当处理多个分区和/或筛选索引时，Marc_s的答案给出了错误的结果。它也不区分数据和索引的大小，这通常是非常相关的。一些建议的修复方法并不能解决核心问题，或者根本就是错误的。

以下查询解决了所有这些问题。

SELECT 
     [object_id]        = t.[object_id]
    ,[schema_name]      = s.[name]
    ,[table_name]       = t.[name]
    ,[index_name]       = CASE WHEN i.[type] in (0,1,5) THEN null    ELSE i.[name] END -- 0=Heap; 1=Clustered; 5=Clustered Columnstore
    ,[object_type]      = CASE WHEN i.[type] in (0,1,5) THEN 'TABLE' ELSE 'INDEX'  END
    ,[index_type]       = i.[type_desc]
    ,[partition_count]  = p.partition_count
    ,[row_count]        = p.[rows]
    ,[data_compression] = CASE WHEN p.data_compression_cnt > 1 THEN 'Mixed'
                               ELSE (  SELECT DISTINCT p.data_compression_desc
                                       FROM sys.partitions p
                                       WHERE i.[object_id] = p.[object_id] AND i.index_id = p.index_id
                                    )
                          END
    ,[total_space_MB]   = cast(round(( au.total_pages                  * (8/1024.00)), 2) AS DECIMAL(36,2))
    ,[used_space_MB]    = cast(round(( au.used_pages                   * (8/1024.00)), 2) AS DECIMAL(36,2))
    ,[unused_space_MB]  = cast(round(((au.total_pages - au.used_pages) * (8/1024.00)), 2) AS DECIMAL(36,2))
FROM sys.schemas s
JOIN sys.tables  t ON s.schema_id = t.schema_id
JOIN sys.indexes i ON t.object_id = i.object_id
JOIN (
    SELECT [object_id], index_id, partition_count=count(*), [rows]=sum([rows]), data_compression_cnt=count(distinct [data_compression])
    FROM sys.partitions
    GROUP BY [object_id], [index_id]
) p ON i.[object_id] = p.[object_id] AND i.[index_id] = p.[index_id]
JOIN (
    SELECT p.[object_id], p.[index_id], total_pages = sum(a.total_pages), used_pages = sum(a.used_pages), data_pages=sum(a.data_pages)
    FROM sys.partitions p
    JOIN sys.allocation_units a ON p.[partition_id] = a.[container_id]
    GROUP BY p.[object_id], p.[index_id]
) au ON i.[object_id] = au.[object_id] AND i.[index_id] = au.[index_id]
WHERE t.is_ms_shipped = 0 -- Not a system table

-- Show the size of all the tables in a database sort by data size descending
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = 'exec sp_spaceused ''?'''

INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1

SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC

如果您只关心数据库中的空浪费空间，而不关心单个表，则可以考虑以下问题：

如果数据库经历了大量的数据插入和删除，可能与ETL情况类似，这将导致数据库中有太多未使用的空间，因为文件组会自动增长，但不会自动收缩。

您可以通过使用数据库的财产页面来查看是否是这种情况。您可以收缩（右键单击数据库>任务>收缩）并收回一些空间。但是，如果根本原因仍然存在，则数据库将增长（并花费额外的时间尝试增长，直到增长到足够的速度，所以不要这样做）

对于Azure，我使用了：

您应该有SSMS v17.x+

我使用；

正如用户Sparrow所提到的：

打开数据库>并选择表，然后按F7键你应该看到行数作为：

此处的SSMS连接到Azure数据库

这将为您提供每个表的大小和记录计数。

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
-- Get a list of tables and their sizes on disk
ALTER PROCEDURE [dbo].[sp_Table_Sizes]
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;
DECLARE @table_name VARCHAR(500)  
DECLARE @schema_name VARCHAR(500)  
DECLARE @tab1 TABLE( 
        tablename VARCHAR (500) collate database_default 
       ,schemaname VARCHAR(500) collate database_default 
) 

CREATE TABLE #temp_Table ( 
        tablename sysname 
       ,row_count INT 
       ,reserved VARCHAR(50) collate database_default 
       ,data VARCHAR(50) collate database_default 
       ,index_size VARCHAR(50) collate database_default 
       ,unused VARCHAR(50) collate database_default  
) 

INSERT INTO @tab1  
SELECT Table_Name, Table_Schema  
FROM information_schema.tables  
WHERE TABLE_TYPE = 'BASE TABLE' 

DECLARE c1 CURSOR FOR 
SELECT Table_Schema + '.' + Table_Name   
FROM information_schema.tables t1  
WHERE TABLE_TYPE = 'BASE TABLE' 

OPEN c1 
FETCH NEXT FROM c1 INTO @table_name 
WHILE @@FETCH_STATUS = 0  
BEGIN   
        SET @table_name = REPLACE(@table_name, '[','');  
        SET @table_name = REPLACE(@table_name, ']','');  

        -- make sure the object exists before calling sp_spacedused 
        IF EXISTS(SELECT id FROM sysobjects WHERE id = OBJECT_ID(@table_name)) 
        BEGIN 
               INSERT INTO #temp_Table EXEC sp_spaceused @table_name, false; 
        END 

        FETCH NEXT FROM c1 INTO @table_name 
END 
CLOSE c1 
DEALLOCATE c1 

SELECT  t1.* 
       ,t2.schemaname  
FROM #temp_Table t1  
INNER JOIN @tab1 t2 ON (t1.tablename = t2.tablename ) 
ORDER BY schemaname,t1.tablename; 

DROP TABLE #temp_Table
END

经过一番搜索，我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的方便存储过程，它将返回数据库使用的所有空间。如果提供了表名，则返回该表使用的空间。但是，存储过程返回的结果不可排序，因为列是字符值。

以下脚本将生成我要查找的信息。

create table #TableSize (
    Name varchar(255),
    [rows] int,
    reserved varchar(255),
    data varchar(255),
    index_size varchar(255),
    unused varchar(255))
create table #ConvertedSizes (
    Name varchar(255),
    [rows] int,
    reservedKb int,
    dataKb int,
    reservedIndexSize int,
    reservedUnused int)

EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows], 
SUBSTRING(reserved, 0, LEN(reserved)-2), 
SUBSTRING(data, 0, LEN(data)-2), 
SUBSTRING(index_size, 0, LEN(index_size)-2), 
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize

select * from #ConvertedSizes
order by reservedKb desc

drop table #TableSize
drop table #ConvertedSizes