在@brunobronosky的回答基础上，我添加了一个“预处理器”来处理一些常见的格式：

将--longopt=val展开为--longopt-val将-xyz展开为-x-y-z支持--表示标志的结束显示意外选项的错误小巧易读的选项开关

#!/bin/bash

# Report usage
usage() {
  echo "Usage:"
  echo "$(basename "$0") [options] [--] [file1, ...]"
}

invalid() {
  echo "ERROR: Unrecognized argument: $1" >&2
  usage
  exit 1
}

# Pre-process options to:
# - expand -xyz into -x -y -z
# - expand --longopt=arg into --longopt arg
ARGV=()
END_OF_OPT=
while [[ $# -gt 0 ]]; do
  arg="$1"; shift
  case "${END_OF_OPT}${arg}" in
    --) ARGV+=("$arg"); END_OF_OPT=1 ;;
    --*=*)ARGV+=("${arg%%=*}" "${arg#*=}") ;;
    --*) ARGV+=("$arg") ;;
    -*) for i in $(seq 2 ${#arg}); do ARGV+=("-${arg:i-1:1}"); done ;;
    *) ARGV+=("$arg") ;;
  esac
done

# Apply pre-processed options
set -- "${ARGV[@]}"

# Parse options
END_OF_OPT=
POSITIONAL=()
while [[ $# -gt 0 ]]; do
  case "${END_OF_OPT}${1}" in
    -h|--help)      usage; exit 0 ;;
    -p|--password)  shift; PASSWORD="$1" ;;
    -u|--username)  shift; USERNAME="$1" ;;
    -n|--name)      shift; names+=("$1") ;;
    -q|--quiet)     QUIET=1 ;;
    -C|--copy)      COPY=1 ;;
    -N|--notify)    NOTIFY=1 ;;
    --stdin)        READ_STDIN=1 ;;
    --)             END_OF_OPT=1 ;;
    -*)             invalid "$1" ;;
    *)              POSITIONAL+=("$1") ;;
  esac
  shift
done

# Restore positional parameters
set -- "${POSITIONAL[@]}"

我认为这个很简单：

#!/bin/bash
#

readopt='getopts $opts opt;rc=$?;[ "$rc$opt" = "0?" ]&&exit 1;[ $rc = 0 ]||{ shift $[OPTIND-1];false; }'

opts=vfdo:

# Enumerating options
while eval "$readopt"
do
    echo OPT:$opt ${OPTARG+OPTARG:$OPTARG}
done

# Enumerating arguments
for arg
do
    echo ARG:$arg
done

调用示例：

./myscript -v -do /fizz/someOtherFile -f ./foo/bar/someFile
OPT:v 
OPT:d 
OPT:o OPTARG:/fizz/someOtherFile
OPT:f 
ARG:./foo/bar/someFile

假设我们创建一个名为test_args.sh的shell脚本，如下所示

#!/bin/sh
until [ $# -eq 0 ]
do
  name=${1:1}; shift;
  if [[ -z "$1" || $1 == -* ]] ; then eval "export $name=true"; else eval "export $name=$1"; shift; fi  
done
echo "year=$year month=$month day=$day flag=$flag"

运行以下命令后：

sh test_args.sh  -year 2017 -flag  -month 12 -day 22 

输出将是：

year=2017 month=12 day=22 flag=true

根据这里的其他答案，这是我的版本：

#!/bin/bash
set -e

function parse() {
    for arg in "$@"; do # transform long options to short ones
        shift
        case "$arg" in
            "--name") set -- "$@" "-n" ;;
            "--verbose") set -- "$@" "-v" ;;
            *) set -- "$@" "$arg"
        esac
    done

    while getopts "n:v" optname  # left to ":" are flags that expect a value, right to the ":" are flags that expect nothing
    do
        case "$optname" in
            "n") name=${OPTARG} ;;
            "v") verbose=true ;;
        esac
    done
    shift "$((OPTIND-1))" # shift out all the already processed options
}


parse "$@"
echo "hello $name"
if [ ! -z $verbose ]; then echo 'nice to meet you!'; fi

用法：

$ ./parse.sh
hello
$ ./parse.sh -n YOUR_NAME
hello YOUR_NAME
$ ./parse.sh -n YOUR_NAME -v
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v -n YOUR_NAME
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v
hello 
nice to meet you!

我最终实现了公认答案的dash（或/bin/sh）版本，基本上不使用数组：

while [[ $# -gt 0 ]]; do
    case "$1" in
    -v|--verbose) verbose=1; shift;;
    -o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
            file=$2; shift 2
        else
            echo "-o requires file-path" 1>&2; exit 1
        fi ;;
    --)
        while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
        break;;
    *)
        BACKUP="$BACKUP;$1"
        shift
        ;;
    esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
    [ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
    [ "$BACKUP" = "${BACKUP/;/}" ] && break
    BACKUP="${BACKUP#*;}"
done

while [ "$#" -gt 0 ]; do
  case "$1" in
    -n) name="$2"; shift 2;;
    -p) pidfile="$2"; shift 2;;
    -l) logfile="$2"; shift 2;;

    --name=*) name="${1#*=}"; shift 1;;
    --pidfile=*) pidfile="${1#*=}"; shift 1;;
    --logfile=*) logfile="${1#*=}"; shift 1;;
    --name|--pidfile|--logfile) echo "$1 requires an argument" >&2; exit 1;;
    
    -*) echo "unknown option: $1" >&2; exit 1;;
    *) handle_argument "$1"; shift 1;;
  esac
done

此解决方案：

句柄-n arg和--name=arg允许在末尾使用参数如果有任何拼写错误，则显示正常错误兼容，不使用抨击可读，不需要在循环中维护状态