我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
sp_spaceused可以获取表、索引视图或整个数据库使用的磁盘空间的信息。
例如:
USE MyDatabase; GO
EXEC sp_spaceused N'User.ContactInfo'; GO
这将报告ContactInfo表的磁盘使用情况信息。
要同时对所有表使用此选项:
USE MyDatabase; GO
sp_msforeachtable 'EXEC sp_spaceused [?]' GO
您还可以从SQL Server的右键单击“标准报告”功能中获取磁盘使用情况。要获取此报告,请从对象资源管理器中的服务器对象导航,向下移动到数据库对象,然后右键单击任何数据库。从出现的菜单中,选择“报告”,然后选择“标准报告”,再选择“磁盘分区使用情况:[DatabaseName]”。
其他回答
如果需要精确计算SSMS中“表财产-存储”页面上的相同数字,则需要使用与SSMS中相同的方法进行计数(适用于sql server 2005及更高版本……也适用于具有LOB字段的表,因为仅计算“used_pages”不足以显示准确的索引大小):
;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END) as pages
FROM sys.dm_db_partition_stats AS s
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
cte.TableName,
cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB,
cast(((CASE WHEN cte.used_pages_count > cte.pages
THEN cte.used_pages_count - cte.pages
ELSE 0
END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc
下面是另一种方法:使用SQLServerManagementStudio,在对象资源管理器中,转到数据库并选择表
然后打开“对象浏览器详细信息”(按F7或转到“查看”->“对象浏览器详情”)。在对象资源管理器详细信息页面中,右键单击列标题并启用您希望在页面中看到的列。您也可以按任何列对数据进行排序。
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
作为marc_s答案(已被接受的答案)的一个简单扩展,它被调整为返回列计数并允许过滤:
SELECT *
FROM
(
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
(SUM(a.used_pages) * 8) AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
) AS Result
WHERE
RowCounts > 1000
AND ColumnCount > 10
ORDER BY
UsedSpaceKB DESC
我要感谢Greg Low先生的提问:
SELECT o.name AS ObjectName,
SUM(reserved_page_count) * 8.0 / 1024 AS SizeinMB
FROM sys.dm_db_partition_stats AS ps
INNER JOIN sys.sysobjects AS o
ON ps.object_id = o.id
GROUP BY o.name
ORDER BY SizeinMB DESC;