作为marc_s答案（已被接受的答案）的一个简单扩展，它被调整为返回列计数并允许过滤：

SELECT *
FROM
(

SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    (SUM(a.used_pages) * 8) AS UsedSpaceKB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
    INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY 
    t.Name, s.Name, p.Rows
) AS Result

WHERE
    RowCounts > 1000
    AND ColumnCount > 10
ORDER BY 
    UsedSpaceKB DESC

与Marc_s的回答有一点不同，因为我经常回到这一页，按大多数第一行排序：

SELECT
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB,
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
    sys.tables t
INNER JOIN
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
    sys.schemas s ON t.schema_id = s.schema_id
WHERE
    t.NAME NOT LIKE 'dt%'
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY
    t.Name, s.Name, p.Rows
ORDER BY
    --p.rows DESC --Uncomment to order by amount rows instead of size in KB.
    SUM(a.total_pages) DESC 

SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    TotalSpaceMB DESC, t.Name

对于Azure，我使用了：

您应该有SSMS v17.x+

我使用；

正如用户Sparrow所提到的：

打开数据库>并选择表，然后按F7键你应该看到行数作为：

此处的SSMS连接到Azure数据库

当处理多个分区和/或筛选索引时，Marc_s的答案给出了错误的结果。它也不区分数据和索引的大小，这通常是非常相关的。一些建议的修复方法并不能解决核心问题，或者根本就是错误的。

以下查询解决了所有这些问题。

SELECT 
     [object_id]        = t.[object_id]
    ,[schema_name]      = s.[name]
    ,[table_name]       = t.[name]
    ,[index_name]       = CASE WHEN i.[type] in (0,1,5) THEN null    ELSE i.[name] END -- 0=Heap; 1=Clustered; 5=Clustered Columnstore
    ,[object_type]      = CASE WHEN i.[type] in (0,1,5) THEN 'TABLE' ELSE 'INDEX'  END
    ,[index_type]       = i.[type_desc]
    ,[partition_count]  = p.partition_count
    ,[row_count]        = p.[rows]
    ,[data_compression] = CASE WHEN p.data_compression_cnt > 1 THEN 'Mixed'
                               ELSE (  SELECT DISTINCT p.data_compression_desc
                                       FROM sys.partitions p
                                       WHERE i.[object_id] = p.[object_id] AND i.index_id = p.index_id
                                    )
                          END
    ,[total_space_MB]   = cast(round(( au.total_pages                  * (8/1024.00)), 2) AS DECIMAL(36,2))
    ,[used_space_MB]    = cast(round(( au.used_pages                   * (8/1024.00)), 2) AS DECIMAL(36,2))
    ,[unused_space_MB]  = cast(round(((au.total_pages - au.used_pages) * (8/1024.00)), 2) AS DECIMAL(36,2))
FROM sys.schemas s
JOIN sys.tables  t ON s.schema_id = t.schema_id
JOIN sys.indexes i ON t.object_id = i.object_id
JOIN (
    SELECT [object_id], index_id, partition_count=count(*), [rows]=sum([rows]), data_compression_cnt=count(distinct [data_compression])
    FROM sys.partitions
    GROUP BY [object_id], [index_id]
) p ON i.[object_id] = p.[object_id] AND i.[index_id] = p.[index_id]
JOIN (
    SELECT p.[object_id], p.[index_id], total_pages = sum(a.total_pages), used_pages = sum(a.used_pages), data_pages=sum(a.data_pages)
    FROM sys.partitions p
    JOIN sys.allocation_units a ON p.[partition_id] = a.[container_id]
    GROUP BY p.[object_id], p.[index_id]
) au ON i.[object_id] = au.[object_id] AND i.[index_id] = au.[index_id]
WHERE t.is_ms_shipped = 0 -- Not a system table

我的文章只与SQL Server 2000相关，并且已经过测试，可以在我的环境中工作。

该代码访问单个实例的所有可能的数据库，而不仅仅是单个数据库。

我使用两个临时表来帮助收集适当的数据，然后将结果转储到一个“Live”表中。

返回的数据是：DatabaseName、DatabaseTableName、Rows（在表中）、data（表的大小，以KB为单位）、entry data（我发现这对了解我上次运行脚本的时间很有用）。

这段代码的缺点是“data”字段不是以int形式存储的（字符“KB”保留在该字段中），这对于排序是有用的（但不是完全必要的）。

希望这段代码能帮助一些人，并为他们节省一些时间！

CREATE PROCEDURE [dbo].[usp_getAllDBTableSizes]

AS
BEGIN
   SET NOCOUNT OFF

   CREATE TABLE #DatabaseTables([dbname] sysname,TableName sysname)
   CREATE TABLE #AllDatabaseTableSizes(Name sysname,[rows] VARCHAR(18), reserved VARCHAR(18), data VARCHAR(18), index_size VARCHAR(18), unused VARCHAR(18))

   DECLARE @SQL nvarchar(4000)
   SET @SQL='select ''?'' AS [Database], Table_Name from [?].information_schema.tables WHERE TABLE_TYPE = ''BASE TABLE'' '

   INSERT INTO #DatabaseTables(DbName, TableName)
      EXECUTE sp_msforeachdb @Command1=@SQL

   DECLARE AllDatabaseTables CURSOR LOCAL READ_ONLY FOR   
   SELECT TableName FROM #DatabaseTables

   DECLARE AllDatabaseNames CURSOR LOCAL READ_ONLY FOR   
   SELECT DBName FROM #DatabaseTables

   DECLARE @DBName sysname  
   OPEN AllDatabaseNames  

   DECLARE @TName sysname
   OPEN AllDatabaseTables  

   WHILE 1=1 BEGIN 
      FETCH NEXT FROM AllDatabaseNames INTO @DBName  
      FETCH NEXT FROM AllDatabaseTables INTO @TName 
      IF @@FETCH_STATUS<>0 BREAK  
      INSERT INTO #AllDatabaseTableSizes
         EXEC ( 'EXEC ' + @DBName + '.dbo.sp_spaceused ' + @TName) 

   END 

   --http://msdn.microsoft.com/en-us/library/aa175920(v=sql.80).aspx
   INSERT INTO rsp_DatabaseTableSizes (DatabaseName, name, [rows], data)
      SELECT   [dbname], name, [rows],  data FROM #DatabaseTables
      INNER JOIN #AllDatabaseTableSizes
      ON #DatabaseTables.TableName = #AllDatabaseTableSizes.Name
      GROUP BY [dbname] , name, [rows],  data
      ORDER BY [dbname]
   --To be honest, I have no idea what exact duplicates we are dropping
    -- but in my case a near enough approach has been good enough.
   DELETE FROM [rsp_DatabaseTableSizes]
   WHERE name IN 
      ( 
      SELECT name 
      FROM [rsp_DatabaseTableSizes]
      GROUP BY name
      HAVING COUNT(*) > 1
      )

   DROP TABLE #DatabaseTables
   DROP TABLE #AllDatabaseTableSizes

   CLOSE AllDatabaseTables  
   DEALLOCATE AllDatabaseTables  

   CLOSE AllDatabaseNames  
   DEALLOCATE AllDatabaseNames      
END

--EXEC [dbo].[usp_getAllDBTableSizes] 

如果您需要知道，rsp_DatabaseTableSizes表是通过以下方式创建的：

CREATE TABLE [dbo].[rsp_DatabaseSizes](
    [DatabaseName] [varchar](1000) NULL,
    [dbSize] [decimal](15, 2) NULL,
    [DateUpdated] [smalldatetime] NULL
) ON [PRIMARY]

GO