我有一个对话框与EditText进行输入。当我单击对话框上的“是”按钮时,它将验证输入,然后关闭对话框。但是,如果输入错误,我希望保持在同一对话框中。每次无论输入是什么,当我单击“否”按钮时,对话框都会自动关闭。如何禁用此功能?顺便说一句,我在对话框中使用了PositiveButton和NegativeButton。
当前回答
科特林
val dialogView = LayoutInflater.from(requireContext()).inflate(R.layout.dialog_userinput, null)
val dialogBuilder = MaterialAlertDialogBuilder(requireContext(), R.style.AlertDialogTheme)
dialogBuilder.setView(dialogView)
dialogBuilder.setCancelable(false)
dialogBuilder.setPositiveButton("send",null)
dialogBuilder.setNegativeButton("cancel") { dialog,_ ->
dialog.dismiss()
}
val alertDialog = dialogBuilder.create()
alertDialog.show()
val positiveButton = alertDialog.getButton(AlertDialog.BUTTON_POSITIVE)
positiveButton.setOnClickListener {
val myInputText = dialogView.etxt_userinput.text.toString().trim()
if(myInputText.isNotEmpty()){
//Do something
}else{
//Prompt error
dialogView.etxt_userinput.error = "Please fill this"
}
}
我们只需使用dialogBuilder创建一个AlertDialog,然后根据需要设置肯定按钮
其他回答
这段代码对你有用,因为我有一个类似的问题,这对我有用。:)
1-重写片段对话框类中的Onstart()方法。
@Override
public void onStart() {
super.onStart();
final AlertDialog D = (AlertDialog) getDialog();
if (D != null) {
Button positive = (Button) D.getButton(Dialog.BUTTON_POSITIVE);
positive.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
if (edittext.equals("")) {
Toast.makeText(getActivity(), "EditText empty",Toast.LENGTH_SHORT).show();
} else {
D.dismiss(); //dissmiss dialog
}
}
});
}
}
可以添加builder.show();在返回之前的验证消息之后;
这样地
public void login()
{
final AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setView(R.layout.login_layout);
builder.setTitle("Login");
builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
dialog.cancel();
}
});// put the negative button before the positive button, so it will appear
builder.setPositiveButton("Ok", new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int id)
{
Dialog d = (Dialog) dialog;
final EditText etUserName = (EditText) d.findViewById(R.id.etLoginName);
final EditText etPassword = (EditText) d.findViewById(R.id.etLoginPassword);
String userName = etUserName.getText().toString().trim();
String password = etPassword.getText().toString().trim();
if (userName.isEmpty() || password.isEmpty())
{
Toast.makeText(getApplicationContext(),
"Please Fill all fields", Toast.LENGTH_SHORT).show();
builder.show();// here after validation message before retrun
// it will reopen the dialog
// till the user enter the right condition
return;
}
user = Manager.get(getApplicationContext()).getUserByName(userName);
if (user == null)
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
if (password.equals(user.getPassword()))
{
etPassword.setText("");
etUserName.setText("");
setLogged(1);
setLoggedId(user.getUserId());
Toast.makeText(getApplicationContext(),
"Successfully logged in", Toast.LENGTH_SHORT).show();
dialog.dismiss();// if every thing is ok then dismiss the dialog
}
else
{
Toast.makeText(getApplicationContext(),
"Error ethier username or password are wrong", Toast.LENGTH_SHORT).show();
builder.show();
return;
}
}
});
builder.show();
}
我找到了另一种方法来实现这一点。。。
步骤1:将对话框打开代码放入方法(或C中的函数)。步骤2:在onClick of yes(您的positiveButton)中,调用此对话框打开如果条件不满足,则递归使用方法(通过使用if…else…)。如下所示:
private void openSave() {
final AlertDialog.Builder builder=new AlertDialog.Builder(Phase2Activity.this);
builder.setTitle("SAVE")
.setIcon(R.drawable.ic_save_icon)
.setPositiveButton("Save", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
if((!editText.getText().toString().isEmpty() && !editText1.getText().toString().isEmpty())){
createPdf(fileName,title,file);
}else {
openSave();
Toast.makeText(Phase2Activity.this, "Some fields are empty.", Toast.LENGTH_SHORT).show();
}
})
.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
dialogInterface.dismiss();
}
})
.setCancelable(false)
.create()
.show();
}
但这将使对话框消失片刻,并立即再次出现。:)
对于API 8之前的版本,如果editText的内容不正确,我使用一个布尔标志、一个关闭监听器并再次调用dialog.show来解决这个问题。这样地:
case ADD_CLIENT:
LayoutInflater factoryClient = LayoutInflater.from(this);
final View EntryViewClient = factoryClient.inflate(
R.layout.alert_dialog_add_client, null);
EditText ClientText = (EditText) EntryViewClient
.findViewById(R.id.client_edit);
AlertDialog.Builder builderClient = new AlertDialog.Builder(this);
builderClient
.setTitle(R.string.alert_dialog_client)
.setCancelable(false)
.setView(EntryViewClient)
.setPositiveButton("Save",
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog,
int whichButton) {
EditText newClient = (EditText) EntryViewClient
.findViewById(R.id.client_edit);
String newClientString = newClient
.getText().toString();
if (checkForEmptyFields(newClientString)) {
//If field is empty show toast and set error flag to true;
Toast.makeText(getApplicationContext(),
"Fields cant be empty",
Toast.LENGTH_SHORT).show();
add_client_error = true;
} else {
//Here save the info and set the error flag to false
add_client_error = false;
}
}
})
.setNegativeButton("Cancel",
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog,
int id) {
add_client_error = false;
dialog.cancel();
}
});
final AlertDialog alertClient = builderClient.create();
alertClient.show();
alertClient
.setOnDismissListener(new DialogInterface.OnDismissListener() {
@Override
public void onDismiss(DialogInterface dialog) {
//If the error flag was set to true then show the dialog again
if (add_client_error == true) {
alertClient.show();
} else {
return;
}
}
});
return true;
受汤姆的回答启发,我认为这里的想法是:
在创建对话框期间将onClickListener设置为null然后在显示对话框后设置onClickListener。
您可以像Tom一样重写onShowListener。或者,您可以
调用AlertDialog的show()后获取按钮按如下方式设置按钮的onClickListener(我认为稍微可读一些)。
代码:
AlertDialog.Builder builder = new AlertDialog.Builder(context);
// ...
final AlertDialog dialog = builder.create();
dialog.show();
// now you can override the default onClickListener
Button b = dialog.getButton(AlertDialog.BUTTON_POSITIVE);
b.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Log.i(TAG, "ok button is clicked");
handleClick(dialog);
}
});
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