比如@NET3的解决方案。使用shift而不是除法来测试字节的范围，因为除法占用更多的CPU成本。

private static readonly string[] UNITS = new string[] { "B", "KB", "MB", "GB", "TB", "PB", "EB" };

public static string FormatSize(ulong bytes)
{
    int c = 0;
    for (c = 0; c < UNITS.Length; c++)
    {
        ulong m = (ulong)1 << ((c + 1) * 10);
        if (bytes < m)
            break;
    }

    double n = bytes / (double)((ulong)1 << (c * 10));
    return string.Format("{0:0.##} {1}", n, UNITS[c]);
}

又多了一种方法，不管怎样。我喜欢上面提到的@humbads优化解决方案，所以复制了原理，但我实现了一点不同。

我认为它是否应该是一个扩展方法是有争议的(因为不是所有的long都必须是字节大小)，但我喜欢它们，当我下次需要它时，我可以在某个地方找到它!

关于单位，我想我从来没有说过“Kibibyte”或“Mebibyte”，虽然我对这种强制而非进化的标准持怀疑态度，但我认为从长远来看，这将避免混淆。

public static class LongExtensions
{
    private static readonly long[] numberOfBytesInUnit;
    private static readonly Func<long, string>[] bytesToUnitConverters;

    static LongExtensions()
    {
        numberOfBytesInUnit = new long[6]    
        {
            1L << 10,    // Bytes in a Kibibyte
            1L << 20,    // Bytes in a Mebibyte
            1L << 30,    // Bytes in a Gibibyte
            1L << 40,    // Bytes in a Tebibyte
            1L << 50,    // Bytes in a Pebibyte
            1L << 60     // Bytes in a Exbibyte
        };

        // Shift the long (integer) down to 1024 times its number of units, convert to a double (real number), 
        // then divide to get the final number of units (units will be in the range 1 to 1023.999)
        Func<long, int, string> FormatAsProportionOfUnit = (bytes, shift) => (((double)(bytes >> shift)) / 1024).ToString("0.###");

        bytesToUnitConverters = new Func<long,string>[7]
        {
            bytes => bytes.ToString() + " B",
            bytes => FormatAsProportionOfUnit(bytes, 0) + " KiB",
            bytes => FormatAsProportionOfUnit(bytes, 10) + " MiB",
            bytes => FormatAsProportionOfUnit(bytes, 20) + " GiB",
            bytes => FormatAsProportionOfUnit(bytes, 30) + " TiB",
            bytes => FormatAsProportionOfUnit(bytes, 40) + " PiB",
            bytes => FormatAsProportionOfUnit(bytes, 50) + " EiB",
        };
    }

    public static string ToReadableByteSizeString(this long bytes)
    {
        if (bytes < 0)
            return "-" + Math.Abs(bytes).ToReadableByteSizeString();

        int counter = 0;
        while (counter < numberOfBytesInUnit.Length)
        {
            if (bytes < numberOfBytesInUnit[counter])
                return bytesToUnitConverters[counter](bytes);
            counter++;
        }
        return bytesToUnitConverters[counter](bytes);
    }
}

检查我的ByteSize库。这是系统的问题。TimeSpan for bytes!

它为您处理转换和格式化。

var maxFileSize = ByteSize.FromKiloBytes(10);
maxFileSize.Bytes;
maxFileSize.MegaBytes;
maxFileSize.GigaBytes;

它还可以进行字符串表示和解析。

// ToString
ByteSize.FromKiloBytes(1024).ToString(); // 1 MB
ByteSize.FromGigabytes(.5).ToString();   // 512 MB
ByteSize.FromGigabytes(1024).ToString(); // 1 TB

// Parsing
ByteSize.Parse("5b");
ByteSize.Parse("1.55B");

下面是@ deepe1的BigInteger版本的答案，它绕过了long的大小限制(因此支持yottabyte和理论上的任何后面的限制):

public static string ToBytesString(this BigInteger byteCount, string format = "N3")
{
    string[] suf = { "B", "KiB", "MiB", "GiB", "TiB", "PiB", "EiB", "YiB" };
    if (byteCount.IsZero)
    {
        return $"{0.0.ToString(format)} {suf[0]}";
    }

    var abs = BigInteger.Abs(byteCount);
    var place = Convert.ToInt32(Math.Floor(BigInteger.Log(abs, 1024)));
    var pow = Math.Pow(1024, place);

