我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
我在marc_s答案的顶部添加了几列:
with fs
as
(
select i.object_id,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKb
from sys.indexes i INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
i.OBJECT_ID > 255
GROUP BY
i.object_id,
p.rows
)
SELECT
t.NAME AS TableName,
fs.RowCounts,
fs.TotalSpaceKb,
t.create_date,
t.modify_date,
( select COUNT(1)
from sys.columns c
where c.object_id = t.object_id ) TotalColumns
FROM
sys.tables t INNER JOIN
fs ON t.OBJECT_ID = fs.object_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
ORDER BY
t.Name
其他回答
也许表格有更多的分区文件,必须显示文件顺序
SELECT
T1.Name AS TableName,
T5.Name AS SchemaName,
T3.partition_number AS PartionNumber,
T3.Rows AS RowsCount,
SUM(T4.total_pages) * 8 AS TotalSpaceKB,
SUM(T4.used_pages) * 8 AS UsedSpaceKB,
(SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.objects T1 INNER JOIN
sys.indexes T2 ON T1.object_id = T2.object_id INNER JOIN
sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id INNER JOIN
sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
T1.type='U'
GROUP BY
T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
T1.Name,T3.partition_number;
从使用OSQL的命令提示符:
OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
对于Azure,我使用了:
您应该有SSMS v17.x+
我使用;
正如用户Sparrow所提到的:
打开数据库>并选择表,然后按F7键你应该看到行数作为:
此处的SSMS连接到Azure数据库
要获取一个数据库中的所有表大小,可以使用以下查询:
Exec sys.sp_MSforeachtable ' sp_spaceused "?" '
您可以将其更改为将所有结果插入临时表,然后从临时表中进行选择。
Insert into #TempTable Exec sys.sp_MSforeachtable ' sp_spaceused "?" '
Select * from #TempTable