如何将以下字符串转换为datetime对象?
"Jun 1 2005 1:33PM"
如何将以下字符串转换为datetime对象?
"Jun 1 2005 1:33PM"
当前回答
#Convert String to datetime
>>> x=datetime.strptime('Jun 1 2005', '%b %d %Y').date()
>>> print(x,type(x))
2005-06-01 00:00:00 <class 'datetime.datetime'>
#Convert datetime to String (Reverse above process)
>>> y=x.strftime('%b %d %Y')
>>> print(y,type(y))
Jun 01 2005 <class 'str'>
其他回答
以下是使用Pandas将格式化为字符串的日期转换为datetime.date对象的两种解决方案。
import pandas as pd
dates = ['2015-12-25', '2015-12-26']
# 1) Use a list comprehension.
>>> [d.date() for d in pd.to_datetime(dates)]
[datetime.date(2015, 12, 25), datetime.date(2015, 12, 26)]
# 2) Convert the dates to a DatetimeIndex and extract the python dates.
>>> pd.DatetimeIndex(dates).date.tolist()
[datetime.date(2015, 12, 25), datetime.date(2015, 12, 26)]
计时
dates = pd.DatetimeIndex(start='2000-1-1', end='2010-1-1', freq='d').date.tolist()
>>> %timeit [d.date() for d in pd.to_datetime(dates)]
# 100 loops, best of 3: 3.11 ms per loop
>>> %timeit pd.DatetimeIndex(dates).date.tolist()
# 100 loops, best of 3: 6.85 ms per loop
下面是如何转换OP的原始日期时间示例:
datetimes = ['Jun 1 2005 1:33PM', 'Aug 28 1999 12:00AM']
>>> pd.to_datetime(datetimes).to_pydatetime().tolist()
[datetime.datetime(2005, 6, 1, 13, 33),
datetime.datetime(1999, 8, 28, 0, 0)]
使用to_datetime将字符串转换为Pandas时间戳有很多选项,因此如果需要任何特殊信息,请查看文档。
同样,除了.date之外,时间戳还有许多可以访问的财产和方法
arrow为日期和时间提供了许多有用的函数。这段代码为这个问题提供了答案,并表明箭头还能够轻松格式化日期并显示其他地区的信息。
>>> import arrow
>>> dateStrings = [ 'Jun 1 2005 1:33PM', 'Aug 28 1999 12:00AM' ]
>>> for dateString in dateStrings:
... dateString
... arrow.get(dateString.replace(' ',' '), 'MMM D YYYY H:mmA').datetime
... arrow.get(dateString.replace(' ',' '), 'MMM D YYYY H:mmA').format('ddd, Do MMM YYYY HH:mm')
... arrow.get(dateString.replace(' ',' '), 'MMM D YYYY H:mmA').humanize(locale='de')
...
'Jun 1 2005 1:33PM'
datetime.datetime(2005, 6, 1, 13, 33, tzinfo=tzutc())
'Wed, 1st Jun 2005 13:33'
'vor 11 Jahren'
'Aug 28 1999 12:00AM'
datetime.datetime(1999, 8, 28, 0, 0, tzinfo=tzutc())
'Sat, 28th Aug 1999 00:00'
'vor 17 Jahren'
看见http://arrow.readthedocs.io/en/latest/了解更多信息。
这里没有提到但很有用的一点:在当天添加后缀。我解耦了后缀逻辑,这样你就可以将它用于任何你喜欢的数字,而不仅仅是日期。
import time
def num_suffix(n):
'''
Returns the suffix for any given int
'''
suf = ('th','st', 'nd', 'rd')
n = abs(n) # wise guy
tens = int(str(n)[-2:])
units = n % 10
if tens > 10 and tens < 20:
return suf[0] # teens with 'th'
elif units <= 3:
return suf[units]
else:
return suf[0] # 'th'
def day_suffix(t):
'''
Returns the suffix of the given struct_time day
'''
return num_suffix(t.tm_mday)
# Examples
print num_suffix(123)
print num_suffix(3431)
print num_suffix(1234)
print ''
print day_suffix(time.strptime("1 Dec 00", "%d %b %y"))
print day_suffix(time.strptime("2 Nov 01", "%d %b %y"))
print day_suffix(time.strptime("3 Oct 02", "%d %b %y"))
print day_suffix(time.strptime("4 Sep 03", "%d %b %y"))
print day_suffix(time.strptime("13 Nov 90", "%d %b %y"))
print day_suffix(time.strptime("14 Oct 10", "%d %b %y"))
如果您的字符串是ISO 8601格式,并且您有Python 3.7+,则可以使用以下简单代码:
import datetime
aDate = datetime.date.fromisoformat('2020-10-04')
日期和
import datetime
aDateTime = datetime.datetime.fromisoformat('2020-10-04 22:47:00')
用于包含日期和时间的字符串。如果包含时间戳,函数datetime.datetime.isoformat()支持以下格式:
YYYY-MM-DD[*HH[:MM[:SS[.fff[fff]]]][+HH:MM[:SS[.ffffff]]]]
其中*匹配任何单个字符。另请参见此处和此处。
如果您不想明确指定字符串相对于日期时间格式的格式,可以使用此黑客绕过该步骤:
from dateutil.parser import parse
# Function that'll guess the format and convert it into the python datetime format
def update_event(start_datetime=None, end_datetime=None, description=None):
if start_datetime is not None:
new_start_time = parse(start_datetime)
return new_start_time
# Sample input dates in different formats
d = ['06/07/2021 06:40:23.277000', '06/07/2021 06:40', '06/07/2021']
new = [update_event(i) for i in d]
for date in new:
print(date)
# Sample output dates in Python datetime object
# 2014-04-23 00:00:00
# 2013-04-24 00:00:00
# 2014-04-25 00:00:00
如果要将其转换为其他日期时间格式,只需使用您喜欢的格式修改最后一行,例如date.strftime(“%Y/%m/%d%H:%m:%S.%f”):
from dateutil.parser import parse
def update_event(start_datetime=None, end_datetime=None, description=None):
if start_datetime is not None:
new_start_time = parse(start_datetime)
return new_start_time
# Sample input dates in different formats
d = ['06/07/2021 06:40:23.277000', '06/07/2021 06:40', '06/07/2021']
# Passing the dates one by one through the function
new = [update_event(i) for i in d]
for date in new:
print(date.strftime('%Y/%m/%d %H:%M:%S.%f'))
# Sample output dates in required Python datetime object
# 2021/06/07 06:40:23.277000
# 2021/06/07 06:40:00.000000
# 2021/06/07 00:00:00.000000
尝试运行上面的代码段以获得更好的清晰度。