比如,我有一个脚本,用这行代码调用:

./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile

或者这个:

./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile 

什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?


当前回答

我已经编写了一个bash助手来编写一个不错的bash工具

项目主页:https://gitlab.mbedsys.org/mbedsys/bashopts

例子:

#!/bin/bash -ei

# load the library
. bashopts.sh

# Enable backtrace dusplay on error
trap 'bashopts_exit_handle' ERR

# Initialize the library
bashopts_setup -n "$0" -d "This is myapp tool description displayed on help message" -s "$HOME/.config/myapprc"

# Declare the options
bashopts_declare -n first_name -l first -o f -d "First name" -t string -i -s -r
bashopts_declare -n last_name -l last -o l -d "Last name" -t string -i -s -r
bashopts_declare -n display_name -l display-name -t string -d "Display name" -e "\$first_name \$last_name"
bashopts_declare -n age -l number -d "Age" -t number
bashopts_declare -n email_list -t string -m add -l email -d "Email adress"

# Parse arguments
bashopts_parse_args "$@"

# Process argument
bashopts_process_args

将提供帮助:

NAME:
    ./example.sh - This is myapp tool description displayed on help message

USAGE:
    [options and commands] [-- [extra args]]

OPTIONS:
    -h,--help                          Display this help
    -n,--non-interactive true          Non interactive mode - [$bashopts_non_interactive] (type:boolean, default:false)
    -f,--first "John"                  First name - [$first_name] (type:string, default:"")
    -l,--last "Smith"                  Last name - [$last_name] (type:string, default:"")
    --display-name "John Smith"        Display name - [$display_name] (type:string, default:"$first_name $last_name")
    --number 0                         Age - [$age] (type:number, default:0)
    --email                            Email adress - [$email_list] (type:string, default:"")

享受:)

其他回答

这也可能很有用:您可以设置一个值,如果有人提供输入,则使用该值覆盖默认值。

myscript.sh-f/serverlist.txt或只是/myscript.sh(它采用默认值)

    #!/bin/bash
    # --- set the value, if there is inputs, override the defaults.

    HOME_FOLDER="${HOME}/owned_id_checker"
    SERVER_FILE_LIST="${HOME_FOLDER}/server_list.txt"

    while [[ $# > 1 ]]
    do
    key="$1"
    shift
    
    case $key in
        -i|--inputlist)
        SERVER_FILE_LIST="$1"
        shift
        ;;
    esac
    done

    
    echo "SERVER LIST   = ${SERVER_FILE_LIST}"

来自digitalpeer.com,稍作修改:

用法myscript.sh-p=my_prefix-s=dirname-l=libname

#!/bin/bash
for i in "$@"
do
case $i in
    -p=*|--prefix=*)
    PREFIX="${i#*=}"

    ;;
    -s=*|--searchpath=*)
    SEARCHPATH="${i#*=}"
    ;;
    -l=*|--lib=*)
    DIR="${i#*=}"
    ;;
    --default)
    DEFAULT=YES
    ;;
    *)
            # unknown option
    ;;
esac
done
echo PREFIX = ${PREFIX}
echo SEARCH PATH = ${SEARCHPATH}
echo DIRS = ${DIR}
echo DEFAULT = ${DEFAULT}

要更好地理解${i#*=},请在本指南中搜索“Substring Removal”。它在功能上等同于调用一个不需要的子流程的‘sed’s/[^=]*=//'<<<“$i”`或调用两个不需要子流程的“echo”$i”|sed’s/[^=]*=//'`。

我使用optget和optgets的组合来解析带或不带参数的短选项和长选项,甚至是非选项(不带-或-的选项):

# catch wrong options and move non-options to the end of the string
args=$(getopt -l "$opt_long" "$opt_short" "$@" 2> >(sed -e 's/^/stderr/g')) || echo -n "Error: " && echo "$args" | grep -oP "(?<=^stderr).*" && exit 1
mapfile -t args < <(xargs -n1 <<< "$(echo "$args" | sed -E "s/(--[^ ]+) /\1=/g")" )
set -- "${args[@]}"

# parse short and long options
while getopts "$opt_short-:" opt; do
  ...
done

# remove all parsed options from $@
shift $((OPTIND-1)

这样,我就可以使用$opt_verbose这样的变量访问所有选项,而非选项可以通过默认变量$1、$2等访问:

echo "help:$opt_help"
echo "file:$opt_file"
echo "verbose:$opt_verbose"
echo "long_only:$opt_long_only"
echo "short_only:$opt_s"
echo "path:$1"
echo "mail:$2"

其中一个主要特点是,我能够以完全随机的顺序传递所有选项和非选项:

