对于在iOS和Android上略有不同的UI,即在不同的平台上,必须有一种方法来检测应用程序在哪个平台上运行,但我在文档中找不到它。是什么?


当前回答

感谢科林,最终答案是:

bool isIOS = Theme.of(context).platform == TargetPlatform.iOS;

其他回答

最“扑”的答案如下:

import 'package:flutter/foundation.dart' show TargetPlatform;

//...

if(Theme.of(context).platform == TargetPlatform.android)
    //do sth for Android
else if(Theme.of(context).platform == TargetPlatform.iOS)
    //do sth else for iOS
else if(Theme.of(context).platform == TargetPlatform.fuchsia)
    //even do sth else for Fuchsia OS

为更简单的方式为网络和应用程序。试试这个

import 'dart:io' show Platform;
import 'package:flutter/foundation.dart' show kIsWeb;


var platformName = '';
if (kIsWeb) {
  platformName = "Web";
} else {
  if (Platform.isAndroid) {
    platformName = "Android";
  } else if (Platform.isIOS) {
    platformName = "IOS";
  } else if (Platform.isFuchsia) {
    platformName = "Fuchsia";
  } else if (Platform.isLinux) {
    platformName = "Linux";
  } else if (Platform.isMacOS) {
    platformName = "MacOS";
  } else if (Platform.isWindows) {
    platformName = "Windows";
  }
}
print("platformName :- "+platformName.toString());

如果您只是需要一个字符串来记录日志,您可以使用Platform。operatingSystem,返回操作系统名称为小写字符串。

import 'dart:io';
import 'package:flutter/foundation.dart';

String _getPlatform() {
  if (kIsWeb) return 'web';
  return Platform.operatingSystem;
}
**multiple platform you check and run your code according specific platform **

bool isIOS = Theme.of(context).platform == TargetPlatform.iOS;
bool isAndroid = Theme.of(context).platform == TargetPlatform.android;
bool islinux = Theme.of(context).platform == TargetPlatform.linux;
bool isfuchsia = Theme.of(context).platform == TargetPlatform.fuchsia;
bool isMacOS = Theme.of(context).platform == TargetPlatform.macOS;
bool iswindows = Theme.of(context).platform == TargetPlatform.windows;

导入io库很简单

import'dart:io' show Platform;
void main(){
if(Platform.isIOS){
  return someThing();
}else if(Platform.isAndroid){
  return otherThing();
}else if(Platform.isMacOS){
  return anotherThing();
}

或者用非常简单的方式

Platform.isIOS ? someThing() : anOther(),