两个mashup，将两个半字节操作合并为一个。

可能非常有效的版本：

public static string ByteArrayToString2(byte[] ba)
{
    char[] c = new char[ba.Length * 2];
    for( int i = 0; i < ba.Length * 2; ++i)
    {
        byte b = (byte)((ba[i>>1] >> 4*((i&1)^1)) & 0xF);
        c[i] = (char)(55 + b + (((b-10)>>31)&-7));
    }
    return new string( c );
}

Decadent linq与比特黑客版本：

public static string ByteArrayToString(byte[] ba)
{
    return string.Concat( ba.SelectMany( b => new int[] { b >> 4, b & 0xF }).Select( b => (char)(55 + b + (((b-10)>>31)&-7))) );
}

并反转：

public static byte[] HexStringToByteArray( string s )
{
    byte[] ab = new byte[s.Length>>1];
    for( int i = 0; i < s.Length; i++ )
    {
        int b = s[i];
        b = (b - '0') + ((('9' - b)>>31)&-7);
        ab[i>>1] |= (byte)(b << 4*((i&1)^1));
    }
    return ab;
}

从.NET 5 RC2开始，您可以使用：

Convert.ToHexString（byte[]inArray），返回字符串和Convert.FromHexString（字符串s），返回字节[]。

可以使用跨度参数的重载。

我猜它的速度值16个额外的字节。

    static char[] hexes = new char[]{'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
    public static string ToHexadecimal (this byte[] Bytes)
    {
        char[] Result = new char[Bytes.Length << 1];
        int Offset = 0;
        for (int i = 0; i != Bytes.Length; i++) {
            Result[Offset++] = hexes[Bytes[i] >> 4];
            Result[Offset++] = hexes[Bytes[i] & 0x0F];
        }
        return new string(Result);
    }

我想出了一个不同的代码，它可以容忍额外的字符（空格、破折号…）。它的灵感主要来自这里一些可以接受的快速答案。它允许解析以下“文件”

00-aa-84-fb
12 32 FF CD
12 00
12_32_FF_CD
1200d5e68a

/// <summary>Reads a hex string into bytes</summary>
public static IEnumerable<byte> HexadecimalStringToBytes(string hex) {
    if (hex == null)
        throw new ArgumentNullException(nameof(hex));

    char c, c1 = default(char);
    bool hasc1 = false;
    unchecked   {
        for (int i = 0; i < hex.Length; i++) {
            c = hex[i];
            bool isValid = 'A' <= c && c <= 'f' || 'a' <= c && c <= 'f' || '0' <= c && c <= '9';
            if (!hasc1) {
                if (isValid) {
                    hasc1 = true;
                }
            } else {
                hasc1 = false;
                if (isValid) {
                    yield return (byte)((GetHexVal(c1) << 4) + GetHexVal(c));
                }
            }

            c1 = c;
        } 
    }
}

/// <summary>Reads a hex string into a byte array</summary>
public static byte[] HexadecimalStringToByteArray(string hex)
{
    if (hex == null)
        throw new ArgumentNullException(nameof(hex));

    var bytes = new List<byte>(hex.Length / 2);
    foreach (var item in HexadecimalStringToBytes(hex)) {
        bytes.Add(item);
    }

    return bytes.ToArray();
}

private static byte GetHexVal(char val)
{
    return (byte)(val - (val < 0x3A ? 0x30 : val < 0x5B ? 0x37 : 0x57));
    //                   ^^^^^^^^^^^^^^^^^   ^^^^^^^^^^^^^^^^^   ^^^^
    //                       digits 0-9       upper char A-Z     a-z
}

复制时请参考完整代码。包括单元测试。

有些人可能会说它对额外的字符太宽容了。因此，不要依赖此代码来执行验证（或更改）。

测试：十六进制字符串到字节数组

我注意到，大多数测试都是在将Bytes数组转换为十六进制字符串的函数上执行的。因此，在这篇文章中，我将关注另一方面：将十六进制字符串转换为字节数组的函数。若您只对结果感兴趣，可以跳到“摘要”部分。测试代码文件在文章末尾提供。

标签

我想根据接受的答案（Tomalak）将函数命名为StringToByteArrayV1，或将其快捷到V1。其余函数将以相同的方式命名：V2、V3、V4、…、。。。，等

