给定一个一维下标数组:
a = array([1, 0, 3])
我想把它编码成一个2D数组:
b = array([[0,1,0,0], [1,0,0,0], [0,0,0,1]])
给定一个一维下标数组:
a = array([1, 0, 3])
我想把它编码成一个2D数组:
b = array([[0,1,0,0], [1,0,0,0], [0,0,0,1]])
当前回答
下面是一个将一维向量转换为二维单热数组的函数。
#!/usr/bin/env python
import numpy as np
def convertToOneHot(vector, num_classes=None):
"""
Converts an input 1-D vector of integers into an output
2-D array of one-hot vectors, where an i'th input value
of j will set a '1' in the i'th row, j'th column of the
output array.
Example:
v = np.array((1, 0, 4))
one_hot_v = convertToOneHot(v)
print one_hot_v
[[0 1 0 0 0]
[1 0 0 0 0]
[0 0 0 0 1]]
"""
assert isinstance(vector, np.ndarray)
assert len(vector) > 0
if num_classes is None:
num_classes = np.max(vector)+1
else:
assert num_classes > 0
assert num_classes >= np.max(vector)
result = np.zeros(shape=(len(vector), num_classes))
result[np.arange(len(vector)), vector] = 1
return result.astype(int)
下面是一些用法示例:
>>> a = np.array([1, 0, 3])
>>> convertToOneHot(a)
array([[0, 1, 0, 0],
[1, 0, 0, 0],
[0, 0, 0, 1]])
>>> convertToOneHot(a, num_classes=10)
array([[0, 1, 0, 0, 0, 0, 0, 0, 0, 0],
[1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 0, 0, 0, 0, 0, 0]])
其他回答
这种类型的编码通常是numpy数组的一部分。如果你使用numpy数组,像这样:
a = np.array([1,0,3])
然后有一个非常简单的方法将其转换为1-hot编码
out = (np.arange(4) == a[:,None]).astype(np.float32)
就是这样。
你可以使用sklearn.预处理。labelbinarizer:
例子:
import sklearn.preprocessing
a = [1,0,3]
label_binarizer = sklearn.preprocessing.LabelBinarizer()
label_binarizer.fit(range(max(a)+1))
b = label_binarizer.transform(a)
print('{0}'.format(b))
输出:
[[0 1 0 0]
[1 0 0 0]
[0 0 0 1]]
除此之外,你可以初始化sklearn.pre - processing. labelbinarizer(),这样transform的输出是稀疏的。
我添加了一个简单的补全函数,只使用numpy操作符:
def probs_to_onehot(output_probabilities):
argmax_indices_array = np.argmax(output_probabilities, axis=1)
onehot_output_array = np.eye(np.unique(argmax_indices_array).shape[0])[argmax_indices_array.reshape(-1)]
return onehot_output_array
它以一个概率矩阵作为输入:例如:
[[0.03038822 0.65810204 0.16549407 0.3797123] . [0.02771272 0.2760752 0.3280924 0.33458805]
它会返回
[[0 0 0 0]... [0 0 0 1]
def one_hot(n, class_num, col_wise=True):
a = np.eye(class_num)[n.reshape(-1)]
return a.T if col_wise else a
# Column for different hot
print(one_hot(np.array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 9, 9, 9, 9, 8, 7]), 10))
# Row for different hot
print(one_hot(np.array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 9, 9, 9, 9, 8, 7]), 10, col_wise=False))
如果你正在使用keras,有一个内置的实用程序:
from keras.utils.np_utils import to_categorical
categorical_labels = to_categorical(int_labels, num_classes=3)
它与@YXD的答案几乎相同(请参阅源代码)。