我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。

是否有一种简单的方法来确定每个表占用的磁盘空间?


当前回答

CREATE TABLE #tmp_table_info
(
id int identity(1,1),
tblname varchar(200)
);
CREATE TABLE #SpaceUsed 
(
     TableName sysname
    ,NumRows BIGINT
    ,ReservedSpace VARCHAR(50)
    ,DataSpace VARCHAR(50)
    ,IndexSize VARCHAR(50)
    ,UnusedSpace VARCHAR(50)
) 

insert into #tmp_table_info
select s.name+'.'+t.name 
from sys.tables t 
inner join sys.schemas s on t.schema_id = s.schema_id
where t.type = 'U';

declare @min int =1,@max int = 0
select @max = count(*)
from #tmp_table_info
while(@min<=@max)
begin
    declare @tablename varchar(200)
    select @tablename=tblname
    from #tmp_table_info
    where id =@min

    DECLARE @str VARCHAR(500)
    SET @str =  'sp_spaceused '''+@tablename+''''
    INSERT INTO #SpaceUsed 
    EXEC (@str)  
    set @min =@min + 1
end;
select @@SERVERNAME as servername,DB_NAME() as DatabaseName,CONVERT(numeric(18,0),REPLACE(ReservedSpace,' KB','')) / 1024 as ReservedSpace_MB,
CONVERT(numeric(18,0),REPLACE(DataSpace,' KB','')) / 1024 as DataSpace_MB,
CONVERT(numeric(18,0),REPLACE(IndexSize,' KB','')) / 1024 as IndexSpace_MB,
CONVERT(numeric(18,0),REPLACE(UnusedSpace,' KB','')) / 1024 as UnusedSpace_MB from #SpaceUsed
drop table #tmp_table_info
drop table #SpaceUsed

其他回答

CREATE TABLE #tmp_table_info
(
id int identity(1,1),
tblname varchar(200)
);
CREATE TABLE #SpaceUsed 
(
     TableName sysname
    ,NumRows BIGINT
    ,ReservedSpace VARCHAR(50)
    ,DataSpace VARCHAR(50)
    ,IndexSize VARCHAR(50)
    ,UnusedSpace VARCHAR(50)
) 

insert into #tmp_table_info
select s.name+'.'+t.name 
from sys.tables t 
inner join sys.schemas s on t.schema_id = s.schema_id
where t.type = 'U';

declare @min int =1,@max int = 0
select @max = count(*)
from #tmp_table_info
while(@min<=@max)
begin
    declare @tablename varchar(200)
    select @tablename=tblname
    from #tmp_table_info
    where id =@min

    DECLARE @str VARCHAR(500)
    SET @str =  'sp_spaceused '''+@tablename+''''
    INSERT INTO #SpaceUsed 
    EXEC (@str)  
    set @min =@min + 1
end;
select @@SERVERNAME as servername,DB_NAME() as DatabaseName,CONVERT(numeric(18,0),REPLACE(ReservedSpace,' KB','')) / 1024 as ReservedSpace_MB,
CONVERT(numeric(18,0),REPLACE(DataSpace,' KB','')) / 1024 as DataSpace_MB,
CONVERT(numeric(18,0),REPLACE(IndexSize,' KB','')) / 1024 as IndexSpace_MB,
CONVERT(numeric(18,0),REPLACE(UnusedSpace,' KB','')) / 1024 as UnusedSpace_MB from #SpaceUsed
drop table #tmp_table_info
drop table #SpaceUsed
SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    TotalSpaceMB DESC, t.Name

我要感谢Greg Low先生的提问:

SELECT o.name AS ObjectName, 
       SUM(reserved_page_count) * 8.0 / 1024 AS SizeinMB
FROM sys.dm_db_partition_stats AS ps
INNER JOIN sys.sysobjects AS o
ON ps.object_id = o.id
GROUP BY o.name
ORDER BY SizeinMB DESC;

以上查询有助于查找表(包括索引)使用的空间量,但如果要比较表上的索引使用了多少空间,请使用以下查询:

SELECT
    OBJECT_NAME(i.OBJECT_ID) AS TableName,
    i.name AS IndexName,
    i.index_id AS IndexID,
    8 * SUM(a.used_pages) AS 'Indexsize(KB)'
FROM
    sys.indexes AS i
    JOIN sys.partitions AS p ON p.OBJECT_ID = i.OBJECT_ID AND p.index_id = i.index_id
    JOIN sys.allocation_units AS a ON a.container_id = p.partition_id
WHERE
    i.is_primary_key = 0 -- fix for size discrepancy
GROUP BY
    i.OBJECT_ID,
    i.index_id,
    i.name
ORDER BY
    OBJECT_NAME(i.OBJECT_ID),
    i.index_id

从使用OSQL的命令提示符:

OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt