如何递归列出所有文件在一个目录和子目录在c# ?


当前回答

一些改进版本,最大lvl下到目录和选项排除文件夹:

using System;
using System.IO;

class MainClass {
  public static void Main (string[] args) {

    var dir = @"C:\directory\to\print";
    PrintDirectoryTree(dir, 2, new string[] {"folder3"});
  }


  public static void PrintDirectoryTree(string directory, int lvl, string[] excludedFolders = null, string lvlSeperator = "")
  {
    excludedFolders = excludedFolders ?? new string[0];

    foreach (string f in Directory.GetFiles(directory))
    {
        Console.WriteLine(lvlSeperator+Path.GetFileName(f));
    } 

    foreach (string d in Directory.GetDirectories(directory))
    {
        Console.WriteLine(lvlSeperator + "-" + Path.GetFileName(d));

        if(lvl > 0 && Array.IndexOf(excludedFolders, Path.GetFileName(d)) < 0)
        {
          PrintDirectoryTree(d, lvl-1, excludedFolders, lvlSeperator+"  ");
        }
    }
  }
}

输入目录:

-folder1
  file1.txt
  -folder2
    file2.txt
    -folder5
      file6.txt
  -folder3
    file3.txt
  -folder4
    file4.txt
    file5.txt

函数的输出(由于lvl限制,folder5的内容被排除,folder3的内容被排除,因为它在excldedfolders数组中):

-folder1
  file1.txt
  -folder2
    file2.txt
    -folder5
  -folder3
  -folder4
    file4.txt
    file5.txt

其他回答

这就是我们如何将文件作为其子目录的FileInfo,

var dir = new DirectoryInfo(rootPath);
FileInfo[] files = dir.GetFiles("*.*", SearchOption.AllDirectories);
var d = new DirectoryInfo(@"C:\logs");
var list = d.GetFiles("*.txt").Select(m => m.Name).ToList();

我更喜欢使用DirectoryInfo,因为我可以得到FileInfo的,而不仅仅是字符串。

        string baseFolder = @"C:\temp";
        DirectoryInfo di = new DirectoryInfo(baseFolder);

        string searchPattern = "*.xml";

        ICollection<FileInfo> matchingFileInfos = di.GetFiles(searchPattern, SearchOption.AllDirectories)
            .Select(x => x)
            .ToList();

我这样做的情况下,在未来我需要未来过滤..基于FileInfo的属性。

        string baseFolder = @"C:\temp";
        DirectoryInfo di = new DirectoryInfo(baseFolder);

        string searchPattern = "*.xml";

        ICollection<FileInfo> matchingFileInfos = di.GetFiles(searchPattern, SearchOption.AllDirectories)
            .Where(x => x.LastWriteTimeUtc < DateTimeOffset.Now)
            .Select(x => x)
            .ToList();

如果需要,我也可以求助于字符串。(仍然是未来证明过滤器/where-clause子句的东西。

        string baseFolder = @"C:\temp";
        DirectoryInfo di = new DirectoryInfo(baseFolder);

        string searchPattern = "*.xml";

        ICollection<string> matchingFileNames = di.GetFiles(searchPattern, SearchOption.AllDirectories)
            .Select(x => x.FullName)
            .ToList();

请注意,如果您想通过扩展文件,“.”是一个有效的搜索模式。

下面是B. Clay Shannon的非静态excel文件代码:

class ExcelSearcher
{
    private List<string> _fileNames;

    public ExcelSearcher(List<string> filenames)
    {
        _fileNames = filenames;
    }
    public List<string> GetExcelFiles(string dir, List<string> filenames = null)
    {

        string dirName = dir;
        var dirNames = new List<string>();
        if (filenames != null)
        {
            _fileNames.Concat(filenames);
        }
        try
        {
            foreach (string f in Directory.GetFiles(dirName))
            {
                if (f.ToLower().EndsWith(".xls") || f.ToLower().EndsWith(".xlsx"))
                {
                    _fileNames.Add(f);
                }
            }
            dirNames = Directory.GetDirectories(dirName).ToList();
            foreach (string d in dirNames)
            {
                GetExcelFiles(d, _fileNames);
            }
        }
        catch (Exception ex)
        {
            //Bam
        }
        return _fileNames;
    }

在Framework 2.0中,你可以使用(它列出根文件夹的文件,这是最好的最流行的答案):

static void DirSearch(string dir)
{
    try
    {
        foreach (string f in Directory.GetFiles(dir))
            Console.WriteLine(f);
        foreach (string d in Directory.GetDirectories(dir))
        {
            Console.WriteLine(d);
            DirSearch(d);
        }

    }
    catch (System.Exception ex)
    {
        Console.WriteLine(ex.Message);
    }
}