    // since we need to do this with integer math, get the quotient and remainder
    var quotient = BigInteger.DivRem(abs, new BigInteger(pow), out var remainder);
    // convert the remainder to a ratio and add both back together as doubles
    var num = byteCount.Sign * (Math.Floor((double)quotient) + ((double)remainder / pow));

    return $"{num.ToString(format)} {suf[place]}";
}

这里没有什么东西完全符合我的需要，我根据这个线程制作了我自己的，所以这里是我的长扩展，允许您根据标准选择格式要求。

绝对不是最快的，但很灵活。支持EB/EiB。

// <summary>
/// <paramref name="byteCount"/> The original size in bytes ( 8 bits )
/// <paramref name="notationFormat"/> is supported in the following ways:
/// [    'B' / 'b' : Binary :   Kilobyte (KB) is 1024 bytes, Megabyte (MB) is 1048576 bytes, etc    ]
/// [    'I' / 'i' : IEC:       Kibibyte (KiB) is 1024 bytes, Mebibyte (MiB) is 1048576 bytes, etc    ]
/// [    'D' / 'd' : Decimal :  Kilobyte (KB) is 1000 bytes, Megabyte (MB) is 1000000 bytes, etc    ]
/// </summary>

public static string ToDataSizeString( this long byteCount, char notationFormat = 'b' )
{
    char[] supportedFormatChars = { 'b', 'i', 'd' };

    var lowerCaseNotationFormat = char.ToLowerInvariant( notationFormat );

    // Stop shooting holes in my ship!
    if ( !supportedFormatChars.Contains( lowerCaseNotationFormat ) )
    {
        throw new ArgumentException( $"notationFormat argument '{notationFormat}' not supported" );
    }

    long ebLimit = 1152921504606846976;
    long pbLimit = 1125899906842624;
    long tbLimit = 1099511627776;
    long gbLimit = 1073741824;
    long mbLimit = 1048576;
    long kbLimit = 1024;

    var ebSuffix = "EB";
    var pbSuffix = "PB";
    var tbSuffix = "TB";
    var gbSuffix = "GB";
    var mbSuffix = "MB";
    var kbSuffix = "KB";
    var bSuffix  = " B";

    switch ( lowerCaseNotationFormat )
    {
        case 'b':
            // Sweet as
            break;

        case 'i':
            // Limits stay the same, suffixes need changed
            ebSuffix = "EiB";
            pbSuffix = "PiB";
            tbSuffix = "TiB";
            gbSuffix = "GiB";
            mbSuffix = "MiB";
            kbSuffix = "KiB";
            bSuffix  = "  B";
            break;

        case 'd':
            // Suffixes stay the same, limits need changed
            ebLimit = 1000000000000000000;
            pbLimit = 1000000000000000;
            tbLimit = 1000000000000;
            gbLimit = 1000000000;
            mbLimit = 1000000;
            kbLimit = 1000;
            break;

        default:
            // Should have already Excepted, but hey whatever
            throw new ArgumentException( $"notationFormat argument '{notationFormat}' not supported" );

    }

    string fileSizeText;

    // Exa/Exbi sized
    if ( byteCount >= ebLimit )
    {
        fileSizeText = $"{( (double)byteCount / ebLimit ):N1} {ebSuffix}";
    }
    // Peta/Pebi sized
    else if ( byteCount >= pbLimit )
    {
        fileSizeText = $"{( (double)byteCount / pbLimit ):N1} {pbSuffix}";
    }
    // Tera/Tebi sized
    else if ( byteCount >= tbLimit )
    {
        fileSizeText = $"{( (double)byteCount / tbLimit ):N1} {tbSuffix}";
    }
    // Giga/Gibi sized
    else if ( byteCount >= gbLimit )
    {
        fileSizeText = $"{( (double)byteCount / gbLimit ):N1} {gbSuffix}";
    }
    // Mega/Mibi sized
    else if ( byteCount >= mbLimit )
    {
        fileSizeText = $"{( (double)byteCount / mbLimit ):N1} {mbSuffix}";
    }
    // Kilo/Kibi sized
    else if ( byteCount >= kbLimit )
    {
        fileSizeText = $"{( (double)byteCount / kbLimit ):N1} {kbSuffix}";
    }
    // Byte sized
    else
    {
        fileSizeText = $"{byteCount} {bSuffix}";
    }

    return fileSizeText;
}

我猜你要找的是“1.4 MB”而不是“1468006字节”?

我不认为在。net中有内置的方法来做到这一点。你只需要找出哪个单元是合适的，然后格式化它。

编辑:这里有一些示例代码来做到这一点:

http://www.codeproject.com/KB/cpp/formatsize.aspx