我有一个对话框与EditText进行输入。当我单击对话框上的“是”按钮时,它将验证输入,然后关闭对话框。但是,如果输入错误,我希望保持在同一对话框中。每次无论输入是什么,当我单击“否”按钮时,对话框都会自动关闭。如何禁用此功能?顺便说一句,我在对话框中使用了PositiveButton和NegativeButton。
当前回答
它可以用最简单的方法构建:
带有自定义视图和两个按钮(正和负)的警报对话框。
AlertDialog.Builder builder = new AlertDialog.Builder(getActivity()).setTitle(getString(R.string.select_period));
builder.setPositiveButton(getString(R.string.ok), null);
builder.setNegativeButton(getString(R.string.cancel), new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
// Click of Cancel Button
}
});
LayoutInflater li = LayoutInflater.from(getActivity());
View promptsView = li.inflate(R.layout.dialog_date_picker, null, false);
builder.setView(promptsView);
DatePicker startDatePicker = (DatePicker)promptsView.findViewById(R.id.startDatePicker);
DatePicker endDatePicker = (DatePicker)promptsView.findViewById(R.id.endDatePicker);
final AlertDialog alertDialog = builder.create();
alertDialog.show();
Button theButton = alertDialog.getButton(DialogInterface.BUTTON_POSITIVE);
theButton.setOnClickListener(new CustomListener(alertDialog, startDatePicker, endDatePicker));
警报日志正面按钮的CustomClickLister:
private class CustomListener implements View.OnClickListener {
private final Dialog dialog;
private DatePicker mStartDp, mEndDp;
public CustomListener(Dialog dialog, DatePicker dS, DatePicker dE) {
this.dialog = dialog;
mStartDp = dS;
mEndDp = dE;
}
@Override
public void onClick(View v) {
int day1 = mStartDp.getDayOfMonth();
int month1= mStartDp.getMonth();
int year1 = mStartDp.getYear();
Calendar cal1 = Calendar.getInstance();
cal1.set(Calendar.YEAR, year1);
cal1.set(Calendar.MONTH, month1);
cal1.set(Calendar.DAY_OF_MONTH, day1);
int day2 = mEndDp.getDayOfMonth();
int month2= mEndDp.getMonth();
int year2 = mEndDp.getYear();
Calendar cal2 = Calendar.getInstance();
cal2.set(Calendar.YEAR, year2);
cal2.set(Calendar.MONTH, month2);
cal2.set(Calendar.DAY_OF_MONTH, day2);
if(cal2.getTimeInMillis()>=cal1.getTimeInMillis()){
dialog.dismiss();
Log.i("Dialog", "Dismiss");
// Condition is satisfied so do dialog dismiss
}else {
Log.i("Dialog", "Do not Dismiss");
// Condition is not satisfied so do not dialog dismiss
}
}
}
Done
其他回答
这个链接的答案是一个简单的解决方案,它与API 3兼容。它与Tom Bollwitt的解决方案非常相似,但没有使用兼容性较差的OnShowListener。
是的,你可以。您基本上需要:使用DialogBuilder创建对话框show()对话框在显示的对话框中查找按钮并覆盖其onClickListener
自从我扩展EditTextPreference以来,我对Kamen的代码进行了一些小的修改。
@Override
protected void showDialog(Bundle state) {
super.showDialog(state);
class mocl implements OnClickListener{
private final AlertDialog dialog;
public mocl(AlertDialog dialog) {
this.dialog = dialog;
}
@Override
public void onClick(View v) {
//checks if EditText is empty, and if so tells the user via Toast
//otherwise it closes dialog and calls the EditTextPreference's onClick
//method to let it know that the button has been pressed
if (!IntPreference.this.getEditText().getText().toString().equals("")){
dialog.dismiss();
IntPreference.this.onClick(dialog,DialogInterface.BUTTON_POSITIVE);
}
else {
Toast t = Toast.makeText(getContext(), "Enter a number!", Toast.LENGTH_SHORT);
t.show();
}
}
}
AlertDialog d = (AlertDialog) getDialog();
Button b = d.getButton(DialogInterface.BUTTON_POSITIVE);
b.setOnClickListener(new mocl((d)));
}
真有趣!
