我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。

是否有一种简单的方法来确定每个表占用的磁盘空间?


当前回答

-- Show the size of all the tables in a database sort by data size descending
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = 'exec sp_spaceused ''?'''

INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1

SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC

其他回答

如果您使用的是SQL Server Management Studio(SSMS),则可以运行标准报告,而不是运行查询(在我的情况下返回重复的行)

右键单击数据库导航到报告>标准报告>磁盘使用情况(按表)

注意:数据库兼容级别必须设置为90或更高,才能正常工作。看见http://msdn.microsoft.com/en-gb/library/bb510680.aspx

也许表格有更多的分区文件,必须显示文件顺序

SELECT
  T1.Name                                       AS TableName,
  T5.Name                                       AS SchemaName,
  T3.partition_number                           AS PartionNumber,   
  T3.Rows                                       AS RowsCount,
  SUM(T4.total_pages) * 8                       AS TotalSpaceKB,
  SUM(T4.used_pages) * 8                        AS UsedSpaceKB,
  (SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
  sys.objects T1  INNER JOIN 
  sys.indexes T2 ON T1.object_id = T2.object_id  INNER JOIN 
  sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id  INNER JOIN
  sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
  sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
  T1.type='U'
GROUP BY
  T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
  T1.Name,T3.partition_number;
SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    TotalSpaceMB DESC, t.Name

我们使用表分区,由于重复记录,上面提供的查询有一些问题。

对于需要此功能的人,您可以在下面找到SQL Server 2014在生成“磁盘使用情况(按表)”报告时运行的查询。我假设它也适用于以前版本的SQL Server。

它就像一个符咒。

SELECT
    a2.name AS [tablename],
    a1.rows as row_count,
    (a1.reserved + ISNULL(a4.reserved,0))* 8 AS reserved, 
    a1.data * 8 AS data,
    (CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 AS index_size,
    (CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 AS unused
FROM
    (SELECT 
        ps.object_id,
        SUM (
            CASE
                WHEN (ps.index_id < 2) THEN row_count
                ELSE 0
            END
            ) AS [rows],
        SUM (ps.reserved_page_count) AS reserved,
        SUM (
            CASE
                WHEN (ps.index_id < 2) THEN (ps.in_row_data_page_count + ps.lob_used_page_count + ps.row_overflow_used_page_count)
                ELSE (ps.lob_used_page_count + ps.row_overflow_used_page_count)
            END
            ) AS data,
        SUM (ps.used_page_count) AS used
    FROM sys.dm_db_partition_stats ps
        WHERE ps.object_id NOT IN (SELECT object_id FROM sys.tables WHERE is_memory_optimized = 1)
    GROUP BY ps.object_id) AS a1
LEFT OUTER JOIN 
    (SELECT 
        it.parent_id,
        SUM(ps.reserved_page_count) AS reserved,
        SUM(ps.used_page_count) AS used
     FROM sys.dm_db_partition_stats ps
     INNER JOIN sys.internal_tables it ON (it.object_id = ps.object_id)
     WHERE it.internal_type IN (202,204)
     GROUP BY it.parent_id) AS a4 ON (a4.parent_id = a1.object_id)
INNER JOIN sys.all_objects a2  ON ( a1.object_id = a2.object_id ) 
INNER JOIN sys.schemas a3 ON (a2.schema_id = a3.schema_id)
WHERE a2.type <> N'S' and a2.type <> N'IT'
ORDER BY a3.name, a2.name

与Marc_s的回答有一点不同,因为我经常回到这一页,按大多数第一行排序:

SELECT
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB,
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
    sys.tables t
INNER JOIN
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
    sys.schemas s ON t.schema_id = s.schema_id
WHERE
    t.NAME NOT LIKE 'dt%'
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY
    t.Name, s.Name, p.Rows
ORDER BY
    --p.rows DESC --Uncomment to order by amount rows instead of size in KB.
    SUM(a.total_pages) DESC