斯威夫特 3+

    if #available(iOS 10.0, *) {
        UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
            // settings.authorizationStatus == .authorized
        })
    } else {
        return UIApplication.shared.currentUserNotificationSettings?.types.contains(UIUserNotificationType.alert) ?? false
    }

RxSwift可观察的iOS10+版本:

import UserNotifications
extension UNUserNotificationCenter {
    static var isAuthorized: Observable<Bool> {
        return Observable.create { observer in
            DispatchQueue.main.async {
                current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
                    if settings.authorizationStatus == .authorized {
                        observer.onNext(true)
                        observer.onCompleted()
                    } else {
                        current().requestAuthorization(options: [.badge, .alert, .sound]) { (granted, error) in
                            observer.onNext(granted)
                            observer.onCompleted()
                        }
                    }
                })
            }
            return Disposables.create()
        }
    }
}

为了完成这个答案，它可以这样工作……

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
   case UIRemoteNotificationTypeAlert:
   case UIRemoteNotificationTypeBadge:
       // For enabled code
       break;
   case UIRemoteNotificationTypeSound:
   case UIRemoteNotificationTypeNone:
   default:
       // For disabled code
       break;
}

编辑:这是不对的。因为这些是位智慧的东西，它不会与开关工作，所以我结束使用这个:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
    CeldaSwitch.chkSwitch.on = true;
}
else
{
    CeldaSwitch.chkSwitch.on = false;
}

这个Swifty解决方案对我来说效果很好(iOS8+)，

方法:

func isNotificationEnabled(completion:@escaping (_ enabled:Bool)->()){
    if #available(iOS 10.0, *) {
        UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
            let status =  (settings.authorizationStatus == .authorized)
            completion(status)
        })
    } else {
        if let status = UIApplication.shared.currentUserNotificationSettings?.types{
            let status = status.rawValue != UIUserNotificationType(rawValue: 0).rawValue
            completion(status)
        }else{
            completion(false)
        }
    }
}

用法:

isNotificationEnabled { (isEnabled) in
            if isEnabled{
                print("Push notification enabled")
            }else{
                print("Push notification not enabled")
            }
        }

Ref

在Xamarin，以上所有的解决方案都不适合我。 这是我用的:

public static bool IsRemoteNotificationsEnabled() {
    return UIApplication.SharedApplication.CurrentUserNotificationSettings.Types != UIUserNotificationType.None;
}

当你在设置中更改通知状态后，它也会得到实时更新。

我尝试使用@Shaheen ghassy提供的解决方案支持iOS 10及以上版本，但发现剥夺问题enabledRemoteNotificationTypes。所以，我找到的解决方案是使用isregisteredforremotenotification而不是enabledRemoteNotificationTypes，这在iOS 8中已弃用。下面是我最新的解决方案，对我来说非常有效:

- (BOOL)notificationServicesEnabled {
    BOOL isEnabled = NO;
    if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]){
        UIUserNotificationSettings *notificationSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];

        if (!notificationSettings || (notificationSettings.types == UIUserNotificationTypeNone)) {
            isEnabled = NO;
        } else {
            isEnabled = YES;
        }
    } else {

        if ([[UIApplication sharedApplication] isRegisteredForRemoteNotifications]) {
            isEnabled = YES;
        } else{
            isEnabled = NO;
        }
    }
    return isEnabled;
}

我们可以很容易地调用这个函数，访问它的Bool值，并将其转换为字符串值:

NSString *str = [self notificationServicesEnabled] ? @"YES" : @"NO";

希望它也能帮助到其他人:) 快乐的编码。

调用enabledremotenotificationsttypes并检查掩码。

例如:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types == UIRemoteNotificationTypeNone) 
   // blah blah blah

iOS8及以上:

[[UIApplication sharedApplication] isRegisteredForRemoteNotifications]