一些改进版本，最大lvl下到目录和选项排除文件夹:

using System;
using System.IO;

class MainClass {
  public static void Main (string[] args) {

    var dir = @"C:\directory\to\print";
    PrintDirectoryTree(dir, 2, new string[] {"folder3"});
  }


  public static void PrintDirectoryTree(string directory, int lvl, string[] excludedFolders = null, string lvlSeperator = "")
  {
    excludedFolders = excludedFolders ?? new string[0];

    foreach (string f in Directory.GetFiles(directory))
    {
        Console.WriteLine(lvlSeperator+Path.GetFileName(f));
    } 

    foreach (string d in Directory.GetDirectories(directory))
    {
        Console.WriteLine(lvlSeperator + "-" + Path.GetFileName(d));

        if(lvl > 0 && Array.IndexOf(excludedFolders, Path.GetFileName(d)) < 0)
        {
          PrintDirectoryTree(d, lvl-1, excludedFolders, lvlSeperator+"  ");
        }
    }
  }
}

输入目录:

-folder1
  file1.txt
  -folder2
    file2.txt
    -folder5
      file6.txt
  -folder3
    file3.txt
  -folder4
    file4.txt
    file5.txt

函数的输出(由于lvl限制，folder5的内容被排除，folder3的内容被排除，因为它在excldedfolders数组中):

-folder1
  file1.txt
  -folder2
    file2.txt
    -folder5
  -folder3
  -folder4
    file4.txt
    file5.txt

一个非常简单的解决方案，返回一个文件列表。

    public static List<string> AllFilesInFolder(string folder)
    {
        var result = new List<string>();

        foreach (string f in Directory.GetFiles(folder))
        {
            result.Add(f);
        }

        foreach (string d in Directory.GetDirectories(folder))
        {
            result.AddRange(AllFilesInFolder(d));
        }

        return result;
    }

这一个帮助我得到一个目录和子目录中的所有文件，可能对某人有帮助。[灵感来自上述答案]

static void Main(string[] args)
    {
        try
        {
            var root = @"G:\logs";
            DirectorySearch(root);
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.Message);
        }
        Console.ReadKey();
    }





public static void DirectorySearch(string root, bool isRootItrated = false)
{
    if (!isRootItrated)
    {
        var rootDirectoryFiles = Directory.GetFiles(root);
        foreach (var file in rootDirectoryFiles)
        {
            Console.WriteLine(file);
        } 
    }

    var subDirectories = Directory.GetDirectories(root);
    if (subDirectories?.Any() == true)
    {
        foreach (var directory in subDirectories)
        {
            var files = Directory.GetFiles(directory);
            foreach (var file in files)
            {
                Console.WriteLine(file);
            }
            DirectorySearch(directory, true);
        }
    }
}

如果您只需要文件名，并且由于我不喜欢这里的大多数解决方案(特性或可读性方面)，那么这个懒惰的解决方案如何?

private void Foo()
{
  var files = GetAllFiles("pathToADirectory");
  foreach (string file in files)
  {
      // Use can use Path.GetFileName() or similar to extract just the filename if needed
      // You can break early and it won't still browse your whole disk since it's a lazy one
  }
}

/// <exception cref="T:System.IO.DirectoryNotFoundException">The specified path is invalid (for example, it is on an unmapped drive).</exception>
/// <exception cref="T:System.UnauthorizedAccessException">The caller does not have the required permission.</exception>
/// <exception cref="T:System.IO.IOException"><paramref name="path" /> is a file name.-or-A network error has occurred.</exception>
/// <exception cref="T:System.IO.PathTooLongException">The specified path, file name, or both exceed the system-defined maximum length. For example, on Windows-based platforms, paths must be less than 248 characters and file names must be less than 260 characters.</exception>
/// <exception cref="T:System.ArgumentNullException"><paramref name="path" /> is null.</exception>
/// <exception cref="T:System.ArgumentException"><paramref name="path" /> is a zero-length string, contains only white space, or contains one or more invalid characters as defined by <see cref="F:System.IO.Path.InvalidPathChars" />.</exception>
[NotNull]
public static IEnumerable<string> GetAllFiles([NotNull] string directory)
{
  foreach (string file in Directory.GetFiles(directory))
  {
    yield return file; // includes the path
  }

  foreach (string subDir in Directory.GetDirectories(directory))
  {
    foreach (string subFile in GetAllFiles(subDir))
    {
      yield return subFile;
    }
  }
}

这篇文章涵盖了您需要的所有内容。除了与搜索文件和比较名称不同，只需打印出名称。

可以这样修改:

static void DirSearch(string sDir)
{
    try
    {
        foreach (string d in Directory.GetDirectories(sDir))
        {
            foreach (string f in Directory.GetFiles(d))
            {
                Console.WriteLine(f);
            }
            DirSearch(d);
        }
    }
    catch (System.Exception excpt)
    {
        Console.WriteLine(excpt.Message);
    }
}

barlop添加

GONeale提到上面没有列出当前目录中的文件，并建议将文件列表部分放在获取目录的部分之外。下面的代码可以做到这一点。它还包括一个Writeline行，你可以取消注释，这有助于跟踪你在递归中的位置，这可能有助于显示调用，帮助显示递归是如何工作的。

            DirSearch_ex3("c:\\aaa");
            static void DirSearch_ex3(string sDir)
            {
                //Console.WriteLine("DirSearch..(" + sDir + ")");
                try
                {
                    Console.WriteLine(sDir);

                    foreach (string f in Directory.GetFiles(sDir))
                    {
                        Console.WriteLine(f);
                    }

                    foreach (string d in Directory.GetDirectories(sDir))
                    {
                        DirSearch_ex3(d);
                    }
                }
                catch (System.Exception excpt)
                {
                    Console.WriteLine(excpt.Message);
                }
            }

注意。net 4.0中内置了基于迭代器的(而不是基于数组的)文件函数:

foreach (string file in Directory.EnumerateFiles(path, "*.*", SearchOption.AllDirectories))
{
    Console.WriteLine(file);
}

现在我会使用如下的方法;如果你不能访问单个子目录，那么内置的递归方法很容易崩溃…;Queue<string>的使用避免了太多的调用堆栈递归，迭代器块避免了我们拥有一个巨大的数组。

static void Main() {
    foreach (string file in GetFiles(SOME_PATH)) {
        Console.WriteLine(file);
    }
}

static IEnumerable<string> GetFiles(string path) {
    Queue<string> queue = new Queue<string>();
    queue.Enqueue(path);
    while (queue.Count > 0) {
        path = queue.Dequeue();
        try {
            foreach (string subDir in Directory.GetDirectories(path)) {
                queue.Enqueue(subDir);
            }
        }
        catch(Exception ex) {
            Console.Error.WriteLine(ex);
        }
        string[] files = null;
        try {
            files = Directory.GetFiles(path);
        }
        catch (Exception ex) {
            Console.Error.WriteLine(ex);
        }
        if (files != null) {
            for(int i = 0 ; i < files.Length ; i++) {
                yield return files[i];
            }
        }
    }
}