我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。

是否有一种简单的方法来确定每个表占用的磁盘空间?


当前回答

如果您使用的是SQL Server Management Studio(SSMS),则可以运行标准报告,而不是运行查询(在我的情况下返回重复的行)

右键单击数据库导航到报告>标准报告>磁盘使用情况(按表)

注意:数据库兼容级别必须设置为90或更高,才能正常工作。看见http://msdn.microsoft.com/en-gb/library/bb510680.aspx

其他回答

我发现这个查询很容易使用和快速。

select schema_name(tab.schema_id) + '.' + tab.name as [table], 
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind 
    on tab.object_id = ind.object_id
inner join sys.partitions  (nolock) part 
    on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
    on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + '.' + tab.name
order by sum(spc.used_pages) desc
SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    TotalSpaceMB DESC, t.Name

从使用OSQL的命令提示符:

OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt

经过一番搜索,我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的方便存储过程,它将返回数据库使用的所有空间。如果提供了表名,则返回该表使用的空间。但是,存储过程返回的结果不可排序,因为列是字符值。

以下脚本将生成我要查找的信息。

create table #TableSize (
    Name varchar(255),
    [rows] int,
    reserved varchar(255),
    data varchar(255),
    index_size varchar(255),
    unused varchar(255))
create table #ConvertedSizes (
    Name varchar(255),
    [rows] int,
    reservedKb int,
    dataKb int,
    reservedIndexSize int,
    reservedUnused int)

EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows], 
SUBSTRING(reserved, 0, LEN(reserved)-2), 
SUBSTRING(data, 0, LEN(data)-2), 
SUBSTRING(index_size, 0, LEN(index_size)-2), 
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize

select * from #ConvertedSizes
order by reservedKb desc

drop table #TableSize
drop table #ConvertedSizes
 exec  sp_spaceused N'dbo.MyTable'

对于所有表,请使用。。(根据保罗的评论补充)

exec sp_MSForEachTable 'exec sp_spaceused [?]'