给定字符串“ThisStringHasNoSpacesButItDoesHaveCapitals”，什么是在大写字母之前添加空格的最好方法。所以结尾字符串是"This string Has No space But It Does Have大写"
下面是我使用正则表达式的尝试
System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0")
当前回答
这里有一个更彻底的解决方案，它没有在单词前面放空格:
注意:我使用了多个regex(不简洁，但它也可以处理首字母缩略词和单字母单词)
Dim s As String = "ThisStringHasNoSpacesButItDoesHaveCapitals"
s = System.Text.RegularExpressions.Regex.Replace(s, "([a-z])([A-Z](?=[A-Z])[a-z]*)", "$1 $2")
s = System.Text.RegularExpressions.Regex.Replace(s, "([A-Z])([A-Z][a-z])", "$1 $2")
s = System.Text.RegularExpressions.Regex.Replace(s, "([a-z])([A-Z][a-z])", "$1 $2")
s = System.Text.RegularExpressions.Regex.Replace(s, "([a-z])([A-Z][a-z])", "$1 $2") // repeat a second time
In:
"ThisStringHasNoSpacesButItDoesHaveCapitals"
"IAmNotAGoat"
"LOLThatsHilarious!"
"ThisIsASMSMessage"
Out:
"This String Has No Spaces But It Does Have Capitals"
"I Am Not A Goat"
"LOL Thats Hilarious!"
"This Is ASMS Message" // (Difficult to handle single letter words when they are next to acronyms.)
其他回答
private string GetProperName(string Header)
{
if (Header.ToCharArray().Where(c => Char.IsUpper(c)).Count() == 1)
{
return Header;
}
else
{
string ReturnHeader = Header[0].ToString();
for(int i=1; i<Header.Length;i++)
{
if (char.IsLower(Header[i-1]) && char.IsUpper(Header[i]))
{
ReturnHeader += " " + Header[i].ToString();
}
else
{
ReturnHeader += Header[i].ToString();
}
}
return ReturnHeader;
}
return Header;
}
下面是在SQL中如何做到这一点
create FUNCTION dbo.PascalCaseWithSpace(@pInput AS VARCHAR(MAX)) RETURNS VARCHAR(MAX)
BEGIN
declare @output varchar(8000)
set @output = ''
Declare @vInputLength INT
Declare @vIndex INT
Declare @vCount INT
Declare @PrevLetter varchar(50)
SET @PrevLetter = ''
SET @vCount = 0
SET @vIndex = 1
SET @vInputLength = LEN(@pInput)
WHILE @vIndex <= @vInputLength
BEGIN
IF ASCII(SUBSTRING(@pInput, @vIndex, 1)) = ASCII(Upper(SUBSTRING(@pInput, @vIndex, 1)))
begin
if(@PrevLetter != '' and ASCII(@PrevLetter) = ASCII(Lower(@PrevLetter)))
SET @output = @output + ' ' + SUBSTRING(@pInput, @vIndex, 1)
else
SET @output = @output + SUBSTRING(@pInput, @vIndex, 1)
end
else
begin
SET @output = @output + SUBSTRING(@pInput, @vIndex, 1)
end
set @PrevLetter = SUBSTRING(@pInput, @vIndex, 1)
SET @vIndex = @vIndex + 1
END
return @output
END
请确保您没有在字符串的开头放置空格，而是将它们放在连续的大写字母之间。这里的一些答案并没有解决其中的一个或两个问题。除了regex，还有其他方法，但如果你更喜欢使用它，试试这个:
Regex.Replace(value, @"\B[A-Z]", " $0")
\B是一个负的\B，所以它代表一个非单词边界。这意味着模式匹配XYzabc中的“Y”，但不匹配Yzabc或XYzabc。作为一个小奖励，你可以在一个有空格的字符串上使用它，它不会使它们加倍。
具有fold的实现，也称为Aggregate:
public static string SpaceCapitals(this string arg) =>
new string(arg.Aggregate(new List<Char>(),
(accum, x) =>
{
if (Char.IsUpper(x) &&
accum.Any() &&
// prevent double spacing
accum.Last() != ' ' &&
// prevent spacing acronyms (ASCII, SCSI)
!Char.IsUpper(accum.Last()))
{
accum.Add(' ');
}
accum.Add(x);
return accum;
}).ToArray());
除了请求之外，这个实现还正确地保存了开头、内部、结尾空格和首字母缩写，例如，
" SpacedWord " => " Spaced Word ",
"Inner Space" => "Inner Space",
"SomeACRONYM" => "Some ACRONYM".
我想用这个
string InsertSpace(string text ) {
return string.Join("" , text.Select(ch => char.IsUpper(ch) ? " " : "" + ch)) ;
}
