比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
当前回答
我已经编写了一个bash助手来编写一个不错的bash工具
项目主页:https://gitlab.mbedsys.org/mbedsys/bashopts
例子:
#!/bin/bash -ei
# load the library
. bashopts.sh
# Enable backtrace dusplay on error
trap 'bashopts_exit_handle' ERR
# Initialize the library
bashopts_setup -n "$0" -d "This is myapp tool description displayed on help message" -s "$HOME/.config/myapprc"
# Declare the options
bashopts_declare -n first_name -l first -o f -d "First name" -t string -i -s -r
bashopts_declare -n last_name -l last -o l -d "Last name" -t string -i -s -r
bashopts_declare -n display_name -l display-name -t string -d "Display name" -e "\$first_name \$last_name"
bashopts_declare -n age -l number -d "Age" -t number
bashopts_declare -n email_list -t string -m add -l email -d "Email adress"
# Parse arguments
bashopts_parse_args "$@"
# Process argument
bashopts_process_args
将提供帮助:
NAME:
./example.sh - This is myapp tool description displayed on help message
USAGE:
[options and commands] [-- [extra args]]
OPTIONS:
-h,--help Display this help
-n,--non-interactive true Non interactive mode - [$bashopts_non_interactive] (type:boolean, default:false)
-f,--first "John" First name - [$first_name] (type:string, default:"")
-l,--last "Smith" Last name - [$last_name] (type:string, default:"")
--display-name "John Smith" Display name - [$display_name] (type:string, default:"$first_name $last_name")
--number 0 Age - [$age] (type:number, default:0)
--email Email adress - [$email_list] (type:string, default:"")
享受:)
其他回答
这也可能很有用:您可以设置一个值,如果有人提供输入,则使用该值覆盖默认值。
myscript.sh-f/serverlist.txt或只是/myscript.sh(它采用默认值)
#!/bin/bash
# --- set the value, if there is inputs, override the defaults.
HOME_FOLDER="${HOME}/owned_id_checker"
SERVER_FILE_LIST="${HOME_FOLDER}/server_list.txt"
while [[ $# > 1 ]]
do
key="$1"
shift
case $key in
-i|--inputlist)
SERVER_FILE_LIST="$1"
shift
;;
esac
done
echo "SERVER LIST = ${SERVER_FILE_LIST}"
这是我使用变量数组对Bruno Bronosky答案的改进解决方案。
它允许您混合参数位置,并为您提供一个参数数组,该数组在没有选项的情况下保持顺序
#!/bin/bash
echo $@
PARAMS=()
SOFT=0
SKIP=()
for i in "$@"
do
case $i in
-n=*|--skip=*)
SKIP+=("${i#*=}")
;;
-s|--soft)
SOFT=1
;;
*)
# unknown option
PARAMS+=("$i")
;;
esac
done
echo "SKIP = ${SKIP[@]}"
echo "SOFT = $SOFT"
echo "Parameters:"
echo ${PARAMS[@]}
将输出例如:
$ ./test.sh parameter -s somefile --skip=.c --skip=.obj
parameter -s somefile --skip=.c --skip=.obj
SKIP = .c .obj
SOFT = 1
Parameters:
parameter somefile
我想提交我的项目:https://github.com/flyingangel/argparser
source argparser.sh
parse_args "$@"
就这么简单。环境将填充与参数同名的变量
根据这里的其他答案,这是我的版本:
#!/bin/bash
set -e
function parse() {
for arg in "$@"; do # transform long options to short ones
shift
case "$arg" in
"--name") set -- "$@" "-n" ;;
"--verbose") set -- "$@" "-v" ;;
*) set -- "$@" "$arg"
esac
done
while getopts "n:v" optname # left to ":" are flags that expect a value, right to the ":" are flags that expect nothing
do
case "$optname" in
"n") name=${OPTARG} ;;
"v") verbose=true ;;
esac
done
shift "$((OPTIND-1))" # shift out all the already processed options
}
parse "$@"
echo "hello $name"
if [ ! -z $verbose ]; then echo 'nice to meet you!'; fi
用法:
$ ./parse.sh
hello
$ ./parse.sh -n YOUR_NAME
hello YOUR_NAME
$ ./parse.sh -n YOUR_NAME -v
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v -n YOUR_NAME
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v
hello
nice to meet you!
我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:
while [[ $# -gt 0 ]]; do
case "$1" in
-v|--verbose) verbose=1; shift;;
-o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
file=$2; shift 2
else
echo "-o requires file-path" 1>&2; exit 1
fi ;;
--)
while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
break;;
*)
BACKUP="$BACKUP;$1"
shift
;;
esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
[ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
[ "$BACKUP" = "${BACKUP/;/}" ] && break
BACKUP="${BACKUP#*;}"
done