我想创建一个随机字符串,由字母-数字字符组成。我希望能够指定字符串的长度。
如何在c++中做到这一点?
我想创建一个随机字符串,由字母-数字字符组成。我希望能够指定字符串的长度。
如何在c++中做到这一点?
当前回答
#include <iostream>
#include <string>
#include <random>
std::string generateRandomId(size_t length = 0)
{
static const std::string allowed_chars {"123456789BCDFGHJKLMNPQRSTVWXZbcdfghjklmnpqrstvwxz"};
static thread_local std::default_random_engine randomEngine(std::random_device{}());
static thread_local std::uniform_int_distribution<int> randomDistribution(0, allowed_chars.size() - 1);
std::string id(length ? length : 32, '\0');
for (std::string::value_type& c : id) {
c = allowed_chars[randomDistribution(randomEngine)];
}
return id;
}
int main()
{
std::cout << generateRandomId() << std::endl;
}
其他回答
Qt使用示例:
QString random_string(int length=32, QString allow_symbols=QString("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789")) {
QString result;
qsrand(QTime::currentTime().msec());
for (int i = 0; i < length; ++i) {
result.append(allow_symbols.at(qrand() % (allow_symbols.length())));
}
return result;
}
#include <iostream>
#include <string>
#include <stdlib.h>
int main()
{
int size;
std::cout << "Enter size : ";
std::cin >> size;
std::string str;
for (int i = 0; i < size; i++)
{
auto d = rand() % 26 + 'a';
str.push_back(d);
}
for (int i = 0; i < size; i++)
{
std::cout << str[i] << '\t';
}
return 0;
}
在调用函数时要小心
string gen_random(const int len) {
static const char alphanum[] = "0123456789"
"ABCDEFGHIJKLMNOPQRSTUVWXYZ";
stringstream ss;
for (int i = 0; i < len; ++i) {
ss << alphanum[rand() % (sizeof(alphanum) - 1)];
}
return ss.str();
}
(改编自@Ates Goral)每次都会产生相同的字符序列。使用
srand(time(NULL));
在调用函数之前,rand()函数总是以1 @kjfletch作为种子。
例如:
void SerialNumberGenerator() {
srand(time(NULL));
for (int i = 0; i < 5; i++) {
cout << gen_random(10) << endl;
}
}
void gen_random(char *s, size_t len) {
for (size_t i = 0; i < len; ++i) {
int randomChar = rand()%(26+26+10);
if (randomChar < 26)
s[i] = 'a' + randomChar;
else if (randomChar < 26+26)
s[i] = 'A' + randomChar - 26;
else
s[i] = '0' + randomChar - 26 - 26;
}
s[len] = 0;
}
这里有一个有趣的单句。需要ASCII。
void gen_random(char *s, int l) {
for (int c; c=rand()%62, *s++ = (c+"07="[(c+16)/26])*(l-->0););
}