我要感谢Greg Low先生的提问：

SELECT o.name AS ObjectName, 
       SUM(reserved_page_count) * 8.0 / 1024 AS SizeinMB
FROM sys.dm_db_partition_stats AS ps
INNER JOIN sys.sysobjects AS o
ON ps.object_id = o.id
GROUP BY o.name
ORDER BY SizeinMB DESC;

CREATE TABLE #tmp_table_info
(
id int identity(1,1),
tblname varchar(200)
);
CREATE TABLE #SpaceUsed 
(
     TableName sysname
    ,NumRows BIGINT
    ,ReservedSpace VARCHAR(50)
    ,DataSpace VARCHAR(50)
    ,IndexSize VARCHAR(50)
    ,UnusedSpace VARCHAR(50)
) 

insert into #tmp_table_info
select s.name+'.'+t.name 
from sys.tables t 
inner join sys.schemas s on t.schema_id = s.schema_id
where t.type = 'U';

declare @min int =1,@max int = 0
select @max = count(*)
from #tmp_table_info
while(@min<=@max)
begin
    declare @tablename varchar(200)
    select @tablename=tblname
    from #tmp_table_info
    where id =@min

    DECLARE @str VARCHAR(500)
    SET @str =  'sp_spaceused '''+@tablename+''''
    INSERT INTO #SpaceUsed 
    EXEC (@str)  
    set @min =@min + 1
end;
select @@SERVERNAME as servername,DB_NAME() as DatabaseName,CONVERT(numeric(18,0),REPLACE(ReservedSpace,' KB','')) / 1024 as ReservedSpace_MB,
CONVERT(numeric(18,0),REPLACE(DataSpace,' KB','')) / 1024 as DataSpace_MB,
CONVERT(numeric(18,0),REPLACE(IndexSize,' KB','')) / 1024 as IndexSpace_MB,
CONVERT(numeric(18,0),REPLACE(UnusedSpace,' KB','')) / 1024 as UnusedSpace_MB from #SpaceUsed
drop table #tmp_table_info
drop table #SpaceUsed

与Marc_s的回答有一点不同，因为我经常回到这一页，按大多数第一行排序：

SELECT
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB,
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
    sys.tables t
INNER JOIN
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
    sys.schemas s ON t.schema_id = s.schema_id
WHERE
    t.NAME NOT LIKE 'dt%'
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY
    t.Name, s.Name, p.Rows
ORDER BY
    --p.rows DESC --Uncomment to order by amount rows instead of size in KB.
    SUM(a.total_pages) DESC 

经过一番搜索，我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的方便存储过程，它将返回数据库使用的所有空间。如果提供了表名，则返回该表使用的空间。但是，存储过程返回的结果不可排序，因为列是字符值。

以下脚本将生成我要查找的信息。

create table #TableSize (
    Name varchar(255),
    [rows] int,
    reserved varchar(255),
    data varchar(255),
    index_size varchar(255),
    unused varchar(255))
create table #ConvertedSizes (
    Name varchar(255),
    [rows] int,
    reservedKb int,
    dataKb int,
    reservedIndexSize int,
    reservedUnused int)

EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows], 
SUBSTRING(reserved, 0, LEN(reserved)-2), 
SUBSTRING(data, 0, LEN(data)-2), 
SUBSTRING(index_size, 0, LEN(index_size)-2), 
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize

select * from #ConvertedSizes
order by reservedKb desc

drop table #TableSize
drop table #ConvertedSizes

如果您使用的是SQL Server Management Studio（SSMS），则可以运行标准报告，而不是运行查询（在我的情况下返回重复的行）

右键单击数据库导航到报告>标准报告>磁盘使用情况（按表）

注意：数据库兼容级别必须设置为90或更高，才能正常工作。看见http://msdn.microsoft.com/en-gb/library/bb510680.aspx

我发现这个查询很容易使用和快速。

select schema_name(tab.schema_id) + '.' + tab.name as [table], 
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind 
    on tab.object_id = ind.object_id
inner join sys.partitions  (nolock) part 
    on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
    on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + '.' + tab.name
order by sum(spc.used_pages) desc