比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
当前回答
这里有一个getopts,它用最少的代码实现解析,并允许您在一种情况下使用eval和substring定义要提取的内容。
基本上eval“local key='val'”
function myrsync() {
local backup=("${@}") args=(); while [[ $# -gt 0 ]]; do k="$1";
case "$k" in
---sourceuser|---sourceurl|---targetuser|---targeturl|---file|---exclude|---include)
eval "local ${k:3}='${2}'"; shift; shift # Past two arguments
;;
*) # Unknown option
args+=("$1"); shift; # Past argument only
;;
esac
done; set -- "${backup[@]}" # Restore $@
echo "${sourceurl}"
}
在这里,将变量声明为局部变量,而不是全局变量。
调用为:
myrsync ---sourceurl http://abc.def.g ---sourceuser myuser ...
${k:3}基本上是一个从键中删除第一个---的子字符串。
其他回答
我使用optget和optgets的组合来解析带或不带参数的短选项和长选项,甚至是非选项(不带-或-的选项):
# catch wrong options and move non-options to the end of the string
args=$(getopt -l "$opt_long" "$opt_short" "$@" 2> >(sed -e 's/^/stderr/g')) || echo -n "Error: " && echo "$args" | grep -oP "(?<=^stderr).*" && exit 1
mapfile -t args < <(xargs -n1 <<< "$(echo "$args" | sed -E "s/(--[^ ]+) /\1=/g")" )
set -- "${args[@]}"
# parse short and long options
while getopts "$opt_short-:" opt; do
...
done
# remove all parsed options from $@
shift $((OPTIND-1)
这样,我就可以使用$opt_verbose这样的变量访问所有选项,而非选项可以通过默认变量$1、$2等访问:
echo "help:$opt_help"
echo "file:$opt_file"
echo "verbose:$opt_verbose"
echo "long_only:$opt_long_only"
echo "short_only:$opt_s"
echo "path:$1"
echo "mail:$2"
其中一个主要特点是,我能够以完全随机的顺序传递所有选项和非选项:
# $opt_file $1 $2 $opt_... $opt_... $opt_...
# /demo.sh --file=file.txt /dir info@example.com -V -h --long_only=yes -s
help:1
file:file.txt
verbose:1
long_only:yes
short_only:1
path:/dir
mail:info@example.com
更多详情:https://stackoverflow.com/a/74275254/318765
我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:
while [[ $# -gt 0 ]]; do
case "$1" in
-v|--verbose) verbose=1; shift;;
-o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
file=$2; shift 2
else
echo "-o requires file-path" 1>&2; exit 1
fi ;;
--)
while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
break;;
*)
BACKUP="$BACKUP;$1"
shift
;;
esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
[ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
[ "$BACKUP" = "${BACKUP/;/}" ] && break
BACKUP="${BACKUP#*;}"
done
当我尝试这个问题时,上面的答案似乎有点bug——这是我发现更强大的解决方案:
boolean_arg=""
arg_with_value=""
while [[ $# -gt 0 ]]
do
key="$1"
case $key in
-b|--boolean-arg)
boolean_arg=true
shift
;;
-a|--arg-with-value)
arg_with_value="$2"
shift
shift
;;
-*)
echo "Unknown option: $1"
exit 1
;;
*)
arg_num=$(( $arg_num + 1 ))
case $arg_num in
1)
first_normal_arg="$1"
shift
;;
2)
second_normal_arg="$1"
shift
;;
*)
bad_args=TRUE
esac
;;
esac
done
# Handy to have this here when adding arguments to
# see if they're working. Just edit the '0' to be '1'.
if [[ 0 == 1 ]]; then
echo "first_normal_arg: $first_normal_arg"
echo "second_normal_arg: $second_normal_arg"
echo "boolean_arg: $boolean_arg"
echo "arg_with_value: $arg_with_value"
exit 0
fi
if [[ $bad_args == TRUE || $arg_num < 2 ]]; then
echo "Usage: $(basename "$0") <first-normal-arg> <second-normal-arg> [--boolean-arg] [--arg-with-value VALUE]"
exit 1
fi
# As long as there is at least one more argument, keep looping
while [[ $# -gt 0 ]]; do
key="$1"
case "$key" in
# This is a flag type option. Will catch either -f or --foo
-f|--foo)
FOO=1
;;
# Also a flag type option. Will catch either -b or --bar
-b|--bar)
BAR=1
;;
# This is an arg value type option. Will catch -o value or --output-file value
-o|--output-file)
shift # past the key and to the value
OUTPUTFILE="$1"
;;
# This is an arg=value type option. Will catch -o=value or --output-file=value
-o=*|--output-file=*)
# No need to shift here since the value is part of the same string
OUTPUTFILE="${key#*=}"
;;
*)
# Do whatever you want with extra options
echo "Unknown option '$key'"
;;
esac
# Shift after checking all the cases to get the next option
shift
done
这使您既可以使用空格分隔的选项/值,也可以使用相等的定义值。
因此,您可以使用以下命令运行脚本:
./myscript --foo -b -o /fizz/file.txt
以及:
./myscript -f --bar -o=/fizz/file.txt
并且两者应该具有相同的最终结果。
赞成的意见:
允许-arg=value和-arg-value适用于bash中可以使用的任何arg名称意思是-a或-arg或--arg或-ar-g或其他纯粹的狂欢。无需学习/使用getopt或getopts
欺骗:
无法组合参数意思是没有-abc。您必须执行-a-b-c
这也可能很有用:您可以设置一个值,如果有人提供输入,则使用该值覆盖默认值。
myscript.sh-f/serverlist.txt或只是/myscript.sh(它采用默认值)
#!/bin/bash
# --- set the value, if there is inputs, override the defaults.
HOME_FOLDER="${HOME}/owned_id_checker"
SERVER_FILE_LIST="${HOME_FOLDER}/server_list.txt"
while [[ $# > 1 ]]
do
key="$1"
shift
case $key in
-i|--inputlist)
SERVER_FILE_LIST="$1"
shift
;;
esac
done
echo "SERVER LIST = ${SERVER_FILE_LIST}"