参与功能索引

Tomalak的StringToByteArrayV1（公认答案）Mykroft的StringToByteArrayV2（使用SoapHexBinary）drphrozen的StringToByteArrayV3（查找表）CoperNick的StringToByteArrayV4（字节操作）Chris F编写的StringToByteArrayV5_1（字节操作）Chris F的StringToByteArrayV5_2（V5_1+根据Amir Rezaei的评论修改）Chris F的StringToByteArrayV5_3（V5_2+根据Ben Voigt的评论对其进行了修改）（您可以在发布后的测试代码中看到它的最终形状）Ben Mosher编写的StringToByteArrayV6（字节操作）Maratius的StringToByteArrayV7（字节操作-安全版本）Maratius的StringToByteArrayV8（字节操作-不安全版本）StringToByteArrayV9（按Geograph）AlejandroAlis编写的StringToByteArrayV10Fredrik Hu编写的StringToByteArrayV11Maarten Bodewes编写的StringToByteArrayV12ClausAndersen编写的StringToByteArrayV13Stas Makutin编写的StringToByteArrayV14JJJ的StringToByteArrayV15JamieSee的StringToByteArrayV16spacepille的StringToByteArrayV17Gregory Morse编写的StringToByteArrayV18Rick编写的StringToByteArrayV19SandRock的StringToByteArrayV20Paul编写的StringToByteArrayV21

正确性测试

我通过传递1字节的所有256个可能值来测试正确性，然后检查输出是否正确。结果：

V18中以“00”开头的字符串有问题（请参阅Roger Stewart对此的评论）。除了通过所有测试。如果十六进制字符串字母是大写的：所有函数都成功传递如果十六进制字符串字母是小写的，则以下函数失败：V5_1、V5_2、v7、V8、V15、V19

注：V5_3解决了这个问题（V5_1和V5_2）

性能测试

我已经使用Stopwatch类进行了性能测试。

长字符串的性能

input length: 10,000,000 bytes
runs: 100
average elapsed time per run:
V1 = 136.4ms
V2 = 104.5ms
V3 = 22.0ms
V4 = 9.9ms
V5_1 = 10.2ms
V5_2 = 9.0ms
V5_3 = 9.3ms
V6 = 18.3ms
V7 = 9.8ms
V8 = 8.8ms
V9 = 10.2ms
V10 = 19.0ms
V11 = 12.2ms
V12 = 27.4ms
V13 = 21.8ms
V14 = 12.0ms
V15 = 14.9ms
V16 = 15.3ms
V17 = 9.5ms
V18 got excluded from this test, because it was very slow when using very long string
V19 = 222.8ms
V20 = 66.0ms
V21 = 15.4ms

V1 average ticks per run: 1363529.4
V2 is more fast than V1 by: 1.3 times (ticks ratio)
V3 is more fast than V1 by: 6.2 times (ticks ratio)
V4 is more fast than V1 by: 13.8 times (ticks ratio)
V5_1 is more fast than V1 by: 13.3 times (ticks ratio)
V5_2 is more fast than V1 by: 15.2 times (ticks ratio)
V5_3 is more fast than V1 by: 14.8 times (ticks ratio)
V6 is more fast than V1 by: 7.4 times (ticks ratio)
V7 is more fast than V1 by: 13.9 times (ticks ratio)
V8 is more fast than V1 by: 15.4 times (ticks ratio)
V9 is more fast than V1 by: 13.4 times (ticks ratio)
V10 is more fast than V1 by: 7.2 times (ticks ratio)
V11 is more fast than V1 by: 11.1 times (ticks ratio)
V12 is more fast than V1 by: 5.0 times (ticks ratio)
V13 is more fast than V1 by: 6.3 times (ticks ratio)
V14 is more fast than V1 by: 11.4 times (ticks ratio)
V15 is more fast than V1 by: 9.2 times (ticks ratio)
V16 is more fast than V1 by: 8.9 times (ticks ratio)
V17 is more fast than V1 by: 14.4 times (ticks ratio)
V19 is more SLOW than V1 by: 1.6 times (ticks ratio)
V20 is more fast than V1 by: 2.1 times (ticks ratio)
V21 is more fast than V1 by: 8.9 times (ticks ratio)

V18的长串性能

V18 took long time at the previous test, 
so let's decrease length for it:  
input length: 1,000,000 bytes
runs: 100
average elapsed time per run: V1 = 14.1ms , V18 = 146.7ms
V1 average ticks per run: 140630.3
V18 is more SLOW than V1 by: 10.4 times (ticks ratio)

短字符串的性能

input length: 100 byte
runs: 1,000,000
V1 average ticks per run: 14.6
V2 is more fast than V1 by: 1.4 times (ticks ratio)
V3 is more fast than V1 by: 5.9 times (ticks ratio)
V4 is more fast than V1 by: 15.7 times (ticks ratio)
V5_1 is more fast than V1 by: 15.1 times (ticks ratio)
V5_2 is more fast than V1 by: 18.4 times (ticks ratio)
V5_3 is more fast than V1 by: 16.3 times (ticks ratio)
V6 is more fast than V1 by: 5.3 times (ticks ratio)
V7 is more fast than V1 by: 15.7 times (ticks ratio)
V8 is more fast than V1 by: 18.0 times (ticks ratio)
V9 is more fast than V1 by: 15.5 times (ticks ratio)
V10 is more fast than V1 by: 7.8 times (ticks ratio)
V11 is more fast than V1 by: 12.4 times (ticks ratio)
V12 is more fast than V1 by: 5.3 times (ticks ratio)
V13 is more fast than V1 by: 5.2 times (ticks ratio)
V14 is more fast than V1 by: 13.4 times (ticks ratio)
V15 is more fast than V1 by: 9.9 times (ticks ratio)
V16 is more fast than V1 by: 9.2 times (ticks ratio)
V17 is more fast than V1 by: 16.2 times (ticks ratio)
V18 is more fast than V1 by: 1.1 times (ticks ratio)
V19 is more SLOW than V1 by: 1.6 times (ticks ratio)
V20 is more fast than V1 by: 1.9 times (ticks ratio)
V21 is more fast than V1 by: 11.4 times (ticks ratio)

测试代码

在使用以下代码之前，最好先阅读本文下面的免责声明部分https://github.com/Ghosticollis/performance-tests/blob/main/MTestPerformance.cs

总结

由于性能良好，我建议使用以下函数之一，并支持大写和小写：

CoperNick的StringToByteArrayV4StringToByteArrayV9（按Geograph）spacepille的StringToByteArrayV17StringToByteArrayV5_3基本上由Chris F开发（它基于V5_1，但我根据Amir Rezaei和Ben Voigt的评论对其进行了增强）。

以下是V5_3的最终形状：

static byte[] HexStringToByteArrayV5_3(string hexString) {
    int hexStringLength = hexString.Length;
    byte[] b = new byte[hexStringLength / 2];
    for (int i = 0; i < hexStringLength; i += 2) {
        int topChar = hexString[i];
        topChar = (topChar > 0x40 ? (topChar & ~0x20) - 0x37 : topChar - 0x30) << 4;
        int bottomChar = hexString[i + 1];
        bottomChar = bottomChar > 0x40 ? (bottomChar & ~0x20) - 0x37 : bottomChar - 0x30;
        b[i / 2] = (byte)(topChar + bottomChar);
    }
    return b;
}

免责声明

警告：我没有适当的测试知识。这些原始测试的主要目的是快速概述所有发布的函数的优点。如果您需要准确的结果，请使用适当的测试工具。

最后，我想说，我是新来的，在斯塔科弗洛活跃，如果我的职位空缺，我很抱歉。如果您能发表评论，我们将不胜感激。

另一个快速功能。。。

private static readonly byte[] HexNibble = new byte[] {
    0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7,
    0x8, 0x9, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0,
    0x0, 0xA, 0xB, 0xC, 0xD, 0xE, 0xF, 0x0,
    0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0,
    0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0,
    0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0,
    0x0, 0xA, 0xB, 0xC, 0xD, 0xE, 0xF
};

public static byte[] HexStringToByteArray( string str )
{
    int byteCount = str.Length >> 1;
    byte[] result = new byte[byteCount + (str.Length & 1)];
    for( int i = 0; i < byteCount; i++ )
        result[i] = (byte) (HexNibble[str[i << 1] - 48] << 4 | HexNibble[str[(i << 1) + 1] - 48]);
    if( (str.Length & 1) != 0 )
        result[byteCount] = (byte) HexNibble[str[str.Length - 1] - 48];
    return result;
}