我正在寻找一种方法来确定用户是否有,通过设置,启用或禁用他们的推送通知我的应用程序。
当前回答
斯威夫特 3+
if #available(iOS 10.0, *) {
UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
// settings.authorizationStatus == .authorized
})
} else {
return UIApplication.shared.currentUserNotificationSettings?.types.contains(UIUserNotificationType.alert) ?? false
}
RxSwift可观察的iOS10+版本:
import UserNotifications
extension UNUserNotificationCenter {
static var isAuthorized: Observable<Bool> {
return Observable.create { observer in
DispatchQueue.main.async {
current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
if settings.authorizationStatus == .authorized {
observer.onNext(true)
observer.onCompleted()
} else {
current().requestAuthorization(options: [.badge, .alert, .sound]) { (granted, error) in
observer.onNext(granted)
observer.onCompleted()
}
}
})
}
return Disposables.create()
}
}
}
其他回答
re:
这是正确的
if (types & UIRemoteNotificationTypeAlert)
但是下面也是正确的!(因为UIRemoteNotificationTypeNone是0)
if (types == UIRemoteNotificationTypeNone)
参见以下内容
NSLog(@"log:%d",0 & 0); ///false
NSLog(@"log:%d",1 & 1); ///true
NSLog(@"log:%d",1<<1 & 1<<1); ///true
NSLog(@"log:%d",1<<2 & 1<<2); ///true
NSLog(@"log:%d",(0 & 0) && YES); ///false
NSLog(@"log:%d",(1 & 1) && YES); ///true
NSLog(@"log:%d",(1<<1 & 1<<1) && YES); ///true
NSLog(@"log:%d",(1<<2 & 1<<2) && YES); ///true
为了完成这个答案,它可以这样工作……
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
case UIRemoteNotificationTypeAlert:
case UIRemoteNotificationTypeBadge:
// For enabled code
break;
case UIRemoteNotificationTypeSound:
case UIRemoteNotificationTypeNone:
default:
// For disabled code
break;
}
编辑:这是不对的。因为这些是位智慧的东西,它不会与开关工作,所以我结束使用这个:
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
CeldaSwitch.chkSwitch.on = true;
}
else
{
CeldaSwitch.chkSwitch.on = false;
}
这个Swifty解决方案对我来说效果很好(iOS8+),
方法:
func isNotificationEnabled(completion:@escaping (_ enabled:Bool)->()){
if #available(iOS 10.0, *) {
UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
let status = (settings.authorizationStatus == .authorized)
completion(status)
})
} else {
if let status = UIApplication.shared.currentUserNotificationSettings?.types{
let status = status.rawValue != UIUserNotificationType(rawValue: 0).rawValue
completion(status)
}else{
completion(false)
}
}
}
用法:
isNotificationEnabled { (isEnabled) in
if isEnabled{
print("Push notification enabled")
}else{
print("Push notification not enabled")
}
}
Ref
在尝试同时支持iOS8和更低版本时,我并没有像Kevin建议的那样使用isregisteredforremotenotifations。相反,我使用了currentUserNotificationSettings,它在我的测试中工作得很好。
+ (BOOL)notificationServicesEnabled {
BOOL isEnabled = NO;
if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]){
UIUserNotificationSettings *notificationSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];
if (!notificationSettings || (notificationSettings.types == UIUserNotificationTypeNone)) {
isEnabled = NO;
} else {
isEnabled = YES;
}
} else {
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types & UIRemoteNotificationTypeAlert) {
isEnabled = YES;
} else{
isEnabled = NO;
}
}
return isEnabled;
}
在iOS7和之前,你应该使用enabledRemoteNotificationTypes并检查它是否等于(或不等于取决于你想要什么)UIRemoteNotificationTypeNone。
然而,对于iOS8来说,仅仅检查isregisteredforremotenotifations并不总是足够的,因为上面有许多状态。你还应该检查application.currentUserNotificationSettings.types是否等于(或不等于取决于你想要什么)UIUserNotificationTypeNone!
isregisteredforremotenotifations可能返回true,即使currentUserNotificationSettings。types返回UIUserNotificationTypeNone。
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