我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。

是否有一种简单的方法来确定每个表占用的磁盘空间?


当前回答

对于Azure,我使用了:

您应该有SSMS v17.x+

我使用;

正如用户Sparrow所提到的:

打开数据库>并选择表,然后按F7键你应该看到行数作为:

此处的SSMS连接到Azure数据库

其他回答

作为marc_s答案(已被接受的答案)的一个简单扩展,它被调整为返回列计数并允许过滤:

SELECT *
FROM
(

SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    (SUM(a.used_pages) * 8) AS UsedSpaceKB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
    INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY 
    t.Name, s.Name, p.Rows
) AS Result

WHERE
    RowCounts > 1000
    AND ColumnCount > 10
ORDER BY 
    UsedSpaceKB DESC

也许表格有更多的分区文件,必须显示文件顺序

SELECT
  T1.Name                                       AS TableName,
  T5.Name                                       AS SchemaName,
  T3.partition_number                           AS PartionNumber,   
  T3.Rows                                       AS RowsCount,
  SUM(T4.total_pages) * 8                       AS TotalSpaceKB,
  SUM(T4.used_pages) * 8                        AS UsedSpaceKB,
  (SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
  sys.objects T1  INNER JOIN 
  sys.indexes T2 ON T1.object_id = T2.object_id  INNER JOIN 
  sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id  INNER JOIN
  sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
  sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
  T1.type='U'
GROUP BY
  T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
  T1.Name,T3.partition_number;

与Marc_s的回答有一点不同,因为我经常回到这一页,按大多数第一行排序:

SELECT
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB,
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
    sys.tables t
INNER JOIN
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
    sys.schemas s ON t.schema_id = s.schema_id
WHERE
    t.NAME NOT LIKE 'dt%'
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY
    t.Name, s.Name, p.Rows
ORDER BY
    --p.rows DESC --Uncomment to order by amount rows instead of size in KB.
    SUM(a.total_pages) DESC 

如果需要精确计算SSMS中“表财产-存储”页面上的相同数字,则需要使用与SSMS中相同的方法进行计数(适用于sql server 2005及更高版本……也适用于具有LOB字段的表,因为仅计算“used_pages”不足以显示准确的索引大小):

;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
            WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
            ELSE lob_used_page_count + row_overflow_used_page_count
        END) as pages
FROM sys.dm_db_partition_stats  AS s 
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
    cte.TableName, 
    cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB, 
    cast(((CASE WHEN cte.used_pages_count > cte.pages 
                THEN cte.used_pages_count - cte.pages
                ELSE 0 
          END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc

下面是一个示例查询,用于获取按大小降序排列的大于1GB的表。

USE YourDB
GO

DECLARE @Mult float = 8
SET @Mult = @Mult / POWER(2, 20) -- Use POWER(2, 10) for MBs

; WITH CTE AS
(
SELECT
    i.object_id,
    Rows = MAX(p.rows),
    TotalSpaceGB = ROUND(SUM(a.total_pages) * @Mult, 0),
    UsedSpaceGB = ROUND(SUM(a.used_pages) * @Mult, 0)
FROM 
    sys.indexes i
JOIN
    sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
WHERE
    i.object_id > 255
GROUP BY
    i.object_id
HAVING
    SUM(a.total_pages) * @Mult > 1
)
SELECT 
    SchemaName = s.name,
    TableName = t.name,
    c.TotalSpaceGB,
    c.UsedSpaceGB,
    UnusedSpaceGB = c.TotalSpaceGB - c.UsedSpaceGB,
    [RowCount] = c.Rows
FROM 
    CTE c
JOIN    
    sys.tables t ON t.object_id = c.object_id
JOIN
    sys.schemas s ON t.schema_id = s.schema_id
ORDER BY
    c.TotalSpaceGB DESC