给定字符串“ThisStringHasNoSpacesButItDoesHaveCapitals”,什么是在大写字母之前添加空格的最好方法。所以结尾字符串是"This string Has No space But It Does Have大写"
下面是我使用正则表达式的尝试
System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0")
给定字符串“ThisStringHasNoSpacesButItDoesHaveCapitals”,什么是在大写字母之前添加空格的最好方法。所以结尾字符串是"This string Has No space But It Does Have大写"
下面是我使用正则表达式的尝试
System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0")
当前回答
在小写字母、大写字母或数字后添加空格的简单方法。
string AddSpacesToSentence(string value, bool spaceLowerChar = true, bool spaceDigitChar = true, bool spaceSymbolChar = false)
{
var result = "";
for (int i = 0; i < value.Length; i++)
{
char currentChar = value[i];
char nextChar = value[i < value.Length - 1 ? i + 1 : value.Length - 1];
if (spaceLowerChar && char.IsLower(currentChar) && !char.IsLower(nextChar))
{
result += value[i] + " ";
}
else if (spaceDigitChar && char.IsDigit(currentChar) && !char.IsDigit(nextChar))
{
result += value[i] + " ";
}
else if(spaceSymbolChar && char.IsSymbol(currentChar) && !char.IsSymbol(nextChar))
{
result += value[i];
}
else
{
result += value[i];
}
}
return result;
}
其他回答
你拥有的一切都很完美。只需要记住将value重新赋值给这个函数的返回值即可。
value = System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0");
在小写字母、大写字母或数字后添加空格的简单方法。
string AddSpacesToSentence(string value, bool spaceLowerChar = true, bool spaceDigitChar = true, bool spaceSymbolChar = false)
{
var result = "";
for (int i = 0; i < value.Length; i++)
{
char currentChar = value[i];
char nextChar = value[i < value.Length - 1 ? i + 1 : value.Length - 1];
if (spaceLowerChar && char.IsLower(currentChar) && !char.IsLower(nextChar))
{
result += value[i] + " ";
}
else if (spaceDigitChar && char.IsDigit(currentChar) && !char.IsDigit(nextChar))
{
result += value[i] + " ";
}
else if(spaceSymbolChar && char.IsSymbol(currentChar) && !char.IsSymbol(nextChar))
{
result += value[i];
}
else
{
result += value[i];
}
}
return result;
}
没有测试性能,但在linq的一行中:
var val = "ThisIsAStringToTest";
val = string.Concat(val.Select(x => Char.IsUpper(x) ? " " + x : x.ToString())).TrimStart(' ');
replaceAll("(?<=[^^\\p{Uppercase}])(?=[\\p{Uppercase}])"," ");
下面是在SQL中如何做到这一点
create FUNCTION dbo.PascalCaseWithSpace(@pInput AS VARCHAR(MAX)) RETURNS VARCHAR(MAX)
BEGIN
declare @output varchar(8000)
set @output = ''
Declare @vInputLength INT
Declare @vIndex INT
Declare @vCount INT
Declare @PrevLetter varchar(50)
SET @PrevLetter = ''
SET @vCount = 0
SET @vIndex = 1
SET @vInputLength = LEN(@pInput)
WHILE @vIndex <= @vInputLength
BEGIN
IF ASCII(SUBSTRING(@pInput, @vIndex, 1)) = ASCII(Upper(SUBSTRING(@pInput, @vIndex, 1)))
begin
if(@PrevLetter != '' and ASCII(@PrevLetter) = ASCII(Lower(@PrevLetter)))
SET @output = @output + ' ' + SUBSTRING(@pInput, @vIndex, 1)
else
SET @output = @output + SUBSTRING(@pInput, @vIndex, 1)
end
else
begin
SET @output = @output + SUBSTRING(@pInput, @vIndex, 1)
end
set @PrevLetter = SUBSTRING(@pInput, @vIndex, 1)
SET @vIndex = @vIndex + 1
END
return @output
END