比如,我有一个脚本,用这行代码调用:

./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile

或者这个:

./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile 

什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?


当前回答

我已经编写了一个bash助手来编写一个不错的bash工具

项目主页:https://gitlab.mbedsys.org/mbedsys/bashopts

例子:

#!/bin/bash -ei

# load the library
. bashopts.sh

# Enable backtrace dusplay on error
trap 'bashopts_exit_handle' ERR

# Initialize the library
bashopts_setup -n "$0" -d "This is myapp tool description displayed on help message" -s "$HOME/.config/myapprc"

# Declare the options
bashopts_declare -n first_name -l first -o f -d "First name" -t string -i -s -r
bashopts_declare -n last_name -l last -o l -d "Last name" -t string -i -s -r
bashopts_declare -n display_name -l display-name -t string -d "Display name" -e "\$first_name \$last_name"
bashopts_declare -n age -l number -d "Age" -t number
bashopts_declare -n email_list -t string -m add -l email -d "Email adress"

# Parse arguments
bashopts_parse_args "$@"

# Process argument
bashopts_process_args

将提供帮助:

NAME:
    ./example.sh - This is myapp tool description displayed on help message

USAGE:
    [options and commands] [-- [extra args]]

OPTIONS:
    -h,--help                          Display this help
    -n,--non-interactive true          Non interactive mode - [$bashopts_non_interactive] (type:boolean, default:false)
    -f,--first "John"                  First name - [$first_name] (type:string, default:"")
    -l,--last "Smith"                  Last name - [$last_name] (type:string, default:"")
    --display-name "John Smith"        Display name - [$display_name] (type:string, default:"$first_name $last_name")
    --number 0                         Age - [$age] (type:number, default:0)
    --email                            Email adress - [$email_list] (type:string, default:"")

享受:)

其他回答

这也可能很有用:您可以设置一个值,如果有人提供输入,则使用该值覆盖默认值。

myscript.sh-f/serverlist.txt或只是/myscript.sh(它采用默认值)

    #!/bin/bash
    # --- set the value, if there is inputs, override the defaults.

    HOME_FOLDER="${HOME}/owned_id_checker"
    SERVER_FILE_LIST="${HOME_FOLDER}/server_list.txt"

    while [[ $# > 1 ]]
    do
    key="$1"
    shift
    
    case $key in
        -i|--inputlist)
        SERVER_FILE_LIST="$1"
        shift
        ;;
    esac
    done

    
    echo "SERVER LIST   = ${SERVER_FILE_LIST}"

这是我使用变量数组对Bruno Bronosky答案的改进解决方案。

它允许您混合参数位置,并为您提供一个参数数组,该数组在没有选项的情况下保持顺序

#!/bin/bash

echo $@

PARAMS=()
SOFT=0
SKIP=()
for i in "$@"
do
case $i in
    -n=*|--skip=*)
    SKIP+=("${i#*=}")
    ;;
    -s|--soft)
    SOFT=1
    ;;
    *)
        # unknown option
        PARAMS+=("$i")
    ;;
esac
done
echo "SKIP            = ${SKIP[@]}"
echo "SOFT            = $SOFT"
    echo "Parameters:"
    echo ${PARAMS[@]}

将输出例如:

$ ./test.sh parameter -s somefile --skip=.c --skip=.obj
parameter -s somefile --skip=.c --skip=.obj
SKIP            = .c .obj
SOFT            = 1
Parameters:
parameter somefile

我想提交我的项目:https://github.com/flyingangel/argparser

source argparser.sh
parse_args "$@"

就这么简单。环境将填充与参数同名的变量

根据这里的其他答案,这是我的版本:

#!/bin/bash
set -e

function parse() {
    for arg in "$@"; do # transform long options to short ones
        shift
        case "$arg" in
            "--name") set -- "$@" "-n" ;;
            "--verbose") set -- "$@" "-v" ;;
            *) set -- "$@" "$arg"
        esac
    done

    while getopts "n:v" optname  # left to ":" are flags that expect a value, right to the ":" are flags that expect nothing
    do
        case "$optname" in
            "n") name=${OPTARG} ;;
            "v") verbose=true ;;
        esac
    done
    shift "$((OPTIND-1))" # shift out all the already processed options
}


parse "$@"
echo "hello $name"
if [ ! -z $verbose ]; then echo 'nice to meet you!'; fi

用法:

$ ./parse.sh
hello
$ ./parse.sh -n YOUR_NAME
hello YOUR_NAME
$ ./parse.sh -n YOUR_NAME -v
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v -n YOUR_NAME
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v
hello 
nice to meet you!

我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:

while [[ $# -gt 0 ]]; do
    case "$1" in
    -v|--verbose) verbose=1; shift;;
    -o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
            file=$2; shift 2
        else
            echo "-o requires file-path" 1>&2; exit 1
        fi ;;
    --)
        while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
        break;;
    *)
        BACKUP="$BACKUP;$1"
        shift
        ;;
    esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
    [ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
    [ "$BACKUP" = "${BACKUP/;/}" ] && break
    BACKUP="${BACKUP#*;}"
done