比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
当前回答
我想提供我的选项解析版本,它允许以下内容:
-s p1
--stage p1
-w somefolder
--workfolder somefolder
-sw p1 somefolder
-e=hello
也允许这样做(可能不需要):
-s--workfolder p1 somefolder
-se=hello p1
-swe=hello p1 somefolder
您必须在使用前决定是否在选项上使用=。这是为了保持代码干净。
while [[ $# > 0 ]]
do
key="$1"
while [[ ${key+x} ]]
do
case $key in
-s*|--stage)
STAGE="$2"
shift # option has parameter
;;
-w*|--workfolder)
workfolder="$2"
shift # option has parameter
;;
-e=*)
EXAMPLE="${key#*=}"
break # option has been fully handled
;;
*)
# unknown option
echo Unknown option: $key #1>&2
exit 10 # either this: my preferred way to handle unknown options
break # or this: do this to signal the option has been handled (if exit isn't used)
;;
esac
# prepare for next option in this key, if any
[[ "$key" = -? || "$key" == --* ]] && unset key || key="${key/#-?/-}"
done
shift # option(s) fully processed, proceed to next input argument
done
其他回答
我想提供我的选项解析版本,它允许以下内容:
-s p1
--stage p1
-w somefolder
--workfolder somefolder
-sw p1 somefolder
-e=hello
也允许这样做(可能不需要):
-s--workfolder p1 somefolder
-se=hello p1
-swe=hello p1 somefolder
您必须在使用前决定是否在选项上使用=。这是为了保持代码干净。
while [[ $# > 0 ]]
do
key="$1"
while [[ ${key+x} ]]
do
case $key in
-s*|--stage)
STAGE="$2"
shift # option has parameter
;;
-w*|--workfolder)
workfolder="$2"
shift # option has parameter
;;
-e=*)
EXAMPLE="${key#*=}"
break # option has been fully handled
;;
*)
# unknown option
echo Unknown option: $key #1>&2
exit 10 # either this: my preferred way to handle unknown options
break # or this: do this to signal the option has been handled (if exit isn't used)
;;
esac
# prepare for next option in this key, if any
[[ "$key" = -? || "$key" == --* ]] && unset key || key="${key/#-?/-}"
done
shift # option(s) fully processed, proceed to next input argument
done
这是我使用变量数组对Bruno Bronosky答案的改进解决方案。
它允许您混合参数位置,并为您提供一个参数数组,该数组在没有选项的情况下保持顺序
#!/bin/bash
echo $@
PARAMS=()
SOFT=0
SKIP=()
for i in "$@"
do
case $i in
-n=*|--skip=*)
SKIP+=("${i#*=}")
;;
-s|--soft)
SOFT=1
;;
*)
# unknown option
PARAMS+=("$i")
;;
esac
done
echo "SKIP = ${SKIP[@]}"
echo "SOFT = $SOFT"
echo "Parameters:"
echo ${PARAMS[@]}
将输出例如:
$ ./test.sh parameter -s somefile --skip=.c --skip=.obj
parameter -s somefile --skip=.c --skip=.obj
SKIP = .c .obj
SOFT = 1
Parameters:
parameter somefile
在@brunobronosky的回答基础上,我添加了一个“预处理器”来处理一些常见的格式:
将--longopt=val展开为--longopt-val将-xyz展开为-x-y-z支持--表示标志的结束显示意外选项的错误小巧易读的选项开关
#!/bin/bash
# Report usage
usage() {
echo "Usage:"
echo "$(basename "$0") [options] [--] [file1, ...]"
}
invalid() {
echo "ERROR: Unrecognized argument: $1" >&2
usage
exit 1
}
# Pre-process options to:
# - expand -xyz into -x -y -z
# - expand --longopt=arg into --longopt arg
ARGV=()
END_OF_OPT=
while [[ $# -gt 0 ]]; do
arg="$1"; shift
case "${END_OF_OPT}${arg}" in
--) ARGV+=("$arg"); END_OF_OPT=1 ;;
--*=*)ARGV+=("${arg%%=*}" "${arg#*=}") ;;
--*) ARGV+=("$arg") ;;
-*) for i in $(seq 2 ${#arg}); do ARGV+=("-${arg:i-1:1}"); done ;;
*) ARGV+=("$arg") ;;
esac
done
# Apply pre-processed options
set -- "${ARGV[@]}"
# Parse options
END_OF_OPT=
POSITIONAL=()
while [[ $# -gt 0 ]]; do
case "${END_OF_OPT}${1}" in
-h|--help) usage; exit 0 ;;
-p|--password) shift; PASSWORD="$1" ;;
-u|--username) shift; USERNAME="$1" ;;
-n|--name) shift; names+=("$1") ;;
-q|--quiet) QUIET=1 ;;
-C|--copy) COPY=1 ;;
-N|--notify) NOTIFY=1 ;;
--stdin) READ_STDIN=1 ;;
--) END_OF_OPT=1 ;;
-*) invalid "$1" ;;
*) POSITIONAL+=("$1") ;;
esac
shift
done
# Restore positional parameters
set -- "${POSITIONAL[@]}"
假设我们创建一个名为test_args.sh的shell脚本,如下所示
#!/bin/sh
until [ $# -eq 0 ]
do
name=${1:1}; shift;
if [[ -z "$1" || $1 == -* ]] ; then eval "export $name=true"; else eval "export $name=$1"; shift; fi
done
echo "year=$year month=$month day=$day flag=$flag"
运行以下命令后:
sh test_args.sh -year 2017 -flag -month 12 -day 22
输出将是:
year=2017 month=12 day=22 flag=true
我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:
while [[ $# -gt 0 ]]; do
case "$1" in
-v|--verbose) verbose=1; shift;;
-o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
file=$2; shift 2
else
echo "-o requires file-path" 1>&2; exit 1
fi ;;
--)
while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
break;;
*)
BACKUP="$BACKUP;$1"
shift
;;
esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
[ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
[ "$BACKUP" = "${BACKUP/;/}" ] && break
BACKUP="${BACKUP#*;}"
done