我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
CREATE TABLE #tmp_table_info
(
id int identity(1,1),
tblname varchar(200)
);
CREATE TABLE #SpaceUsed
(
TableName sysname
,NumRows BIGINT
,ReservedSpace VARCHAR(50)
,DataSpace VARCHAR(50)
,IndexSize VARCHAR(50)
,UnusedSpace VARCHAR(50)
)
insert into #tmp_table_info
select s.name+'.'+t.name
from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
where t.type = 'U';
declare @min int =1,@max int = 0
select @max = count(*)
from #tmp_table_info
while(@min<=@max)
begin
declare @tablename varchar(200)
select @tablename=tblname
from #tmp_table_info
where id =@min
DECLARE @str VARCHAR(500)
SET @str = 'sp_spaceused '''+@tablename+''''
INSERT INTO #SpaceUsed
EXEC (@str)
set @min =@min + 1
end;
select @@SERVERNAME as servername,DB_NAME() as DatabaseName,CONVERT(numeric(18,0),REPLACE(ReservedSpace,' KB','')) / 1024 as ReservedSpace_MB,
CONVERT(numeric(18,0),REPLACE(DataSpace,' KB','')) / 1024 as DataSpace_MB,
CONVERT(numeric(18,0),REPLACE(IndexSize,' KB','')) / 1024 as IndexSpace_MB,
CONVERT(numeric(18,0),REPLACE(UnusedSpace,' KB','')) / 1024 as UnusedSpace_MB from #SpaceUsed
drop table #tmp_table_info
drop table #SpaceUsed
其他回答
我发现这个查询很容易使用和快速。
select schema_name(tab.schema_id) + '.' + tab.name as [table],
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind
on tab.object_id = ind.object_id
inner join sys.partitions (nolock) part
on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + '.' + tab.name
order by sum(spc.used_pages) desc
也许表格有更多的分区文件,必须显示文件顺序
SELECT
T1.Name AS TableName,
T5.Name AS SchemaName,
T3.partition_number AS PartionNumber,
T3.Rows AS RowsCount,
SUM(T4.total_pages) * 8 AS TotalSpaceKB,
SUM(T4.used_pages) * 8 AS UsedSpaceKB,
(SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.objects T1 INNER JOIN
sys.indexes T2 ON T1.object_id = T2.object_id INNER JOIN
sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id INNER JOIN
sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
T1.type='U'
GROUP BY
T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
T1.Name,T3.partition_number;
下面是一个示例查询,用于获取按大小降序排列的大于1GB的表。
USE YourDB
GO
DECLARE @Mult float = 8
SET @Mult = @Mult / POWER(2, 20) -- Use POWER(2, 10) for MBs
; WITH CTE AS
(
SELECT
i.object_id,
Rows = MAX(p.rows),
TotalSpaceGB = ROUND(SUM(a.total_pages) * @Mult, 0),
UsedSpaceGB = ROUND(SUM(a.used_pages) * @Mult, 0)
FROM
sys.indexes i
JOIN
sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
i.object_id > 255
GROUP BY
i.object_id
HAVING
SUM(a.total_pages) * @Mult > 1
)
SELECT
SchemaName = s.name,
TableName = t.name,
c.TotalSpaceGB,
c.UsedSpaceGB,
UnusedSpaceGB = c.TotalSpaceGB - c.UsedSpaceGB,
[RowCount] = c.Rows
FROM
CTE c
JOIN
sys.tables t ON t.object_id = c.object_id
JOIN
sys.schemas s ON t.schema_id = s.schema_id
ORDER BY
c.TotalSpaceGB DESC
对于Azure,我使用了:
您应该有SSMS v17.x+
我使用;
正如用户Sparrow所提到的:
打开数据库>并选择表,然后按F7键你应该看到行数作为:
此处的SSMS连接到Azure数据库
以下是通过以下步骤快速获取所有表格大小的方法:
编写给定的T-SQL命令以列出所有数据库表:从INFORMATION_SCHEMA.TABLES中选择“exec sp_spaceused”+TABLE_NAME,其中TABLE_TYPE=“BASE TABLE”现在复制数据库表列表,并将其复制到新的查询分析器窗口中执行sp_spaceused表1执行sp_spaceused表2执行sp_spaceused表3执行sp_spaceused表4执行sp_spaceused表5在SQL查询分析器中,从顶部工具栏中选择“结果到文件”选项(Ctrl+Shift+F)。现在,最后点击上面工具栏中标记为红色的Execute按钮。所有表的数据库大小现在存储在计算机上的文件中。