//C++ Simple Code
#include <bits/stdc++.h>
using namespace std;
int main() {
vector<char> alphanum =
    {'0','1','2','3','4',
'5','6','7','8','9',
'A','B','C','D','E','F',
'G','H','I','J','K',
'L','M','N','O','P',
'Q','R','S','T','U',
'V','W','X','Y','Z',
'a','b','c','d','e','f',
'g','h','i','j','k',
'l','m','n','o','p',
'q','r','s','t','u',
'v','w','x','y','z'
};
string s="";
int len=5;
srand(time(0)); 
for (int i = 0; i <len; i++) {
    int t=alphanum.size()-1;
    int idx=rand()%t;
    s+= alphanum[idx];
}
cout<<s<<" ";
return 0;
}

让我们再次让随机变得方便!

我做了一个很好的c++ 11头解决方案。 您可以轻松地将一个头文件添加到项目中，然后将测试添加到项目中，或者将随机字符串用于其他目的。

这是一个快速的描述，但是您可以通过链接查看完整的代码。解决方案的主要部分是在Randomer类中:

class Randomer {
    // random seed by default
    std::mt19937 gen_;
    std::uniform_int_distribution<size_t> dist_;

public:
    /* ... some convenience ctors ... */

    Randomer(size_t min, size_t max, unsigned int seed = std::random_device{}())
        : gen_{seed}, dist_{min, max} {
    }

    // if you want predictable numbers
    void SetSeed(unsigned int seed) {
        gen_.seed(seed);
    }

    size_t operator()() {
        return dist_(gen_);
    }
};

随机封装所有随机的东西，你可以很容易地添加自己的功能。有了Randomer之后，生成字符串就很容易了:

std::string GenerateString(size_t len) {
    std::string str;
    auto rand_char = [](){ return alphabet[randomer()]; };
    std::generate_n(std::back_inserter(str), len, rand_char);
    return str;
}

在下面写下你的改进建议。 https://gist.github.com/VjGusev/e6da2cb4d4b0b531c1d009cd1f8904ad

一些更简单和更基本的东西，如果你想让你的字符串包含任何可打印的字符:

#include <time.h>   // we'll use time for the seed
#include <string.h> // this is for strcpy

void randomString(int size, char* output) // pass the destination size and the destination itself
{
    srand(time(NULL)); // seed with time

    char src[size];
    size = rand() % size; // this randomises the size (optional)

    src[size] = '\0'; // start with the end of the string...

    // ...and work your way backwards
    while(--size > -1)
        src[size] = (rand() % 94) + 32; // generate a string ranging from the space character to ~ (tilde)

    strcpy(output, src); // store the random string
}

我的2p解:

#include <random>
#include <string>

std::string random_string(std::string::size_type length)
{
    static auto& chrs = "0123456789"
        "abcdefghijklmnopqrstuvwxyz"
        "ABCDEFGHIJKLMNOPQRSTUVWXYZ";

    thread_local static std::mt19937 rg{std::random_device{}()};
    thread_local static std::uniform_int_distribution<std::string::size_type> pick(0, sizeof(chrs) - 2);

    std::string s;

    s.reserve(length);

    while(length--)
        s += chrs[pick(rg)];

    return s;
}

这里有一个有趣的单句。需要ASCII。

void gen_random(char *s, int l) {
    for (int c; c=rand()%62, *s++ = (c+"07="[(c+16)/26])*(l-->0););
}

我希望这能帮助到一些人。

在https://www.codechef.com/ide上用c++ 4.9.2测试

#include <iostream>
#include <string>
#include <stdlib.h>     /* srand, rand */

using namespace std;

string RandomString(int len)
{
   string str = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
   string newstr;
   int pos;
   while(newstr.size() != len) {
    pos = ((rand() % (str.size() - 1)));
    newstr += str.substr(pos,1);
   }
   return newstr;
}

int main()
{
   srand(time(0));
   string random_str = RandomString(100);
   cout << "random_str : " << random_str << endl;
}

输出: random_str: DNAT1LAmbJYO0GvVo4LGqYpNcyK3eZ6t0IN3dYpHtRfwheSYipoZOf04gK7OwFIwXg2BHsSBMB84rceaTTCtBC0uZ8JWPdVxKXBd