我正在寻找一种方法来确定用户是否有,通过设置,启用或禁用他们的推送通知我的应用程序。


当前回答

斯威夫特 3+

    if #available(iOS 10.0, *) {
        UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
            // settings.authorizationStatus == .authorized
        })
    } else {
        return UIApplication.shared.currentUserNotificationSettings?.types.contains(UIUserNotificationType.alert) ?? false
    }

RxSwift可观察的iOS10+版本:

import UserNotifications
extension UNUserNotificationCenter {
    static var isAuthorized: Observable<Bool> {
        return Observable.create { observer in
            DispatchQueue.main.async {
                current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
                    if settings.authorizationStatus == .authorized {
                        observer.onNext(true)
                        observer.onCompleted()
                    } else {
                        current().requestAuthorization(options: [.badge, .alert, .sound]) { (granted, error) in
                            observer.onNext(granted)
                            observer.onCompleted()
                        }
                    }
                })
            }
            return Disposables.create()
        }
    }
}

其他回答

re:

这是正确的

if (types & UIRemoteNotificationTypeAlert)

但是下面也是正确的!(因为UIRemoteNotificationTypeNone是0)

if (types == UIRemoteNotificationTypeNone) 

参见以下内容

NSLog(@"log:%d",0 & 0); ///false
NSLog(@"log:%d",1 & 1); ///true
NSLog(@"log:%d",1<<1 & 1<<1); ///true
NSLog(@"log:%d",1<<2 & 1<<2); ///true
NSLog(@"log:%d",(0 & 0) && YES); ///false
NSLog(@"log:%d",(1 & 1) && YES); ///true
NSLog(@"log:%d",(1<<1 & 1<<1) && YES); ///true
NSLog(@"log:%d",(1<<2 & 1<<2) && YES); ///true

为了完成这个答案,它可以这样工作……

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
   case UIRemoteNotificationTypeAlert:
   case UIRemoteNotificationTypeBadge:
       // For enabled code
       break;
   case UIRemoteNotificationTypeSound:
   case UIRemoteNotificationTypeNone:
   default:
       // For disabled code
       break;
}

编辑:这是不对的。因为这些是位智慧的东西,它不会与开关工作,所以我结束使用这个:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
    CeldaSwitch.chkSwitch.on = true;
}
else
{
    CeldaSwitch.chkSwitch.on = false;
}

这个Swifty解决方案对我来说效果很好(iOS8+),

方法:

func isNotificationEnabled(completion:@escaping (_ enabled:Bool)->()){
    if #available(iOS 10.0, *) {
        UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
            let status =  (settings.authorizationStatus == .authorized)
            completion(status)
        })
    } else {
        if let status = UIApplication.shared.currentUserNotificationSettings?.types{
            let status = status.rawValue != UIUserNotificationType(rawValue: 0).rawValue
            completion(status)
        }else{
            completion(false)
        }
    }
}

用法:

isNotificationEnabled { (isEnabled) in
            if isEnabled{
                print("Push notification enabled")
            }else{
                print("Push notification not enabled")
            }
        }

Ref

在尝试同时支持iOS8和更低版本时,我并没有像Kevin建议的那样使用isregisteredforremotenotifations。相反,我使用了currentUserNotificationSettings,它在我的测试中工作得很好。

+ (BOOL)notificationServicesEnabled {
    BOOL isEnabled = NO;

    if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]){
        UIUserNotificationSettings *notificationSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];

        if (!notificationSettings || (notificationSettings.types == UIUserNotificationTypeNone)) {
            isEnabled = NO;
        } else {
            isEnabled = YES;
        }
    } else {
        UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
        if (types & UIRemoteNotificationTypeAlert) {
            isEnabled = YES;
        } else{
            isEnabled = NO;
        }
    }

    return isEnabled;
}

在iOS7和之前,你应该使用enabledRemoteNotificationTypes并检查它是否等于(或不等于取决于你想要什么)UIRemoteNotificationTypeNone。

然而,对于iOS8来说,仅仅检查isregisteredforremotenotifations并不总是足够的,因为上面有许多状态。你还应该检查application.currentUserNotificationSettings.types是否等于(或不等于取决于你想要什么)UIUserNotificationTypeNone!

isregisteredforremotenotifations可能返回true,即使currentUserNotificationSettings。types返回UIUserNotificationTypeNone。