我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
-- Show the size of all the tables in a database sort by data size descending
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = 'exec sp_spaceused ''?'''
INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1
SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC
其他回答
也许表格有更多的分区文件,必须显示文件顺序
SELECT
T1.Name AS TableName,
T5.Name AS SchemaName,
T3.partition_number AS PartionNumber,
T3.Rows AS RowsCount,
SUM(T4.total_pages) * 8 AS TotalSpaceKB,
SUM(T4.used_pages) * 8 AS UsedSpaceKB,
(SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.objects T1 INNER JOIN
sys.indexes T2 ON T1.object_id = T2.object_id INNER JOIN
sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id INNER JOIN
sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
T1.type='U'
GROUP BY
T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
T1.Name,T3.partition_number;
经过一番搜索,我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的方便存储过程,它将返回数据库使用的所有空间。如果提供了表名,则返回该表使用的空间。但是,存储过程返回的结果不可排序,因为列是字符值。
以下脚本将生成我要查找的信息。
create table #TableSize (
Name varchar(255),
[rows] int,
reserved varchar(255),
data varchar(255),
index_size varchar(255),
unused varchar(255))
create table #ConvertedSizes (
Name varchar(255),
[rows] int,
reservedKb int,
dataKb int,
reservedIndexSize int,
reservedUnused int)
EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows],
SUBSTRING(reserved, 0, LEN(reserved)-2),
SUBSTRING(data, 0, LEN(data)-2),
SUBSTRING(index_size, 0, LEN(index_size)-2),
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize
select * from #ConvertedSizes
order by reservedKb desc
drop table #TableSize
drop table #ConvertedSizes
在上面的@Mark回答中,添加了@updateusage='true'以强制更新最新的尺码统计(https://msdn.microsoft.com/en-us/library/ms188776.aspx):
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = 'exec sp_spaceused @objname =''?'', @updateusage =''true'' '
INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1
SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC
如果您使用的是SQL Server Management Studio(SSMS),则可以运行标准报告,而不是运行查询(在我的情况下返回重复的行)
右键单击数据库导航到报告>标准报告>磁盘使用情况(按表)
注意:数据库兼容级别必须设置为90或更高,才能正常工作。看见http://msdn.microsoft.com/en-gb/library/bb510680.aspx
如果需要精确计算SSMS中“表财产-存储”页面上的相同数字,则需要使用与SSMS中相同的方法进行计数(适用于sql server 2005及更高版本……也适用于具有LOB字段的表,因为仅计算“used_pages”不足以显示准确的索引大小):
;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END) as pages
FROM sys.dm_db_partition_stats AS s
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
cte.TableName,
cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB,
cast(((CASE WHEN cte.used_pages_count > cte.pages
THEN cte.used_pages_count - cte.pages
ELSE 0
END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc