如何将字节数组转换为十六进制字符串,反之亦然?


当前回答

另一种基于查找表的方法。该方法只为每个字节使用一个查找表,而不是为每个半字节使用查找表。

private static readonly uint[] _lookup32 = CreateLookup32();

private static uint[] CreateLookup32()
{
    var result = new uint[256];
    for (int i = 0; i < 256; i++)
    {
        string s=i.ToString("X2");
        result[i] = ((uint)s[0]) + ((uint)s[1] << 16);
    }
    return result;
}

private static string ByteArrayToHexViaLookup32(byte[] bytes)
{
    var lookup32 = _lookup32;
    var result = new char[bytes.Length * 2];
    for (int i = 0; i < bytes.Length; i++)
    {
        var val = lookup32[bytes[i]];
        result[2*i] = (char)val;
        result[2*i + 1] = (char) (val >> 16);
    }
    return new string(result);
}

我还使用查找表中的ushort、struct{char X1,X2}、struct{byte X1,X2}测试了这个变体。

根据编译目标(x86、X64)的不同,它们要么具有大致相同的性能,要么稍慢于此变体。


为了获得更高的性能,其不安全的兄弟:

private static readonly uint[] _lookup32Unsafe = CreateLookup32Unsafe();
private static readonly uint* _lookup32UnsafeP = (uint*)GCHandle.Alloc(_lookup32Unsafe,GCHandleType.Pinned).AddrOfPinnedObject();

private static uint[] CreateLookup32Unsafe()
{
    var result = new uint[256];
    for (int i = 0; i < 256; i++)
    {
        string s=i.ToString("X2");
        if(BitConverter.IsLittleEndian)
            result[i] = ((uint)s[0]) + ((uint)s[1] << 16);
        else
            result[i] = ((uint)s[1]) + ((uint)s[0] << 16);
    }
    return result;
}

public static string ByteArrayToHexViaLookup32Unsafe(byte[] bytes)
{
    var lookupP = _lookup32UnsafeP;
    var result = new char[bytes.Length * 2];
    fixed(byte* bytesP = bytes)
    fixed (char* resultP = result)
    {
        uint* resultP2 = (uint*)resultP;
        for (int i = 0; i < bytes.Length; i++)
        {
            resultP2[i] = lookupP[bytesP[i]];
        }
    }
    return new string(result);
}

或者如果您认为可以直接写入字符串:

public static string ByteArrayToHexViaLookup32UnsafeDirect(byte[] bytes)
{
    var lookupP = _lookup32UnsafeP;
    var result = new string((char)0, bytes.Length * 2);
    fixed (byte* bytesP = bytes)
    fixed (char* resultP = result)
    {
        uint* resultP2 = (uint*)resultP;
        for (int i = 0; i < bytes.Length; i++)
        {
            resultP2[i] = lookupP[bytesP[i]];
        }
    }
    return result;
}

其他回答

支持最短路径和.net核心:

    public static string BytesToString(byte[] ba) =>
        ba.Aggregate(new StringBuilder(32), (sb, b) => sb.Append(b.ToString("X2"))).ToString();

下面还通过允许本机小写选项扩展了这里的优秀答案,并且还处理null或空输入,并使其成为扩展方法。

    /// <summary>
    /// Converts the byte array to a hex string very fast. Excellent job
    /// with code lightly adapted from 'community wiki' here: https://stackoverflow.com/a/14333437/264031
    /// (the function was originally named: ByteToHexBitFiddle). Now allows a native lowerCase option
    /// to be input and allows null or empty inputs (null returns null, empty returns empty).
    /// </summary>
    public static string ToHexString(this byte[] bytes, bool lowerCase = false)
    {
        if (bytes == null)
            return null;
        else if (bytes.Length == 0)
            return "";

        char[] c = new char[bytes.Length * 2];

        int b;
        int xAddToAlpha = lowerCase ? 87 : 55;
        int xAddToDigit = lowerCase ? -39 : -7;

        for (int i = 0; i < bytes.Length; i++) {

            b = bytes[i] >> 4;
            c[i * 2] = (char)(xAddToAlpha + b + (((b - 10) >> 31) & xAddToDigit));

            b = bytes[i] & 0xF;
            c[i * 2 + 1] = (char)(xAddToAlpha + b + (((b - 10) >> 31) & xAddToDigit));
        }

        string val = new string(c);
        return val;
    }

    public static string ToHexString(this IEnumerable<byte> bytes, bool lowerCase = false)
    {
        if (bytes == null)
            return null;
        byte[] arr = bytes.ToArray();
        return arr.ToHexString(lowerCase);
    }

为了方便以后复制和粘贴,将几个答案合并到一个类中:

/// <summary>
/// Extension methods to quickly convert byte array to string and back.
/// </summary>
public static class HexConverter
{
    /// <summary>
    /// Map values to hex digits
    /// </summary>
    private static readonly char[] HexDigits =
        {
            '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'
        };

    /// <summary>
    /// Map 56 characters between ['0', 'F'] to their hex equivalents, and set invalid characters
    /// such that they will overflow byte to fail conversion.
    /// </summary>
    private static readonly ushort[] HexValues =
        {
            0x0000, 0x0001, 0x0002, 0x0003, 0x0004, 0x0005, 0x0006, 0x0007, 0x0008, 0x0009, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
            0x000A, 0x000B, 0x000C, 0x000D, 0x000E, 0x000F, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
            0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x000A, 0x000B,
            0x000C, 0x000D, 0x000E, 0x000F
        };

    /// <summary>
    /// Empty byte array 
    /// </summary>
    private static readonly byte[] Empty = new byte[0];

    /// <summary>
    /// Convert a byte array to a hexadecimal string.
    /// </summary>
    /// <param name="bytes">
    /// The input byte array.
    /// </param>
    /// <returns>
    /// A string of hexadecimal digits.
    /// </returns>
    public static string ToHexString(this byte[] bytes)
    {
        var c = new char[bytes.Length * 2];
        for (int i = 0, j = 0; i < bytes.Length; i++)
        {
            c[j++] = HexDigits[bytes[i] >> 4];
            c[j++] = HexDigits[bytes[i] & 0x0F];
        }

        return new string(c);
    }

    /// <summary>
    /// Parse a string of hexadecimal digits into a byte array.
    /// </summary>
    /// <param name="hexadecimalString">
    /// The hexadecimal string.
    /// </param>
    /// <returns>
    /// The parsed <see cref="byte[]"/> array.
    /// </returns>
    /// <exception cref="ArgumentException">
    /// The input string either contained invalid characters, or was of an odd length.
    /// </exception>
    public static byte[] ToByteArray(string hexadecimalString)
    {
        if (!TryParse(hexadecimalString, out var value))
        {
            throw new ArgumentException("Invalid hexadecimal string", nameof(hexadecimalString));
        }

        return value;
    }

    /// <summary>
    /// Parse a hexadecimal string to bytes
    /// </summary>
    /// <param name="hexadecimalString">
    /// The hexadecimal string, which must be an even number of characters.
    /// </param>
    /// <param name="value">
    /// The parsed value if successful.
    /// </param>
    /// <returns>
    /// True if successful.
    /// </returns>
    public static bool TryParse(string hexadecimalString, out byte[] value)
    {
        if (hexadecimalString.Length == 0)
        {
            value = Empty;
            return true;
        }

        if (hexadecimalString.Length % 2 != 0)
        {
            value = Empty;
            return false;
        }

        try
        {

            value = new byte[hexadecimalString.Length / 2];
            for (int i = 0, j = 0; j < hexadecimalString.Length; i++)
            {
                value[i] = (byte)((HexValues[hexadecimalString[j++] - '0'] << 4)
                                  | HexValues[hexadecimalString[j++] - '0']);
            }

            return true;
        }
        catch (OverflowException)
        {
            value = Empty;
            return false;
        }
    }
}

为了提高性能,我会选择drphrozens解决方案。解码器的一个微小的优化可能是为任一字符使用一个表,以消除“<<4”。

显然,这两个方法调用代价高昂。如果对输入或输出数据进行某种检查(可以是CRC、校验和或其他),则If(b==255)。。。可以跳过,从而也可以完全调用方法。

使用offset++和offset代替offset和offset+1可能会带来一些理论上的好处,但我怀疑编译器比我更好地处理这一点。

private static readonly byte[] LookupTableLow = new byte[] {
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF
};

private static readonly byte[] LookupTableHigh = new byte[] {
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0x00, 0x10, 0x20, 0x30, 0x40, 0x50, 0x60, 0x70, 0x80, 0x90, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xA0, 0xB0, 0xC0, 0xD0, 0xE0, 0xF0, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xA0, 0xB0, 0xC0, 0xD0, 0xE0, 0xF0, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF
};

private static byte LookupLow(char c)
{
  var b = LookupTableLow[c];
  if (b == 255)
    throw new IOException("Expected a hex character, got " + c);
  return b;
}

private static byte LookupHigh(char c)
{
  var b = LookupTableHigh[c];
  if (b == 255)
    throw new IOException("Expected a hex character, got " + c);
  return b;
}

public static byte ToByte(char[] chars, int offset)
{
  return (byte)(LookupHigh(chars[offset++]) | LookupLow(chars[offset]));
}

这只是我的头顶,没有经过测试或基准测试。

用@CodesInChaus补充答案(反向方法)

public static byte[] HexToByteUsingByteManipulation(string s)
{
    byte[] bytes = new byte[s.Length / 2];
    for (int i = 0; i < bytes.Length; i++)
    {
        int hi = s[i*2] - 65;
        hi = hi + 10 + ((hi >> 31) & 7);

        int lo = s[i*2 + 1] - 65;
        lo = lo + 10 + ((lo >> 31) & 7) & 0x0f;

        bytes[i] = (byte) (lo | hi << 4);
    }
    return bytes;
}

说明:

&0x0f还支持小写字母

hi=hi+10+((hi>>31)&7);与以下内容相同:

hi=ch-65+10+((ch-65)>>31)&7);

对于“0”9’与hi=ch-65+10+7相同;其为hi=ch-48(这是因为0xffffff&7)。

对于“A”F’为hi=ch-65+10;(这是因为0x00000000&7)。

对于“a”我们必须使用大数字,所以我们必须通过使用&0x0f使某些位为0,从默认版本中减去32。

65是“A”的代码

48是“0”的代码

7是ASCII表中“9”和“A”之间的字母数(…456789:;<=>?@ABCD…)。