我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
从使用OSQL的命令提示符:
OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt
其他回答
作为marc_s答案(已被接受的答案)的一个简单扩展,它被调整为返回列计数并允许过滤:
SELECT *
FROM
(
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
(SUM(a.used_pages) * 8) AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
) AS Result
WHERE
RowCounts > 1000
AND ColumnCount > 10
ORDER BY
UsedSpaceKB DESC
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
在上面的@Mark回答中,添加了@updateusage='true'以强制更新最新的尺码统计(https://msdn.microsoft.com/en-us/library/ms188776.aspx):
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = 'exec sp_spaceused @objname =''?'', @updateusage =''true'' '
INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1
SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC
sp_spaceused可以获取表、索引视图或整个数据库使用的磁盘空间的信息。
例如:
USE MyDatabase; GO
EXEC sp_spaceused N'User.ContactInfo'; GO
这将报告ContactInfo表的磁盘使用情况信息。
要同时对所有表使用此选项:
USE MyDatabase; GO
sp_msforeachtable 'EXEC sp_spaceused [?]' GO
您还可以从SQL Server的右键单击“标准报告”功能中获取磁盘使用情况。要获取此报告,请从对象资源管理器中的服务器对象导航,向下移动到数据库对象,然后右键单击任何数据库。从出现的菜单中,选择“报告”,然后选择“标准报告”,再选择“磁盘分区使用情况:[DatabaseName]”。
我在marc_s答案的顶部添加了几列:
with fs
as
(
select i.object_id,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKb
from sys.indexes i INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
i.OBJECT_ID > 255
GROUP BY
i.object_id,
p.rows
)
SELECT
t.NAME AS TableName,
fs.RowCounts,
fs.TotalSpaceKb,
t.create_date,
t.modify_date,
( select COUNT(1)
from sys.columns c
where c.object_id = t.object_id ) TotalColumns
FROM
sys.tables t INNER JOIN
fs ON t.OBJECT_ID = fs.object_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
ORDER BY
t.Name