我有一个foreach循环,需要执行一些逻辑时,最后一项是从列表中选择,例如:
foreach (Item result in Model.Results)
{
//if current result is the last item in Model.Results
//then do something in the code
}
我可以知道哪个循环是最后没有使用循环和计数器吗?
我有一个foreach循环,需要执行一些逻辑时,最后一项是从列表中选择,例如:
foreach (Item result in Model.Results)
{
//if current result is the last item in Model.Results
//then do something in the code
}
我可以知道哪个循环是最后没有使用循环和计数器吗?
当前回答
只需存储之前的值,并在循环中使用它。然后在最后,“previous”值将是最后一项,让您以不同的方式处理它。不需要计数或特殊库。
bool empty = true;
Item previousItem;
foreach (Item result in Model.Results)
{
// Alternatively, check if previousItem == null
// if your Enumerable can't contain nulls
if (!empty)
{
// We know this isn't the last item because
// it came from the previous iteration
handleRegularItem(previousItem);
}
previousItem = result;
empty = false;
}
if (!empty)
{
// We know this is the last item because the loop is finished
handleLastItem(previousItem);
}
其他回答
正如Shimmy所指出的,使用Last()可能会导致性能问题,例如,如果您的集合是LINQ表达式的实时结果。为了防止多次迭代,你可以使用“ForEach”扩展方法,如下所示:
var elements = new[] { "A", "B", "C" };
elements.ForEach((element, info) => {
if (!info.IsLast) {
Console.WriteLine(element);
} else {
Console.WriteLine("Last one: " + element);
}
});
扩展方法看起来像这样(作为额外的奖励,它还会告诉你索引,如果你在看第一个元素):
public static class EnumerableExtensions {
public delegate void ElementAction<in T>(T element, ElementInfo info);
public static void ForEach<T>(this IEnumerable<T> elements, ElementAction<T> action) {
using (IEnumerator<T> enumerator = elements.GetEnumerator())
{
bool isFirst = true;
bool hasNext = enumerator.MoveNext();
int index = 0;
while (hasNext)
{
T current = enumerator.Current;
hasNext = enumerator.MoveNext();
action(current, new ElementInfo(index, isFirst, !hasNext));
isFirst = false;
index++;
}
}
}
public struct ElementInfo {
public ElementInfo(int index, bool isFirst, bool isLast)
: this() {
Index = index;
IsFirst = isFirst;
IsLast = isLast;
}
public int Index { get; private set; }
public bool IsFirst { get; private set; }
public bool IsLast { get; private set; }
}
}
另一种方法是使用Queue(队列),我没有看到它被贴出来。这类似于实现SkipLast()方法而无需进行不必要的迭代。这种方法也可以让你在任何数量的最后一项上这样做。
public static void ForEachAndKnowIfLast<T>(
this IEnumerable<T> source,
Action<T, bool> a,
int numLastItems = 1)
{
int bufferMax = numLastItems + 1;
var buffer = new Queue<T>(bufferMax);
foreach (T x in source)
{
buffer.Enqueue(x);
if (buffer.Count < bufferMax)
continue; //Until the buffer is full, just add to it.
a(buffer.Dequeue(), false);
}
foreach (T item in buffer)
a(item, true);
}
要调用它,你需要执行以下操作:
Model.Results.ForEachAndKnowIfLast(
(result, isLast) =>
{
//your logic goes here, using isLast to do things differently for last item(s).
});
你可以创建一个专门用于此的扩展方法:
public static class EnumerableExtensions {
public static bool IsLast<T>(this List<T> items, T item)
{
if (items.Count == 0)
return false;
T last = items[items.Count - 1];
return item.Equals(last);
}
}
你可以这样使用它:
foreach (Item result in Model.Results)
{
if(Model.Results.IsLast(result))
{
//do something in the code
}
}
List<int> ListInt = new List<int> { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
int count = ListInt.Count;
int index = 1;
foreach (var item in ListInt)
{
if (index != count)
{
Console.WriteLine("do something at index number " + index);
}
else
{
Console.WriteLine("Foreach loop, this is the last iteration of the loop " + index);
}
index++;
}
//OR
int count = ListInt.Count;
int index = 1;
foreach (var item in ListInt)
{
if (index < count)
{
Console.WriteLine("do something at index number " + index);
}
else
{
Console.WriteLine("Foreach loop, this is the last iteration of the loop " + index);
}
index++;
}
var last = objList.LastOrDefault();
foreach (var item in objList)
{
if (item.Equals(last))
{
}
}