比如,我有一个脚本,用这行代码调用:

./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile

或者这个:

./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile 

什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?


当前回答

我想提供我的选项解析版本,它允许以下内容:

-s p1
--stage p1
-w somefolder
--workfolder somefolder
-sw p1 somefolder
-e=hello

也允许这样做(可能不需要):

-s--workfolder p1 somefolder
-se=hello p1
-swe=hello p1 somefolder

您必须在使用前决定是否在选项上使用=。这是为了保持代码干净。

while [[ $# > 0 ]]
do
    key="$1"
    while [[ ${key+x} ]]
    do
        case $key in
            -s*|--stage)
                STAGE="$2"
                shift # option has parameter
                ;;
            -w*|--workfolder)
                workfolder="$2"
                shift # option has parameter
                ;;
            -e=*)
                EXAMPLE="${key#*=}"
                break # option has been fully handled
                ;;
            *)
                # unknown option
                echo Unknown option: $key #1>&2
                exit 10 # either this: my preferred way to handle unknown options
                break # or this: do this to signal the option has been handled (if exit isn't used)
                ;;
        esac
        # prepare for next option in this key, if any
        [[ "$key" = -? || "$key" == --* ]] && unset key || key="${key/#-?/-}"
    done
    shift # option(s) fully processed, proceed to next input argument
done

其他回答

我想提供我的选项解析版本,它允许以下内容:

-s p1
--stage p1
-w somefolder
--workfolder somefolder
-sw p1 somefolder
-e=hello

也允许这样做(可能不需要):

-s--workfolder p1 somefolder
-se=hello p1
-swe=hello p1 somefolder

您必须在使用前决定是否在选项上使用=。这是为了保持代码干净。

while [[ $# > 0 ]]
do
    key="$1"
    while [[ ${key+x} ]]
    do
        case $key in
            -s*|--stage)
                STAGE="$2"
                shift # option has parameter
                ;;
            -w*|--workfolder)
                workfolder="$2"
                shift # option has parameter
                ;;
            -e=*)
                EXAMPLE="${key#*=}"
                break # option has been fully handled
                ;;
            *)
                # unknown option
                echo Unknown option: $key #1>&2
                exit 10 # either this: my preferred way to handle unknown options
                break # or this: do this to signal the option has been handled (if exit isn't used)
                ;;
        esac
        # prepare for next option in this key, if any
        [[ "$key" = -? || "$key" == --* ]] && unset key || key="${key/#-?/-}"
    done
    shift # option(s) fully processed, proceed to next input argument
done

这是我使用变量数组对Bruno Bronosky答案的改进解决方案。

它允许您混合参数位置,并为您提供一个参数数组,该数组在没有选项的情况下保持顺序

#!/bin/bash

echo $@

PARAMS=()
SOFT=0
SKIP=()
for i in "$@"
do
case $i in
    -n=*|--skip=*)
    SKIP+=("${i#*=}")
    ;;
    -s|--soft)
    SOFT=1
    ;;
    *)
        # unknown option
        PARAMS+=("$i")
    ;;
esac
done
echo "SKIP            = ${SKIP[@]}"
echo "SOFT            = $SOFT"
    echo "Parameters:"
    echo ${PARAMS[@]}

将输出例如:

$ ./test.sh parameter -s somefile --skip=.c --skip=.obj
parameter -s somefile --skip=.c --skip=.obj
SKIP            = .c .obj
SOFT            = 1
Parameters:
parameter somefile

在@brunobronosky的回答基础上,我添加了一个“预处理器”来处理一些常见的格式:

将--longopt=val展开为--longopt-val将-xyz展开为-x-y-z支持--表示标志的结束显示意外选项的错误小巧易读的选项开关

#!/bin/bash

# Report usage
usage() {
  echo "Usage:"
  echo "$(basename "$0") [options] [--] [file1, ...]"
}

invalid() {
  echo "ERROR: Unrecognized argument: $1" >&2
  usage
  exit 1
}

# Pre-process options to:
# - expand -xyz into -x -y -z
# - expand --longopt=arg into --longopt arg
ARGV=()
END_OF_OPT=
while [[ $# -gt 0 ]]; do
  arg="$1"; shift
  case "${END_OF_OPT}${arg}" in
    --) ARGV+=("$arg"); END_OF_OPT=1 ;;
    --*=*)ARGV+=("${arg%%=*}" "${arg#*=}") ;;
    --*) ARGV+=("$arg") ;;
    -*) for i in $(seq 2 ${#arg}); do ARGV+=("-${arg:i-1:1}"); done ;;
    *) ARGV+=("$arg") ;;
  esac
done

# Apply pre-processed options
set -- "${ARGV[@]}"

# Parse options
END_OF_OPT=
POSITIONAL=()
while [[ $# -gt 0 ]]; do
  case "${END_OF_OPT}${1}" in
    -h|--help)      usage; exit 0 ;;
    -p|--password)  shift; PASSWORD="$1" ;;
    -u|--username)  shift; USERNAME="$1" ;;
    -n|--name)      shift; names+=("$1") ;;
    -q|--quiet)     QUIET=1 ;;
    -C|--copy)      COPY=1 ;;
    -N|--notify)    NOTIFY=1 ;;
    --stdin)        READ_STDIN=1 ;;
    --)             END_OF_OPT=1 ;;
    -*)             invalid "$1" ;;
    *)              POSITIONAL+=("$1") ;;
  esac
  shift
done

# Restore positional parameters
set -- "${POSITIONAL[@]}"

假设我们创建一个名为test_args.sh的shell脚本,如下所示

#!/bin/sh
until [ $# -eq 0 ]
do
  name=${1:1}; shift;
  if [[ -z "$1" || $1 == -* ]] ; then eval "export $name=true"; else eval "export $name=$1"; shift; fi  
done
echo "year=$year month=$month day=$day flag=$flag"

运行以下命令后:

sh test_args.sh  -year 2017 -flag  -month 12 -day 22 

输出将是:

year=2017 month=12 day=22 flag=true

我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:

while [[ $# -gt 0 ]]; do
    case "$1" in
    -v|--verbose) verbose=1; shift;;
    -o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
            file=$2; shift 2
        else
            echo "-o requires file-path" 1>&2; exit 1
        fi ;;
    --)
        while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
        break;;
    *)
        BACKUP="$BACKUP;$1"
        shift
        ;;
    esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
    [ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
    [ "$BACKUP" = "${BACKUP/;/}" ] && break
    BACKUP="${BACKUP#*;}"
done