可以添加builder.show();在返回之前的验证消息之后;
这样地
public void login()
{
final AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setView(R.layout.login_layout);
builder.setTitle("Login");
builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
dialog.cancel();
}
});// put the negative button before the positive button, so it will appear
builder.setPositiveButton("Ok", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
Dialog d = (Dialog) dialog;
final EditText etUserName = (EditText) d.findViewById(R.id.etLoginName);
final EditText etPassword = (EditText) d.findViewById(R.id.etLoginPassword);
String userName = etUserName.getText().toString().trim();
String password = etPassword.getText().toString().trim();
if (userName.isEmpty() || password.isEmpty())
{
Toast.makeText(getApplicationContext(),
"Please Fill all fields", Toast.LENGTH_SHORT).show();
builder.show();// here after validation message before retrun
// it will reopen the dialog
// till the user enter the right condition
return;
}
user = Manager.get(getApplicationContext()).getUserByName(userName);
if (user == null)
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
if (password.equals(user.getPassword()))
{
etPassword.setText("");
etUserName.setText("");
setLogged(1);
setLoggedId(user.getUserId());
Toast.makeText(getApplicationContext(),
"Successfully logged in", Toast.LENGTH_SHORT).show();
dialog.dismiss();// if every thing is ok then dismiss the dialog
}
else
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
}
});
builder.show();
}
这段代码对你有用,因为我有一个类似的问题,这对我有用。:)
1-重写片段对话框类中的Onstart()方法。
@Override
public void onStart() {
super.onStart();
final AlertDialog D = (AlertDialog) getDialog();
if (D != null) {
Button positive = (Button) D.getButton(Dialog.BUTTON_POSITIVE);
positive.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
if (edittext.equals("")) {
Toast.makeText(getActivity(), "EditText empty",Toast.LENGTH_SHORT).show();
} else {
D.dismiss(); //dissmiss dialog
}
}
});
}
}
如果你使用的是材料设计,我建议你查看材料对话框。它为我修复了几个与当前打开的Android bug相关的问题(参见78088),但最重要的是,对于这个问题,它有一个autoDismiss标志,可以在使用生成器时设置。
如果您正在使用DialogFragment,这是处理Dialog的推荐方法。
AlertDialog的setButton()方法(我认为AlertDialogBuilder的setPositiveButton(()和setNegativeButton()也是如此)所发生的事情是,您使用它设置的按钮(例如AlertDialog.button_POSITIVE)在按下时实际上会触发两个不同的OnClickListener对象。
第一个是DialogInterface.OnClickListener,它是setButton()、setPositiveButton(()和setNegativeButton()的参数。
另一个是View.OnClickListener,它将被设置为在按下任何按钮时自动关闭AlertDialog,并且由AlertDialog自身设置。
您可以做的是使用带有null的setButton()作为DialogInterface.OnClickListener来创建按钮,然后在View.OnClick Listener中调用自定义操作方法。例如,
@Override
public Dialog onCreateDialog(Bundle savedInstanceState)
{
AlertDialog alertDialog = new AlertDialog(getActivity());
// set more items...
alertDialog.setButton(AlertDialog.BUTTON_POSITIVE, "OK", null);
return alertDialog;
}
然后,您可以在DialogFragment的onResume()方法中重写默认AlertDialog的按钮View.OnClickListener(否则将关闭对话框):
@Override
public void onResume()
{
super.onResume();
AlertDialog alertDialog = (AlertDialog) getDialog();
Button okButton = alertDialog.getButton(AlertDialog.BUTTON_POSITIVE);
okButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v)
{
performOkButtonAction();
}
});
}
private void performOkButtonAction() {
// Do your stuff here
}
您需要在onResume()方法中设置此值,因为getButton()将返回null,直到显示对话框!
这将导致您的自定义操作方法只被调用一次,默认情况下对话框不会被关闭。
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