#             $opt_file     $1        $2          $opt_... $opt_... $opt_...
# /demo.sh --file=file.txt /dir info@example.com -V -h --long_only=yes -s
help:1
file:file.txt
verbose:1
long_only:yes
short_only:1
path:/dir
mail:info@example.com

更多详情:https://stackoverflow.com/a/74275254/318765

保留未处理参数的解决方案。包括演示。

这是我的解决方案。它非常灵活,不像其他软件包,不需要外部包,并且可以干净地处理遗留的参数。

用法为:/myscript-flag flag变量-otherflag flagvar2

您所要做的就是编辑有效标记行。它在前面加上连字符并搜索所有参数。然后它将下一个参数定义为标志名,例如。

./myscript -flag flagvariable -otherflag flagvar2
echo $flag $otherflag
flagvariable flagvar2

主要代码(简短的版本,详细的示例,以及错误输出的版本):

#!/usr/bin/env bash
#shebang.io
validflags="rate time number"
count=1
for arg in $@
do
    match=0
    argval=$1
    for flag in $validflags
    do
        sflag="-"$flag
        if [ "$argval" == "$sflag" ]
        then
            declare $flag=$2
            match=1
        fi
    done
        if [ "$match" == "1" ]
    then
        shift 2
    else
        leftovers=$(echo $leftovers $argval)
        shift
    fi
    count=$(($count+1))
done
#Cleanup then restore the leftovers
shift $#
set -- $leftovers

带有内置echo演示的详细版本:

#!/usr/bin/env bash
#shebang.io
rate=30
time=30
number=30
echo "all args
$@"
validflags="rate time number"
count=1
for arg in $@
do
    match=0
    argval=$1
#   argval=$(echo $@ | cut -d ' ' -f$count)
    for flag in $validflags
    do
            sflag="-"$flag
        if [ "$argval" == "$sflag" ]
        then
            declare $flag=$2
            match=1
        fi
    done
        if [ "$match" == "1" ]
    then
        shift 2
    else
        leftovers=$(echo $leftovers $argval)
        shift
    fi
    count=$(($count+1))
done

#Cleanup then restore the leftovers
echo "pre final clear args:
$@"
shift $#
echo "post final clear args:
$@"
set -- $leftovers
echo "all post set args:
$@"
echo arg1: $1 arg2: $2

echo leftovers: $leftovers
echo rate $rate time $time number $number

最后一个,如果传递了一个无效的参数,这一个会出错。

#!/usr/bin/env bash
#shebang.io
rate=30
time=30
number=30
validflags="rate time number"
count=1
for arg in $@
do
    argval=$1
    match=0
        if [ "${argval:0:1}" == "-" ]
    then
        for flag in $validflags
        do
                sflag="-"$flag
            if [ "$argval" == "$sflag" ]
            then
                declare $flag=$2
                match=1
            fi
        done
        if [ "$match" == "0" ]
        then
            echo "Bad argument: $argval"
            exit 1
        fi
        shift 2
    else
        leftovers=$(echo $leftovers $argval)
        shift
    fi
    count=$(($count+1))
done
#Cleanup then restore the leftovers
shift $#
set -- $leftovers
echo rate $rate time $time number $number
echo leftovers: $leftovers

优点:不管怎么说,它处理得很好。它保留了许多其他解决方案所没有的未使用的参数。它还允许调用变量,而无需在脚本中手动定义。如果没有给出相应的参数,它还允许预填充变量。(请参阅详细示例)。

缺点:无法解析单个复杂的arg字符串,例如-xcvf将作为单个参数处理。不过,您可以很容易地在我的代码中编写额外的代码,以添加此功能。

根据这里的其他答案,这是我的版本:

#!/bin/bash
set -e

function parse() {
    for arg in "$@"; do # transform long options to short ones
        shift
        case "$arg" in
            "--name") set -- "$@" "-n" ;;
            "--verbose") set -- "$@" "-v" ;;
            *) set -- "$@" "$arg"
        esac
    done

    while getopts "n:v" optname  # left to ":" are flags that expect a value, right to the ":" are flags that expect nothing
    do
        case "$optname" in
            "n") name=${OPTARG} ;;
            "v") verbose=true ;;
        esac
    done
    shift "$((OPTIND-1))" # shift out all the already processed options
}


parse "$@"
echo "hello $name"
if [ ! -z $verbose ]; then echo 'nice to meet you!'; fi

用法:

$ ./parse.sh
hello
$ ./parse.sh -n YOUR_NAME
hello YOUR_NAME
$ ./parse.sh -n YOUR_NAME -v
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v -n YOUR_NAME
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v
hello 
nice to meet you!