Cat *c);
};

void Sound::hereIsADog(Dog *d)
{ std::cout << "woof!\n"; }

void Sound::hereIsACat(Cat *c)
{ std::cout << "meow!\n"; }

现在，您可以在不修改层次结构的情况下添加操作。 下面是它的工作原理:

int main()
{
    Cat c;
    Sound theSound;
    c.letsDo(&theSound);
}

基于@Federico A. Ramponi的精彩回答。

想象一下你有这样的层次结构:

public interface IAnimal
{
    void DoSound();
}

public class Dog : IAnimal
{
    public void DoSound()
    {
        Console.WriteLine("Woof");
    }
}

public class Cat : IAnimal
{
    public void DoSound(IOperation o)
    {
        Console.WriteLine("Meaw");
    }
}

如果你需要在这里添加一个“Walk”方法会发生什么?这对整个设计来说是痛苦的。

同时，添加“Walk”方法会生成新的问题。那"吃"和"睡"呢?我们真的必须为我们想要添加的每个新动作或操作添加一个新方法到Animal层次结构中吗?这很难看，但最重要的是，我们永远无法关闭Animal界面。因此，使用访问者模式，我们可以在不修改层次结构的情况下向层次结构添加新方法!

因此，只需检查并运行这个c#示例:

using System;
using System.Collections.Generic;

namespace VisitorPattern
{
    class Program
    {
        static void Main(string[] args)
        {
            var animals = new List<IAnimal>
            {
                new Cat(), new Cat(), new Dog(), new Cat(), 
                new Dog(), new Dog(), new Cat(), new Dog()
            };

            foreach (var animal in animals)
            {
                animal.DoOperation(new Walk());
                animal.DoOperation(new Sound());
            }

            Console.ReadLine();
        }
    }

    public interface IOperation
    {
        void PerformOperation(Dog dog);
        void PerformOperation(Cat cat);
    }

    public class Walk : IOperation
    {
        public void PerformOperation(Dog dog)
        {
            Console.WriteLine("Dog walking");
        }

        public void PerformOperation(Cat cat)
        {
            Console.WriteLine("Cat Walking");
        }
    }

    public class Sound : IOperation
    {
        public void PerformOperation(Dog dog)
        {
            Console.WriteLine("Woof");
        }

        public void PerformOperation(Cat cat)
        {
            Console.WriteLine("Meaw");
        }
    }

    public interface IAnimal
    {
        void DoOperation(IOperation o);
    }

    public class Dog : IAnimal
    {
        public void DoOperation(IOperation o)
        {
            o.PerformOperation(this);
        }
    }

    public class Cat : IAnimal
    {
        public void DoOperation(IOperation o)
        {
            o.PerformOperation(this);
        }
    }
}

Quick description of the visitor pattern. The classes that require modification must all implement the 'accept' method. Clients call this accept method to perform some new action on that family of classes thereby extending their functionality. Clients are able to use this one accept method to perform a wide range of new actions by passing in a different visitor class for each specific action. A visitor class contains multiple overridden visit methods defining how to achieve that same specific action for every class within the family. These visit methods get passed an instance on which to work.

当你考虑使用它的时候

When you have a family of classes you know your going to have to add many new actions them all, but for some reason you are not able to alter or recompile the family of classes in the future. When you want to add a new action and have that new action entirely defined within one the visitor class rather than spread out across multiple classes. When your boss says you must produce a range of classes which must do something right now!... but nobody actually knows exactly what that something is yet.

感谢@Federico A. Ramponi的精彩解释，我只是在java版本中做了这个。希望对大家有所帮助。

正如@Konrad Rudolph指出的那样，这实际上是使用两个具体实例一起确定运行时方法的双重分派。

因此，实际上，只要正确定义了操作接口，就不需要为操作执行器创建公共接口。

import static java.lang.System.out;
public class Visitor_2 {
    public static void main(String...args) {
        Hearen hearen = new Hearen();
        FoodImpl food = new FoodImpl();
        hearen.showTheHobby(food);
        Katherine katherine = new Katherine();
        katherine.presentHobby(food);
    }
}

interface Hobby {
    void insert(Hearen hearen);
    void embed(Katherine katherine);
}


class Hearen {
    String name = "Hearen";
    void showTheHobby(Hobby hobby) {
        hobby.insert(this);
    }
}

class Katherine {
    String name = "Katherine";
    void presentHobby(Hobby hobby) {
        hobby.embed(this);
    }
}

class FoodImpl implements Hobby {
    public void insert(Hearen hearen) {
        out.println(hearen.name + " start to eat bread");
    }
    public void embed(Katherine katherine) {
        out.println(katherine.name + " start to eat mango");
    }
}

