我需要执行一个动作(清空一个数组),当UINavigationController的后退按钮被按下,而按钮仍然导致堆栈上的前一个ViewController出现。我如何使用swift来实现这一点?


当前回答

override func willMove(toParent parent: UIViewController?)
{
    super.willMove(toParent: parent)
    if parent == nil
    {
        print("This VC is 'will' be popped. i.e. the back button was pressed.")
    }
}

其他回答

当返回按钮按下,忽略交互式弹出与屏幕边缘手势。

override func viewWillDisappear(_ animated: Bool) {
    super.viewWillDisappear(animated)
    
    if isMovingFromParent, transitionCoordinator?.isInteractive == false {
      // code here
    }
  }

这是我自己解决问题的方法

override func viewWillAppear(_ animated: Bool) {
    super.viewWillAppear(animated)
    self.navigationItem.leftBarButtonItem?.action = #selector(self.back(sender:))
    self.navigationItem.leftBarButtonItem?.target = self
}

@objc func back(sender: UIBarButtonItem) {

}

斯威夫特3:

override func didMove(toParentViewController parent: UIViewController?) {
    super.didMove(toParentViewController: parent)

    if parent == nil{
        print("Back button was clicked")
    }
}

Swift 5 __ Xcode 11.5

在我的情况下,我想做一个动画,当它完成后,返回。 一种覆盖后退按钮默认动作的方法 调用你的自定义动作是这样的:

     override func viewDidAppear(_ animated: Bool) {
        super.viewDidAppear(animated)
        setBtnBack()
    }

    private func setBtnBack() {
        for vw in navigationController?.navigationBar.subviews ?? [] where "\(vw.classForCoder)" == "_UINavigationBarContentView" {
            print("\(vw.classForCoder)")
            for subVw in vw.subviews where "\(subVw.classForCoder)" == "_UIButtonBarButton" {
                let ctrl = subVw as! UIControl
                ctrl.removeTarget(ctrl.allTargets.first, action: nil, for: .allEvents)
                ctrl.addTarget(self, action: #selector(backBarBtnAction), for: .touchUpInside)
            }
        }
    }


    @objc func backBarBtnAction() {
        doSomethingBeforeBack { [weak self](isEndedOk) in
            if isEndedOk {
                self?.navigationController?.popViewController(animated: true)
            }
        }
    }


    private func doSomethingBeforeBack(completion: @escaping (_ isEndedOk:Bool)->Void ) {
        UIView.animate(withDuration: 0.25, animations: { [weak self] in
            self?.vwTxt.alpha = 0
        }) { (isEnded) in
            completion(isEnded)
        }
    }

或者你可以使用这个方法一次来探索NavigationBar视图层次结构,并获得访问_UIButtonBarButton视图的索引,转换为UIControl,删除目标-动作,并添加你的自定义目标-动作:

    private func debug_printSubviews(arrSubviews:[UIView]?, level:Int) {
        for (i,subVw) in (arrSubviews ?? []).enumerated() {
            var str = ""
            for _ in 0...level {
                str += "\t"
            }
            str += String(format: "%2d %@",i, "\(subVw.classForCoder)")
            print(str)
            debug_printSubviews(arrSubviews: subVw.subviews, level: level + 1)
        }
    }

    // Set directly the indexs
    private func setBtnBack_method2() {
        // Remove or comment the print lines
        debug_printSubviews(arrSubviews: navigationController?.navigationBar.subviews, level: 0)   
        let ctrl = navigationController?.navigationBar.subviews[1].subviews[0] as! UIControl
        print("ctrl.allTargets: \(ctrl.allTargets)")
        ctrl.removeTarget(ctrl.allTargets.first, action: nil, for: .allEvents)
        print("ctrl.allTargets: \(ctrl.allTargets)")
        ctrl.addTarget(self, action: #selector(backBarBtnAction), for: .touchUpInside)
        print("ctrl.allTargets: \(ctrl.allTargets)")
    }

我通过调用/重写viewWillDisappear来实现这一点,然后像这样访问navigationController的堆栈:

override func viewWillDisappear(animated: Bool) {
    super.viewWillDisappear(animated)

    let stack = self.navigationController?.viewControllers.count

    if stack >= 2 {
        // for whatever reason, the last item on the stack is the TaskBuilderViewController (not self), so we only use -1 to access it
        if let lastitem = self.navigationController?.viewControllers[stack! - 1] as? theViewControllerYoureTryingToAccess {
            // hand over the data via public property or call a public method of theViewControllerYoureTryingToAccess, like
            lastitem.emptyArray()
            lastitem.value = 5
        }
    }
}