我正在寻找一种方法来确定用户是否有,通过设置,启用或禁用他们的推送通知我的应用程序。
当前回答
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types & UIRemoteNotificationTypeAlert)
// blah blah blah
{
NSLog(@"Notification Enabled");
}
else
{
NSLog(@"Notification not enabled");
}
这里我们从UIApplication获得UIRemoteNotificationType。它代表了这个应用程序在设置中的推送通知的状态,然后你可以很容易地检查它的类型
其他回答
调用enabledremotenotificationsttypes并检查掩码。
例如:
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types == UIRemoteNotificationTypeNone)
// blah blah blah
iOS8及以上:
[[UIApplication sharedApplication] isRegisteredForRemoteNotifications]
斯威夫特 3+
if #available(iOS 10.0, *) {
UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
// settings.authorizationStatus == .authorized
})
} else {
return UIApplication.shared.currentUserNotificationSettings?.types.contains(UIUserNotificationType.alert) ?? false
}
RxSwift可观察的iOS10+版本:
import UserNotifications
extension UNUserNotificationCenter {
static var isAuthorized: Observable<Bool> {
return Observable.create { observer in
DispatchQueue.main.async {
current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
if settings.authorizationStatus == .authorized {
observer.onNext(true)
observer.onCompleted()
} else {
current().requestAuthorization(options: [.badge, .alert, .sound]) { (granted, error) in
observer.onNext(granted)
observer.onCompleted()
}
}
})
}
return Disposables.create()
}
}
}
这个Swifty解决方案对我来说效果很好(iOS8+),
方法:
func isNotificationEnabled(completion:@escaping (_ enabled:Bool)->()){
if #available(iOS 10.0, *) {
UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
let status = (settings.authorizationStatus == .authorized)
completion(status)
})
} else {
if let status = UIApplication.shared.currentUserNotificationSettings?.types{
let status = status.rawValue != UIUserNotificationType(rawValue: 0).rawValue
completion(status)
}else{
completion(false)
}
}
}
用法:
isNotificationEnabled { (isEnabled) in
if isEnabled{
print("Push notification enabled")
}else{
print("Push notification not enabled")
}
}
Ref
下面是如何在Xamarin.ios中做到这一点。
public class NotificationUtils
{
public static bool AreNotificationsEnabled ()
{
var settings = UIApplication.SharedApplication.CurrentUserNotificationSettings;
var types = settings.Types;
return types != UIUserNotificationType.None;
}
}
如果你支持iOS 10+,只使用UNUserNotificationCenter方法。
我尝试使用@Shaheen ghassy提供的解决方案支持iOS 10及以上版本,但发现剥夺问题enabledRemoteNotificationTypes。所以,我找到的解决方案是使用isregisteredforremotenotification而不是enabledRemoteNotificationTypes,这在iOS 8中已弃用。下面是我最新的解决方案,对我来说非常有效:
- (BOOL)notificationServicesEnabled {
BOOL isEnabled = NO;
if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]){
UIUserNotificationSettings *notificationSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];
if (!notificationSettings || (notificationSettings.types == UIUserNotificationTypeNone)) {
isEnabled = NO;
} else {
isEnabled = YES;
}
} else {
if ([[UIApplication sharedApplication] isRegisteredForRemoteNotifications]) {
isEnabled = YES;
} else{
isEnabled = NO;
}
}
return isEnabled;
}
我们可以很容易地调用这个函数,访问它的Bool值,并将其转换为字符串值:
NSString *str = [self notificationServicesEnabled] ? @"YES" : @"NO";
希望它也能帮助到其他人:) 快乐的编码。
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