如何递归列出所有文件在一个目录和子目录在c# ?
当前回答
一个简单干净的解决方案
/// <summary>
/// Scans a folder and all of its subfolders recursively, and updates the List of files
/// </summary>
/// <param name="sFullPath">Full path of the folder</param>
/// <param name="files">The list, where the output is expected</param>
internal static void EnumerateFiles(string sFullPath, List<FileInfo> fileInfoList)
{
try
{
DirectoryInfo di = new DirectoryInfo(sFullPath);
FileInfo[] files = di.GetFiles();
foreach (FileInfo file in files)
fileInfoList.Add(file);
//Scan recursively
DirectoryInfo[] dirs = di.GetDirectories();
if (dirs == null || dirs.Length < 1)
return;
foreach (DirectoryInfo dir in dirs)
EnumerateFiles(dir.FullName, fileInfoList);
}
catch (Exception ex)
{
Logger.Write("Exception in Helper.EnumerateFiles", ex);
}
}
其他回答
以下是我的观点,基于Hernaldo’s,如果你需要找到具有特定模式名称的文件,例如XML文件,它们的名称中包含特定的字符串:
// call this like so: GetXMLFiles("Platypus", "C:\\");
public static List<string> GetXMLFiles(string fileType, string dir)
{
string dirName = dir;
var fileNames = new List<String>();
try
{
foreach (string f in Directory.GetFiles(dirName))
{
if ((f.Contains(fileType)) && (f.Contains(".XML")))
{
fileNames.Add(f);
}
}
foreach (string d in Directory.GetDirectories(dirName))
{
GetXMLFiles(fileType, d);
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
return fileNames;
}
至少在。net 4.5中,有这样一个版本,它要短得多,并且有额外的好处,可以评估包含在列表中的任何文件标准:
public static IEnumerable<string> GetAllFiles(string path,
Func<FileInfo, bool> checkFile = null)
{
string mask = Path.GetFileName(path);
if (string.IsNullOrEmpty(mask)) mask = "*.*";
path = Path.GetDirectoryName(path);
string[] files = Directory.GetFiles(path, mask, SearchOption.AllDirectories);
foreach (string file in files)
{
if (checkFile == null || checkFile(new FileInfo(file)))
yield return file;
}
}
像这样使用:
var list = GetAllFiles(mask, (info) => Path.GetExtension(info.Name) == ".html").ToList();
为了避免unauthoredaccessexception,我使用:
var files = GetFiles(@"C:\", "*.*", SearchOption.AllDirectories);
foreach (var file in files)
{
Console.WriteLine($"{file}");
}
public static IEnumerable<string> GetFiles(string path, string searchPattern, SearchOption searchOption)
{
var foldersToProcess = new List<string>()
{
path
};
while (foldersToProcess.Count > 0)
{
string folder = foldersToProcess[0];
foldersToProcess.RemoveAt(0);
if (searchOption.HasFlag(SearchOption.AllDirectories))
{
//get subfolders
try
{
var subfolders = Directory.GetDirectories(folder);
foldersToProcess.AddRange(subfolders);
}
catch (Exception ex)
{
//log if you're interested
}
}
//get files
var files = new List<string>();
try
{
files = Directory.GetFiles(folder, searchPattern, SearchOption.TopDirectoryOnly).ToList();
}
catch (Exception ex)
{
//log if you're interested
}
foreach (var file in files)
{
yield return file;
}
}
}
static void Main(string[] args)
{
string[] array1 = Directory.GetFiles(@"D:\");
string[] array2 = System.IO.Directory.GetDirectories(@"D:\");
Console.WriteLine("--- Files: ---");
foreach (string name in array1)
{
Console.WriteLine(name);
}
foreach (string name in array2)
{
Console.WriteLine(name);
}
Console.ReadLine();
}
注意。net 4.0中内置了基于迭代器的(而不是基于数组的)文件函数:
foreach (string file in Directory.EnumerateFiles(path, "*.*", SearchOption.AllDirectories))
{
Console.WriteLine(file);
}
现在我会使用如下的方法;如果你不能访问单个子目录,那么内置的递归方法很容易崩溃…;Queue<string>的使用避免了太多的调用堆栈递归,迭代器块避免了我们拥有一个巨大的数组。
static void Main() {
foreach (string file in GetFiles(SOME_PATH)) {
Console.WriteLine(file);
}
}
static IEnumerable<string> GetFiles(string path) {
Queue<string> queue = new Queue<string>();
queue.Enqueue(path);
while (queue.Count > 0) {
path = queue.Dequeue();
try {
foreach (string subDir in Directory.GetDirectories(path)) {
queue.Enqueue(subDir);
}
}
catch(Exception ex) {
Console.Error.WriteLine(ex);
}
string[] files = null;
try {
files = Directory.GetFiles(path);
}
catch (Exception ex) {
Console.Error.WriteLine(ex);
}
if (files != null) {
for(int i = 0 ; i < files.Length ; i++) {
yield return files[i];
}
}
}
}
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