如何在Python中连接两个列表?

例子:

listone = [1, 2, 3]
listtwo = [4, 5, 6]

预期结果:

>>> joinedlist
[1, 2, 3, 4, 5, 6]

当前回答

可以使用集合获取唯一值的合并列表

mergedlist = list(set(listone + listtwo))

其他回答

我能找到的加入列表的所有可能方法

import itertools

A = [1,3,5,7,9] + [2,4,6,8,10]

B = [1,3,5,7,9]
B.append([2,4,6,8,10])

C = [1,3,5,7,9]
C.extend([2,4,6,8,10])

D = list(zip([1,3,5,7,9],[2,4,6,8,10]))
E = [1,3,5,7,9]+[2,4,6,8,10]
F = list(set([1,3,5,7,9] + [2,4,6,8,10]))

G = []
for a in itertools.chain([1,3,5,7,9], [2,4,6,8,10]):
    G.append(a)


print("A: " + str(A))
print("B: " + str(B))
print("C: " + str(C))
print("D: " + str(D))
print("E: " + str(E))
print("F: " + str(F))
print("G: " + str(G))

输出

A: [1, 3, 5, 7, 9, 2, 4, 6, 8, 10]
B: [1, 3, 5, 7, 9, [2, 4, 6, 8, 10]]
C: [1, 3, 5, 7, 9, 2, 4, 6, 8, 10]
D: [(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)]
E: [1, 3, 5, 7, 9, 2, 4, 6, 8, 10]
F: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
G: [1, 3, 5, 7, 9, 2, 4, 6, 8, 10]

使用+运算符组合列表:

listone = [1, 2, 3]
listtwo = [4, 5, 6]

joinedlist = listone + listtwo

输出:

>>> joinedlist
[1, 2, 3, 4, 5, 6]

这很简单,我认为它甚至在教程中显示了:

>>> listone = [1,2,3]
>>> listtwo = [4,5,6]
>>>
>>> listone + listtwo
[1, 2, 3, 4, 5, 6]

如果使用的是NumPy,可以使用以下命令连接两个兼容维度的数组:

numpy.concatenate([a,b])

这个问题直接询问加入两个列表。然而,即使您正在寻找一种连接多个列表的方法(包括连接零个列表的情况),它在搜索中也非常高。

我认为最好的选择是使用列表综合:

>>> a = [[1,2,3], [4,5,6], [7,8,9]]
>>> [x for xs in a for x in xs]
[1, 2, 3, 4, 5, 6, 7, 8, 9]

还可以创建生成器:

>>> map(str, (x for xs in a for x in xs))
['1', '2', '3', '4', '5', '6', '7', '8', '9']

旧答案

考虑这种更通用的方法:

a = [[1,2,3], [4,5,6], [7,8,9]]
reduce(lambda c, x: c + x, a, [])

将输出:

[1, 2, 3, 4, 5, 6, 7, 8, 9]

注意,当a为[]或[[1,2,3]]时,这也可以正常工作。

然而,使用itertools可以更有效地实现这一点:

a = [[1,2,3], [4,5,6], [7,8,9]]
list(itertools.chain(*a))

如果您不需要列表,而只需要一个可迭代的列表,请省略list()。

使现代化

Patrick Collins在评论中提出的备选方案也适用于您:

sum(a, [])