我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
以下是通过以下步骤快速获取所有表格大小的方法:
编写给定的T-SQL命令以列出所有数据库表:从INFORMATION_SCHEMA.TABLES中选择“exec sp_spaceused”+TABLE_NAME,其中TABLE_TYPE=“BASE TABLE”现在复制数据库表列表,并将其复制到新的查询分析器窗口中执行sp_spaceused表1执行sp_spaceused表2执行sp_spaceused表3执行sp_spaceused表4执行sp_spaceused表5在SQL查询分析器中,从顶部工具栏中选择“结果到文件”选项(Ctrl+Shift+F)。现在,最后点击上面工具栏中标记为红色的Execute按钮。所有表的数据库大小现在存储在计算机上的文件中。
其他回答
CREATE TABLE #tmp_table_info
(
id int identity(1,1),
tblname varchar(200)
);
CREATE TABLE #SpaceUsed
(
TableName sysname
,NumRows BIGINT
,ReservedSpace VARCHAR(50)
,DataSpace VARCHAR(50)
,IndexSize VARCHAR(50)
,UnusedSpace VARCHAR(50)
)
insert into #tmp_table_info
select s.name+'.'+t.name
from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
where t.type = 'U';
declare @min int =1,@max int = 0
select @max = count(*)
from #tmp_table_info
while(@min<=@max)
begin
declare @tablename varchar(200)
select @tablename=tblname
from #tmp_table_info
where id =@min
DECLARE @str VARCHAR(500)
SET @str = 'sp_spaceused '''+@tablename+''''
INSERT INTO #SpaceUsed
EXEC (@str)
set @min =@min + 1
end;
select @@SERVERNAME as servername,DB_NAME() as DatabaseName,CONVERT(numeric(18,0),REPLACE(ReservedSpace,' KB','')) / 1024 as ReservedSpace_MB,
CONVERT(numeric(18,0),REPLACE(DataSpace,' KB','')) / 1024 as DataSpace_MB,
CONVERT(numeric(18,0),REPLACE(IndexSize,' KB','')) / 1024 as IndexSpace_MB,
CONVERT(numeric(18,0),REPLACE(UnusedSpace,' KB','')) / 1024 as UnusedSpace_MB from #SpaceUsed
drop table #tmp_table_info
drop table #SpaceUsed
要获取一个数据库中的所有表大小,可以使用以下查询:
Exec sys.sp_MSforeachtable ' sp_spaceused "?" '
您可以将其更改为将所有结果插入临时表,然后从临时表中进行选择。
Insert into #TempTable Exec sys.sp_MSforeachtable ' sp_spaceused "?" '
Select * from #TempTable
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
也许表格有更多的分区文件,必须显示文件顺序
SELECT
T1.Name AS TableName,
T5.Name AS SchemaName,
T3.partition_number AS PartionNumber,
T3.Rows AS RowsCount,
SUM(T4.total_pages) * 8 AS TotalSpaceKB,
SUM(T4.used_pages) * 8 AS UsedSpaceKB,
(SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.objects T1 INNER JOIN
sys.indexes T2 ON T1.object_id = T2.object_id INNER JOIN
sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id INNER JOIN
sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
T1.type='U'
GROUP BY
T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
T1.Name,T3.partition_number;
经过一番搜索,我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的方便存储过程,它将返回数据库使用的所有空间。如果提供了表名,则返回该表使用的空间。但是,存储过程返回的结果不可排序,因为列是字符值。
以下脚本将生成我要查找的信息。
create table #TableSize (
Name varchar(255),
[rows] int,
reserved varchar(255),
data varchar(255),
index_size varchar(255),
unused varchar(255))
create table #ConvertedSizes (
Name varchar(255),
[rows] int,
reservedKb int,
dataKb int,
reservedIndexSize int,
reservedUnused int)
EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows],
SUBSTRING(reserved, 0, LEN(reserved)-2),
SUBSTRING(data, 0, LEN(data)-2),
SUBSTRING(index_size, 0, LEN(index_size)-2),
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize
select * from #ConvertedSizes
order by reservedKb desc
drop table #TableSize
drop table #ConvertedSizes