正如您所期望的那样，公共接口将为我们带来更多的清晰度，尽管它实际上并不是这个模式的基本部分。

import static java.lang.System.out;
public class Visitor_2 {
    public static void main(String...args) {
        Hearen hearen = new Hearen();
        FoodImpl food = new FoodImpl();
        hearen.showHobby(food);
        Katherine katherine = new Katherine();
        katherine.showHobby(food);
    }
}

interface Hobby {
    void insert(Hearen hearen);
    void insert(Katherine katherine);
}

abstract class Person {
    String name;
    protected Person(String n) {
        this.name = n;
    }
    abstract void showHobby(Hobby hobby);
}

class Hearen extends  Person {
    public Hearen() {
        super("Hearen");
    }
    @Override
    void showHobby(Hobby hobby) {
        hobby.insert(this);
    }
}

class Katherine extends Person {
    public Katherine() {
        super("Katherine");
    }

    @Override
    void showHobby(Hobby hobby) {
        hobby.insert(this);
    }
}

class FoodImpl implements Hobby {
    public void insert(Hearen hearen) {
        out.println(hearen.name + " start to eat bread");
    }
    public void insert(Katherine katherine) {
        out.println(katherine.name + " start to eat mango");
    }
}

我不理解这种模式，直到我看到bob叔叔的文章和评论。 考虑下面的代码:

public class Employee
{
}

public class SalariedEmployee : Employee
{
}

public class HourlyEmployee : Employee
{
}

public class QtdHoursAndPayReport
{
    public void PrintReport()
    {
        var employees = new List<Employee>
        {
            new SalariedEmployee(),
            new HourlyEmployee()
        };
        foreach (Employee e in employees)
        {
            if (e is HourlyEmployee he)
                PrintReportLine(he);
            if (e is SalariedEmployee se)
                PrintReportLine(se);
        }
    }

    public void PrintReportLine(HourlyEmployee he)
    {
        System.Diagnostics.Debug.WriteLine("hours");
    }
    public void PrintReportLine(SalariedEmployee se)
    {
        System.Diagnostics.Debug.WriteLine("fix");
    }
}

class Program
{
    static void Main(string[] args)
    {
        new QtdHoursAndPayReport().PrintReport();
    }
}

虽然它看起来很好，因为它确认了单一责任，但它违反了开放/封闭原则。每次你有新的员工类型，你将不得不添加如果与类型检查。如果你不知道，在编译时你永远也不会知道。

使用访问者模式，你可以让你的代码更干净，因为它不违反开放/关闭原则，也不违反单一责任。如果你忘记实现visit，它将不会编译:

public abstract class Employee
{
    public abstract void Accept(EmployeeVisitor v);
}

public class SalariedEmployee : Employee
{
    public override void Accept(EmployeeVisitor v)
    {
        v.Visit(this);
    }
}

public class HourlyEmployee:Employee
{
    public override void Accept(EmployeeVisitor v)
    {
        v.Visit(this);
    }
}

public interface EmployeeVisitor
{
    void Visit(HourlyEmployee he);
    void Visit(SalariedEmployee se);
}

public class QtdHoursAndPayReport : EmployeeVisitor
{
    public void Visit(HourlyEmployee he)
    {
        System.Diagnostics.Debug.WriteLine("hourly");
        // generate the line of the report.
    }
    public void Visit(SalariedEmployee se)
    {
        System.Diagnostics.Debug.WriteLine("fix");
    } // do nothing

    public void PrintReport()
    {
        var employees = new List<Employee>
        {
            new SalariedEmployee(),
            new HourlyEmployee()
        };
        QtdHoursAndPayReport v = new QtdHoursAndPayReport();
        foreach (var emp in employees)
        {
            emp.Accept(v);
        }
    }
}

class Program
{

    public static void Main(string[] args)
    {
        new QtdHoursAndPayReport().PrintReport();
    }       
}  
}

神奇的是，虽然v.Visit(this)看起来一样，但实际上是不同的，因为它调用不同的访问者重载。

你的问题是什么时候知道:

我不首先编码访问者模式。我编写标准代码，等待需求的出现，然后重构。假设你有多个支付系统，一次安装一个。在签出时，你可以有很多if条件(或instanceOf)，例如:

//psuedo code
    if(payPal) 
    do paypal checkout 
    if(stripe)
    do strip stuff checkout
    if(payoneer)
    do payoneer checkout

现在假设我有10种支付方式，这有点难看。因此，当你看到这种模式发生时，访问者会很容易地将所有这些分离出来，然后你最终会调用这样的东西:

new PaymentCheckoutVistor(paymentType).visit()

你可以看到如何实现它从这里的例子的数量，我只是向你展示一个用例。