为了完成这个答案，它可以这样工作……

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
   case UIRemoteNotificationTypeAlert:
   case UIRemoteNotificationTypeBadge:
       // For enabled code
       break;
   case UIRemoteNotificationTypeSound:
   case UIRemoteNotificationTypeNone:
   default:
       // For disabled code
       break;
}

编辑:这是不对的。因为这些是位智慧的东西，它不会与开关工作，所以我结束使用这个:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
    CeldaSwitch.chkSwitch.on = true;
}
else
{
    CeldaSwitch.chkSwitch.on = false;
}

这个Swifty解决方案对我来说效果很好(iOS8+)，

方法:

func isNotificationEnabled(completion:@escaping (_ enabled:Bool)->()){
    if #available(iOS 10.0, *) {
        UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
            let status =  (settings.authorizationStatus == .authorized)
            completion(status)
        })
    } else {
        if let status = UIApplication.shared.currentUserNotificationSettings?.types{
            let status = status.rawValue != UIUserNotificationType(rawValue: 0).rawValue
            completion(status)
        }else{
            completion(false)
        }
    }
}

用法:

isNotificationEnabled { (isEnabled) in
            if isEnabled{
                print("Push notification enabled")
            }else{
                print("Push notification not enabled")
            }
        }

Ref

为了完成这个答案，它可以这样工作……

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
   case UIRemoteNotificationTypeAlert:
   case UIRemoteNotificationTypeBadge:
       // For enabled code
       break;
   case UIRemoteNotificationTypeSound:
   case UIRemoteNotificationTypeNone:
   default:
       // For disabled code
       break;
}

编辑:这是不对的。因为这些是位智慧的东西，它不会与开关工作，所以我结束使用这个:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
    CeldaSwitch.chkSwitch.on = true;
}
else
{
    CeldaSwitch.chkSwitch.on = false;
}

完全容易复制和粘贴代码构建从@ZacBowling的解决方案(https://stackoverflow.com/a/1535427/2298002)

这也将把用户带到你的应用程序设置，并允许他们立即启用

我还添加了一个解决方案，用于检查位置服务是否启用(以及带来的设置)

// check if notification service is enabled
+ (void)checkNotificationServicesEnabled
{
    if (![[UIApplication sharedApplication] isRegisteredForRemoteNotifications])
    {
        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Notification Services Disabled!"
                                                            message:@"Yo don't mess around bro! Enabling your Notifications allows you to receive important updates"
                                                           delegate:self
                                                  cancelButtonTitle:@"Cancel"
                                                  otherButtonTitles:@"Settings", nil];

        alertView.tag = 300;

        [alertView show];

        return;
    }
}

// check if location service is enabled (ref: https://stackoverflow.com/a/35982887/2298002)
+ (void)checkLocationServicesEnabled
{
    //Checking authorization status
    if (![CLLocationManager locationServicesEnabled] || [CLLocationManager authorizationStatus] == kCLAuthorizationStatusDenied)
    {

        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Location Services Disabled!"
                                                            message:@"You need to enable your GPS location right now!!"
                                                           delegate:self
                                                  cancelButtonTitle:@"Cancel"
                                                  otherButtonTitles:@"Settings", nil];

        //TODO if user has not given permission to device
        if (![CLLocationManager locationServicesEnabled])
        {
            alertView.tag = 100;
        }
        //TODO if user has not given permission to particular app
        else
        {
            alertView.tag = 200;
        }

        [alertView show];

        return;
    }
}

// handle bringing user to settings for each
+ (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{

    if(buttonIndex == 0)// Cancel button pressed
    {
        //TODO for cancel
    }
    else if(buttonIndex == 1)// Settings button pressed.
    {
        if (alertView.tag == 100)
        {
            //This will open ios devices location settings
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=LOCATION_SERVICES"]];
        }
        else if (alertView.tag == 200)
        {
            //This will open particular app location settings
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];
        }
        else if (alertView.tag == 300)
        {
            //This will open particular app location settings
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];
        }
    }
}

GLHF !

调用enabledremotenotificationsttypes并检查掩码。

例如:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types == UIRemoteNotificationTypeNone) 
   // blah blah blah

iOS8及以上:

[[UIApplication sharedApplication] isRegisteredForRemoteNotifications]

在iOS7和之前，你应该使用enabledRemoteNotificationTypes并检查它是否等于(或不等于取决于你想要什么)UIRemoteNotificationTypeNone。

然而，对于iOS8来说，仅仅检查isregisteredforremotenotifations并不总是足够的，因为上面有许多状态。你还应该检查application.currentUserNotificationSettings.types是否等于(或不等于取决于你想要什么)UIUserNotificationTypeNone!

isregisteredforremotenotifations可能返回true，即使currentUserNotificationSettings。types返回UIUserNotificationTypeNone。