我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。

是否有一种简单的方法来确定每个表占用的磁盘空间?


当前回答

如果需要精确计算SSMS中“表财产-存储”页面上的相同数字,则需要使用与SSMS中相同的方法进行计数(适用于sql server 2005及更高版本……也适用于具有LOB字段的表,因为仅计算“used_pages”不足以显示准确的索引大小):

;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
            WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
            ELSE lob_used_page_count + row_overflow_used_page_count
        END) as pages
FROM sys.dm_db_partition_stats  AS s 
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
    cte.TableName, 
    cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB, 
    cast(((CASE WHEN cte.used_pages_count > cte.pages 
                THEN cte.used_pages_count - cte.pages
                ELSE 0 
          END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc

其他回答

我的文章只与SQL Server 2000相关,并且已经过测试,可以在我的环境中工作。

该代码访问单个实例的所有可能的数据库,而不仅仅是单个数据库。

我使用两个临时表来帮助收集适当的数据,然后将结果转储到一个“Live”表中。

返回的数据是:DatabaseName、DatabaseTableName、Rows(在表中)、data(表的大小,以KB为单位)、entry data(我发现这对了解我上次运行脚本的时间很有用)。

这段代码的缺点是“data”字段不是以int形式存储的(字符“KB”保留在该字段中),这对于排序是有用的(但不是完全必要的)。

希望这段代码能帮助一些人,并为他们节省一些时间!

CREATE PROCEDURE [dbo].[usp_getAllDBTableSizes]

AS
BEGIN
   SET NOCOUNT OFF

   CREATE TABLE #DatabaseTables([dbname] sysname,TableName sysname)
   CREATE TABLE #AllDatabaseTableSizes(Name sysname,[rows] VARCHAR(18), reserved VARCHAR(18), data VARCHAR(18), index_size VARCHAR(18), unused VARCHAR(18))

   DECLARE @SQL nvarchar(4000)
   SET @SQL='select ''?'' AS [Database], Table_Name from [?].information_schema.tables WHERE TABLE_TYPE = ''BASE TABLE'' '

   INSERT INTO #DatabaseTables(DbName, TableName)
      EXECUTE sp_msforeachdb @Command1=@SQL

   DECLARE AllDatabaseTables CURSOR LOCAL READ_ONLY FOR   
   SELECT TableName FROM #DatabaseTables

   DECLARE AllDatabaseNames CURSOR LOCAL READ_ONLY FOR   
   SELECT DBName FROM #DatabaseTables

   DECLARE @DBName sysname  
   OPEN AllDatabaseNames  

   DECLARE @TName sysname
   OPEN AllDatabaseTables  

   WHILE 1=1 BEGIN 
      FETCH NEXT FROM AllDatabaseNames INTO @DBName  
      FETCH NEXT FROM AllDatabaseTables INTO @TName 
      IF @@FETCH_STATUS<>0 BREAK  
      INSERT INTO #AllDatabaseTableSizes
         EXEC ( 'EXEC ' + @DBName + '.dbo.sp_spaceused ' + @TName) 

   END 

   --http://msdn.microsoft.com/en-us/library/aa175920(v=sql.80).aspx
   INSERT INTO rsp_DatabaseTableSizes (DatabaseName, name, [rows], data)
      SELECT   [dbname], name, [rows],  data FROM #DatabaseTables
      INNER JOIN #AllDatabaseTableSizes
      ON #DatabaseTables.TableName = #AllDatabaseTableSizes.Name
      GROUP BY [dbname] , name, [rows],  data
      ORDER BY [dbname]
   --To be honest, I have no idea what exact duplicates we are dropping
    -- but in my case a near enough approach has been good enough.
   DELETE FROM [rsp_DatabaseTableSizes]
   WHERE name IN 
      ( 
      SELECT name 
      FROM [rsp_DatabaseTableSizes]
      GROUP BY name
      HAVING COUNT(*) > 1
      )

   DROP TABLE #DatabaseTables
   DROP TABLE #AllDatabaseTableSizes

   CLOSE AllDatabaseTables  
   DEALLOCATE AllDatabaseTables  

   CLOSE AllDatabaseNames  
   DEALLOCATE AllDatabaseNames      
END

--EXEC [dbo].[usp_getAllDBTableSizes] 

如果您需要知道,rsp_DatabaseTableSizes表是通过以下方式创建的:

CREATE TABLE [dbo].[rsp_DatabaseSizes](
    [DatabaseName] [varchar](1000) NULL,
    [dbSize] [decimal](15, 2) NULL,
    [DateUpdated] [smalldatetime] NULL
) ON [PRIMARY]

GO

如果需要精确计算SSMS中“表财产-存储”页面上的相同数字,则需要使用与SSMS中相同的方法进行计数(适用于sql server 2005及更高版本……也适用于具有LOB字段的表,因为仅计算“used_pages”不足以显示准确的索引大小):

;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
            WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
            ELSE lob_used_page_count + row_overflow_used_page_count
        END) as pages
FROM sys.dm_db_partition_stats  AS s 
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
    cte.TableName, 
    cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB, 
    cast(((CASE WHEN cte.used_pages_count > cte.pages 
                THEN cte.used_pages_count - cte.pages
                ELSE 0 
          END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc

下面是一个示例查询,用于获取按大小降序排列的大于1GB的表。

USE YourDB
GO

DECLARE @Mult float = 8
SET @Mult = @Mult / POWER(2, 20) -- Use POWER(2, 10) for MBs

; WITH CTE AS
(
SELECT
    i.object_id,
    Rows = MAX(p.rows),
    TotalSpaceGB = ROUND(SUM(a.total_pages) * @Mult, 0),
    UsedSpaceGB = ROUND(SUM(a.used_pages) * @Mult, 0)
FROM 
    sys.indexes i
JOIN
    sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
WHERE
    i.object_id > 255
GROUP BY
    i.object_id
HAVING
    SUM(a.total_pages) * @Mult > 1
)
SELECT 
    SchemaName = s.name,
    TableName = t.name,
    c.TotalSpaceGB,
    c.UsedSpaceGB,
    UnusedSpaceGB = c.TotalSpaceGB - c.UsedSpaceGB,
    [RowCount] = c.Rows
FROM 
    CTE c
JOIN    
    sys.tables t ON t.object_id = c.object_id
JOIN
    sys.schemas s ON t.schema_id = s.schema_id
ORDER BY
    c.TotalSpaceGB DESC

与Marc_s的回答有一点不同,因为我经常回到这一页,按大多数第一行排序:

SELECT
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB,
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
    sys.tables t
INNER JOIN
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
    sys.schemas s ON t.schema_id = s.schema_id
WHERE
    t.NAME NOT LIKE 'dt%'
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY
    t.Name, s.Name, p.Rows
ORDER BY
    --p.rows DESC --Uncomment to order by amount rows instead of size in KB.
    SUM(a.total_pages) DESC 
SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    TotalSpaceMB DESC, t.Name